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FINANCING A CAR Darla purchased a new car during a special sales promotion by the manufacturer. She secured a loan from the manufacturer in the amount of \(\$ 16,000\) at a rate of \(7.9 \% /\) year compounded monthly. Her bank is now charging \(11.5 \%\) year compounded monthly for new car loans. Assuming that each loan would be amortized by 36 equal monthly installments, determine the amount of interest she would have paid at the end of \(3 \mathrm{yr}\) for each loan. How much less will she have paid in interest payments over the life of the loan by borrowing from the manufacturer instead of her bank?

Short Answer

Expert verified
Darla would have paid \$1,931.96 in interest for the manufacturer's loan and \$3,050.84 in interest for the bank loan. By choosing the manufacturer's loan, she saved \$1,118.88 in interest payments over the life of the loan.

Step by step solution

01

Calculate the monthly interest rates for both loans

First, find out the monthly interest rates for both loans. To do this, divide the annual interest rate by 12 (since it's compounded monthly). For the manufacturer's loan: \(i_{manufacturer} = \frac{7.9}{12} \% = 0.00758 \approx 0.658 \% \) For the bank loan: \(i_{bank} = \frac{11.5}{12} \% = 0.958 \% \)
02

Calculate the monthly payments for each loan

In order to calculate the monthly payments for each loan, first let's introduce the following variables: - P: Loan amount (\(\$16,000\)) - r: Monthly interest rate - n: Number of payments (36 installments) The formula to calculate the monthly payment (M) is given by: \[M = P\frac{r(1+r)^n}{(1+r)^n - 1}\] For the manufacturer's loan: \[M_{manufacturer} = 16000\frac{0.00658(1+0.00658)^{36}}{(1+0.00658)^{36} - 1} \approx \$ 498.11\] For the bank loan: \[M_{bank} = 16000\frac{0.00958(1+0.00958)^{36}}{(1+0.00958)^{36} - 1} \approx \$ 529.19\]
03

Calculate the total paid over the life of each loan

Now let's calculate the total amount paid over the life of each loan by multiplying the monthly payment by the number of installments (36). For the manufacturer's loan: \[Total_{manufacturer} = M_{manufacturer} * 36 \approx \$ 498.11 * 36 \approx \$ 17,931.96\] For the bank loan: \[Total_{bank} = M_{bank} * 36 \approx \$ 529.19 * 36 \approx \$ 19,050.84\]
04

Calculate the interest paid over the life of each loan

Now we will calculate the interest paid for each loan by subtracting the original loan amount from the total amount paid. For the manufacturer's loan: \[Interest_{manufacturer} = Total_{manufacturer} - P \approx \$ 17,931.96 - \$ 16,000 \approx \$ 1,931.96\] For the bank loan: \[Interest_{bank} = Total_{bank} - P \approx \$ 19,050.84 - \$ 16,000 \approx \$ 3,050.84\]
05

Calculate the difference in interest payments between the two loans

Finally, find out the difference in interest payments between the two loans. Difference = Interest paid for the bank loan - Interest paid for the manufacturer's loan \[Difference \approx \$ 3,050.84 - \$ 1,931.96 \approx \$ 1,118.88\] So, Darla will have paid \$1,118.88 less in interest payments over the life of the loan by borrowing from the manufacturer instead of her bank.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Compound Interest
When we talk about loans, compound interest plays a major role. Unlike simple interest, which only calculates interest on the initial amount or principal, compound interest calculates interest on the initial principal and also on the accumulated interest from previous periods. This is why debt can grow quickly if not paid regularly.

In Darla's case, both the manufacturer and the bank use compound interest calculated monthly. This means each month the interest is calculated on the principal amount plus any interest already added. While this benefits investments, it can significantly increase the total cost of a loan over time. Understanding how compound interest works helps in making more informed financial decisions.
Monthly Interest Rate
The monthly interest rate is a crucial factor in determining monthly loan payments and can be obtained by dividing the annual interest rate by 12. This simplifies annual rates into more manageable monthly increments.

For Darla's manufacturer loan with an annual rate of 7.9%, we get a monthly interest rate of about 0.658%. On the other hand, the bank's loan at 11.5% annually results in a monthly rate of 0.958%. These percentages might seem small, but over months, they can add significantly to the total cost of the loan. By comparing monthly rates, borrowers can better assess the true cost and choose the more affordable option.
Monthly Payment Calculation
Calculating monthly payments involves a formula that takes into account the loan amount, monthly interest rate, and the number of payment periods. The formula used is:\[M = P\frac{r(1+r)^n}{(1+r)^n - 1}\]Where:
  • \(P\) is the loan amount.
  • \(r\) is the monthly interest rate.
  • \(n\) is the number of payments.
For Darla's situation:
  • The Manufacturer loan requires monthly payments of approximately \(\\(498.11\).
  • The Bank loan demands about \(\\)529.19\) monthly.
This difference arises due to the higher interest rate charged by the bank. Knowing this calculation is helpful for budgeting and loan comparison.
Total Interest Paid
Total interest is what a borrower pays in addition to the loan amount over the life of the loan. To find it, subtract the loan's principal from the total amount repaid. In Darla's context:
  • The Manufacturer's loan incurs total interest of about \(\\(1,931.96\).
  • The Bank's loan leads to a steeper \(\\)3,050.84\) in interest.
Thus, Darla saves approximately \(\$1,118.88\) by choosing the manufacturer's option. This showcases why comparing interest rates and total costs is vital before committing to a loan. Understanding total interest clarifies the long-term financial implications and helps in smarter decision-making.

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Most popular questions from this chapter

The managers of a pension fund have invested \(\$ 1.5\) million in U.S. government certificates of deposit that pay interest at the rate of \(5.5 \% /\) year compounded semiannually over a period of 10 yr. At the end of this period, how much will the investment be worth?

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Suppose payments will be made for \(9 \frac{1}{4}\) yr at the end of each month into an ordinary annuity earning interest at the rate of \(6.25 \% /\) year compounded monthly. If the present value of the annuity is \(\$ 42,000\), what should be the size of each payment?

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