/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 A culture of a certain bacteria ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A culture of a certain bacteria is known to double in number every \(3 \mathrm{hr}\). If the culture has an initial count of 20 , what will be the population of the culture at the end of \(24 \mathrm{hr}\) ?

Short Answer

Expert verified
The population of the bacteria culture will be 5120 at the end of 24 hours, as it doubles 8 times, and \(20 \times 2^{8} = 5120\).

Step by step solution

01

1. Find the number of doublings

To find the number of times the population doubles in 24 hours, divide the total time by the time it takes for one doubling: \[\frac{24}{3} = 8\]So, the population doubles 8 times.
02

2. Calculate the final population

To find the final population, multiply the initial count (20) by 2 raised to the power of the number of doublings (8): \[20 \times 2^{8} = 20 \times 256 = 5120\] Thus, after 24 hours the population of the culture will be 5120.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Doubling
Understanding population doubling is crucial for analyzing biological growth, economics, and other fields where rapid increase is a known characteristic. Simply put, population doubling refers to the amount of time it takes for a given population to double in size. This concept is often encountered in the study of microorganisms, such as bacteria, where the reproduction rate is high.

In our exercise, the bacteria culture doubles every 3 hours, which is a relatively short doubling time indicating a fast rate of growth. This concept can be generalized to any situation where there is a consistent and predictable rate of increase. It is not limited to just bacteria but can also apply to the spread of viruses, human population growth in certain conditions, or even the compounding interest in finance.

To improve understanding for students, exercises involving population doubling could include real-life scenarios, provide interactive models or simulations, and offer practice problems that cover different doubling times.
Exponential Functions
Exponential functions are mathematical expressions that showcase how quantities grow or decay at a rate proportional to their current value. These functions are often represented as \( f(x) = a \times b^{x} \) where \( a \) is the initial amount, \( b \) is the base of the exponential, indicating the growth factor, and \( x \) is the exponent that indicates the number of time intervals.

In our textbook problem, the exponential function that models the population growth of the bacteria culture is \( P(t) = 20 \times 2^{t/3} \), where \( P(t) \) is the population at time \( t \) hours, \( 20 \) is the initial population, \( 2 \) is the base representing the doubling effect every 3 hours, and \( t/3 \) is the number of doublings. Understanding how to manipulate this function and interpret its graph is essential for students grappling with the concept of exponential growth. To enhance comprehension, students may benefit from visual aids such as graphing the function, and exploring how changes in the variables affect growth rates.
Growth Models
Growth models are theoretical constructs used to describe how a population or quantity evolves over time. The exponential growth model is a common type of growth model that assumes the rate of growth is constant and the population increases by a fixed percentage at each time step. This model is characterized by its J-shaped curve when graphed, indicating an acceleration of growth as time progresses.

In the case of our example problem, the simple formula \( P(t) = P_0 \times 2^{t/D} \) where \( P_0 \) is the initial population, \( t \) is the time, and \( D \) is the doubling time, aptly reflects the exponential growth model. Students seeking to grasp this concept should be encouraged to explore different values of \( D \) and \( P_0 \) to see their effect on the model's predictions. Additionally, comparing exponential growth to other models, such as logistic growth, helps illustrate the limitations and appropriate applications of each model, providing a deeper understanding of population dynamics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

FINANCING A HoME After making a down payment of \(\$ 25,000\), the Meyers need to secure a loan of \(\$ 280.000\) to purchase a certain house. Their bank's current rate for 25 -yr home loans is \(11 \% /\) year compounded monthly. The owner has offered to finance the loan at \(9.8 \% /\) year compounded monthly. Assuming that both loans would be amortized over a 25 -yr period by 300 equal monthly installments, determine the difference in the amount of interest the Meyers would pay by choosing the seller's financing rather than their bank's.

Georgia purchased a house in January, 2000 for \(\$ 200,000\). In January 2006 she sold the house and made a net profit of \(\$ 56,000\). Find the effective annual rate of return on her investment over the 6 -yr period.

SINKING FuNDS A city has \(\$ 2.5\) million worth of school bonds that are due in \(20 \mathrm{yr}\) and has established a sinking fund to retire this debt. If the fund earns interest at the rate of \(7 \% /\) year compounded annually, what amount must be deposited annually in this fund?

Use logarithms to solve each problem. How long will it take an investment of \(\$ 6000\) to grow to \(\$ 7000\) if the investment earns interest at the rate of \(7 \frac{1}{2} \%\) compounded continuously?

Restaurant equipment purchased at a cost of \(\$ 150,000\) is to be depreciated by the double declining-balance method over \(10 \mathrm{yr}\). What is the book value of the equipment at the end of 6 yr? By what amount has the equipment been depreciated at the end of the sixth year?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.