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Let \(S=\\{1,2,3,4,5,6\\}, E=\\{2,4,6\\}\) \(\boldsymbol{F}=\\{1,3,5\\}\), and \(\boldsymbol{G}=\\{5,6\\}\). Find the event \((E \cap F \cap G)^{c}\).

Short Answer

Expert verified
The complement of the intersection of events \(E\), \(F\), and \(G\) with respect to the sample space \(S\) is \((E \cap F \cap G)^{c} = \{1, 2, 3, 4, 5, 6\}\).

Step by step solution

01

Analyze the given information

The sample space \(S\) consists of the numbers from 1 to 6. The events are as follows: - \(E = \{2, 4, 6\}\) - \(F = \{1, 3, 5\}\) - \(G = \{5, 6\}\)
02

Find the intersection of the events

To find the intersection of the events \(E\), \(F\), and \(G\), we look for elements that are common to all the three events. \(E \cap F \cap G = \emptyset\) There are no common elements in the three events, so the intersection is the empty set.
03

Calculate the complement

Now, we need to find the complement of the intersection with respect to the sample space \(S\). The complement of an event is the set of all elements in the sample space that are not in the event. Since the intersection is the empty set, the complement will be the entire sample space: \((E \cap F \cap G)^{c} = S\) So, \((E \cap F \cap G)^{c} = \{1, 2, 3, 4, 5, 6\}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Intersection of Sets
In set theory, the intersection of sets refers to a collection of elements that are shared between two or more sets. It's like finding the common friends in different friend circles. For example, if you have sets \(A = \{1, 2, 3\}\) and \(B = \{2, 3, 4\}\), their intersection \(A \cap B\) is \(\{2, 3\}\).
This is because both 2 and 3 are present in both sets. In mathematical symbols, the intersection is denoted by the "\(\cap\)" operator.
When we talk about the intersection of sets \(E = \{2, 4, 6\}, F = \{1, 3, 5\}, \text{and } G = \{5, 6\}\), we look for elements common to all three sets.
In this case, there are no elements that appear in all sets, so the intersection is an empty set, represented by "\(\emptyset\)"."
Complement of a Set
The complement of a set is a fundamental concept in set theory. It helps in understanding the part of the universal set (or sample space) that is not occupied by a particular set. Think of it as understanding what is excluded from a group rather than what is included.
If you have a universal set \(U = \{1, 2, 3, 4\}\) and a set \(A = \{2, 3\}\), the complement of \(A\), denoted \(A^{c}\), is \(U \setminus A\).
In this example, that would be \(\{1, 4\}\). It includes all elements of the universal set that are not elements of \(A\).
For the exercise, given that \((E \cap F \cap G)\) results in an empty set, its complement \((E \cap F \cap G)^{c}\) is the entire sample space \(S = \{1, 2, 3, 4, 5, 6\}\).
Sample Space
The sample space in probability and set theory represents the set of all possible outcomes or scenarios. It's the universal set for a particular discussion or problem.
If you're rolling a die, for example, the sample space \(S\) could be \(\{1, 2, 3, 4, 5, 6\}\), listing all possible outcomes of the roll.
In our exercise, the sample space \(S = \{1, 2, 3, 4, 5, 6\}\) represents all the numbers we are dealing with in this situation. Understanding what the sample space includes is crucial for operations like finding complements and intersections.
It gives you a complete view of what elements you have at your disposal when performing set operations.
Mathematical Logic
Mathematical logic is a powerful tool for solving problems involving sets and their operations. It provides the framework for understanding how sets interact through operations like intersections and complements.
Logic uses principles like "and", "or", and "not" to form expressions and statements in mathematics. With sets, these operations translate to intersection, union, and complement respectively.
The intersection is like the logical "and"—it finds elements in all referenced sets. The complement represents "not", meaning elements not in the specified set.
By applying mathematical logic, we determined that since \(E \cap F \cap G = \emptyset\), the statement can be expressed interactively as there's no overlap ("and") between the sets.
Consequently, the complement ("not") encompasses the entire sample space, showcasing how logic assists in solving set operations.

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Most popular questions from this chapter

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