/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Mitchell has been given the opti... [FREE SOLUTION] | 91Ó°ÊÓ

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Mitchell has been given the option of either paying his \(\$ 300\) bill now or settling it for \(\$ 306\) after 1 mo ( 30 days). If he chooses to pay after 1 mo, find the simple interest rate at which he would be charged.

Short Answer

Expert verified
The simple interest rate charged if Mitchell decides to pay the bill after 1 month is approximately \(24.333\%\).

Step by step solution

01

Identify the simple interest

The simple interest is the difference between the principal amount and the total amount due after 1 mo (30 days). Calculate the simple interest: Simple Interest = Amount due - Principal Simple Interest = \(306 - 300 = \$ 6\).
02

Convert time to years

The simple interest rate will be charged yearly, so we need to convert the time from 1 mo (30 days) to years: Time in years = (30 days) / (365 days in a year) = \( \frac{30}{365} = \frac{6}{73} \) years.
03

Use the simple interest formula to find the rate

Now, we will use the simple interest formula to calculate the rate: Simple Interest = Principal x Rate x Time Rate = (Simple Interest) / (Principal x Time) Substitute the values we found earlier: Rate = \(\frac{6}{300 \times \frac{6}{73}} \)
04

Simplify the expression and find the rate

Simplify the expression by multiplying the numerator and the denominator in the fraction: Rate = \(\frac{6 \times 73}{300 \times 6} \) Now, we can cancel out the number 6 from the numerator and the denominator: Rate = \(\frac{73}{300}\)
05

Convert the rate into a percentage

To convert the rate into a percentage, we will multiply it by 100: Interest Rate = \(\frac{73}{300} \times 100\% \) Interest Rate ≈ 24.333 \% (rounded to 3 decimal places) Therefore, Mitchell would be charged approximately \(24.333\%\) as the simple interest rate if he chooses to pay the bill after 1 month.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Interest Calculation
Calculating interest can be straightforward if you understand the formula and the variables involved. In simple interest, the core elements are the principal, rate, and time. The principal is the initial amount of money, in this case, $300. The interest is what you are charged for borrowing this principal amount over a given period.

The simple interest is found using this formula:

  • Simple Interest = Principal x Rate x Time

The formula allows us to compute the interest based on how much time the loan or bill is outstanding, ensuring the amount paid for borrowing the money is fair and proportionate to the duration the money is borrowed. In the example provided, Mitchell has a simple interest of $6 due to the difference between the amount to be paid ($306) and the principal ($300). Understanding this makes calculating the interest much more manageable.
Converting Time Units
When dealing with financial calculations, it's crucial to express all units of time consistently. Since most interest rates are annual, converting the time from months or days to years is necessary for accuracy.

In the exercise, Mitchell's billing period is 30 days. To convert this into years, use the relationship:

  • Time in years = Number of days/365

For this specific case, it means:
  • Time in years = 30 / 365

This conversion gives us \(\frac{6}{73}\) years, as 30 days arcs approximately this much part of a year. Proper conversion ensures that our interest calculation remains consistent across different time periods, aligning the length of the borrowing period with the yearly rate.
Percentage Conversion
Turning raw rates into a percentage form clarifies how much the rate translates monetarily. After finding the interest rate as a fraction or decimal, convert it to a percentage for better insight.

To convert a rate into a percentage:
  • Multiply the rate by 100
  • Append the percent sign (%) to indicate it's a percentage

Applying this to the exercise, the fraction \(\frac{73}{300}\) becomes \(\frac{73}{300} \times 100\%\), simplifying to approximately 24.333\%.

This conversion gives a more intuitive understanding of the interest rate, helping Mitchell (and us!) easily visualize the proportion that will be charged if the bill is paid late.
Financial Mathematics
Financial mathematics helps in understanding and managing various real-world financial challenges. Concepts like simple interest, time value of money, and rate calculations form the bedrock of making informed personal and business financial decisions.

By exploring the fundamentals of simple interest, this example illustrates a tangible scenario where understanding financial mathematics affects individuals directly. For instance, Mitchell learns how his decision to delay payment affects the cost involved.
  • The exercise shows how choosing to pay later increases the original amount.
  • It highlights the importance of understanding financial terms to manage personal resources efficiently.

Financial mathematics equips anyone with the ability to analyze costs, benefits, and potential pitfalls within monetary scenarios, helping make smarter financial decisions in everyday life.

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Most popular questions from this chapter

ADJUSTABLE-RATE MoRTGAGES George secured an adjustablerate mortgage (ARM) loan to help finance the purchase of his home 5 yr ago. The amount of the loan was \(\$ 300,000\) for a term of \(30 \mathrm{yr}\), with interest at the rate of \(8 \% /\) year compounded monthly. Currently, the interest rate for his ARM is \(6.5 \% /\) year compounded monthly, and George's monthly payments are due to be reset. What will be the new monthly payment?

IRAs Martin has deposited \(\$ 375\) in his IRA at the end of each quarter for the past 20 yr. His investment has earned interest at the rate of \(8 \% /\) year compounded quarterly over this period. Now, at age 60 , he is considering retirement. What quarterly payment will he receive over the next 15 yr? (Assume that the money is earning interest at the same rate and that payments are made at the end of each quarter.) If he continues working and makes quarterly payments of the same amount in his IRA until age 65, what quarterly payment will he receive from his fund upon retirement over the following \(10 \mathrm{yr}\) ?

Find the twentieth term and sum of the first 20 terms of the geometric progression \(-3,3,-3,3, \ldots\)

LoAN AMORTIZATION What monthly payment is required to amortize a loan of \(\$ 30,000\) over \(10 \mathrm{yr}\) if interest at the rate of \(12 \% /\) year is charged on the unpaid balance and interest calculations are made at the end of each month?

Find the periodic payment \(R\) required to amortize a loan of \(P\) dollars over \(t\) yr with interest charged at the rate of \(r \% /\) year compounded \(m\) times a year. \(P=25,000, r=3, t=12, m=4\)

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