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As part of her fitness program, Karen has taken up jogging. If she jogs \(1 \mathrm{mi}\) the first day and increases her daily run by \(\frac{1}{4}\) mi every week, when will she reach her goal of \(10 \mathrm{mi} /\) day?

Short Answer

Expert verified
Karen will reach her goal of running 10 miles per day on the 253rd day.

Step by step solution

01

Define the arithmetic sequence

We can represent Karen's running distances with an arithmetic sequence since the increase is constant. The arithmetic sequence is given by the formula: \[a_n = a_1 + (n - 1)d\] Where \(a_n\) is the distance of the \(n^{th}\) day, \(a_1\) is the first-day distance, \(n\) is the number of days, and \(d\) is the common difference (increase per day). In Karen's case, \(a_1 = 1\) mile and \(d=\frac{1}{4}\) mi/week. We will first convert the increase per week to the increase in miles per day.
02

Find the daily increase

To find the daily increase in miles, we will divide the increase per week by the number of days in a week: Daily increase = \(\frac{total\:increase\:per\:week}{days\:per\:week} = \frac{\frac{1}{4}\:miles}{7\:days}\)
03

Write down the sequence formula for Karen's case

Now that we have the daily increase, we can write down the arithmetic sequence formula for Karen's running distances: \[a_n = 1 + (n - 1)\frac{1/4}{7}\] We need to find the value of \(n\) when \(a_n = 10\) miles.
04

Solve for n when the distance reaches 10 miles

To find the day when Karen reaches her goal of running 10 miles, we will substitute \(a_n = 10\) miles in our arithmetic sequence and solve for n: \[10 = 1 + (n - 1)\frac{1/4}{7}\]
05

Simplify and solve for n

To simplify the equation for n, we will first multiply both sides of the equation by 7: \[70 = 7 + (n - 1)\frac{1/4}\] Now, we can multiply both sides of the equation by 4 to eliminate the fraction: \[280 = 28 + (n - 1)\] Now subtract 28 from both sides: \[252 = n - 1\] Finally, add 1 to both sides to find n: \[n = 253\] So Karen will reach her goal of running 10 miles per day on the 253rd day.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Arithmetic Progression
Arithmetic progression (AP) is a sequence of numbers in which each term after the first is obtained by adding a constant, known as the common difference, to the preceding term. This constant is denoted as 'd' in the AP formula. In our exercise, Karen's jogging distances form an arithmetic progression because she increases her distance by a fixed amount each week.

The general form of an arithmetic progression is: \[a_n = a_1 + (n - 1)d\]Here, \(a_n\) is the \(n^{th}\) term, \(a_1\) is the first term, 'n' is the term number, and 'd' is the common difference. In the context of Karen's jogging routine, her first-day distance (\(a_1\)) is 1 mile and the common difference (\(d\)) is the weekly increase converted to a daily increase.
Sequences in Mathematics
In mathematics, a sequence is an ordered list of numbers that follow a certain rule. We encounter various types of sequences, such as arithmetic sequences, geometric sequences, and more complex forms. Sequences can be finite or infinite and are fundamental in understanding patterns and solving problems systematically.

The significance of understanding sequences in mathematics extends beyond simple number patterns. For instance, in calculus, infinite sequences are used to define limits and series. In the problem about Karen's jogging, we focus on a simple finite arithmetic sequence, which provides us with a structured and predictable pattern. By comprehending sequences, one can approach numerous algebraic problems in a methodical manner and make accurate predictions.
Algebraic Problem Solving
Algebraic problem solving involves finding unknown variables by applying algebraic techniques and understanding. To effectively solve algebraic problems, one must often perform operations such as simplifying expressions, isolating variables, and factoring. In our scenario, solving for the number of days when Karen will jog 10 miles requires manipulating her arithmetic sequence's formula.

The process of algebraic problem solving in this case includes transforming the weekly increase to a daily value, substituting known values into the sequence's formula, and simplifying the equation step by step to isolate 'n'—the number of days. This structured approach, using algebraic methods, ultimately reveals that Karen will reach her 10-mile goal on the 253rd day. When tackling similar problems, remember that each step serves to bring you closer to isolating your desired variable and finding the solution.

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