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Determine whether each system of linear equations has (a) one and only one solution, (b) infinitely many solutions, or (c) no solution. Find all solutions whenever they exist. $$ \begin{array}{r} x-3 y=-1 \\ 4 x+3 y=11 \end{array} $$

Short Answer

Expert verified
The system of linear equations has a unique solution (one and only one solution), with \(x = 2\) and \(y = 1\).

Step by step solution

01

Form the matrix for the system of equations

Write the given system of linear equations as a matrix. \[ \begin{bmatrix} 1 & -3 & | & -1\\ 4 & 3 & | & 11 \end{bmatrix} \]
02

Determine the determinant

Calculate the determinant of the matrix formed by the coefficients of x and y. This determinant, denoted as D, is found by using the formula \(D = a*d - b*c\), where a, b, c, d are the coefficients of the matrix. \[ D = \begin{vmatrix} 1 & -3 \\ 4 & 3 \end{vmatrix} = (1*3) - (-3*4) = 3 + 12 = 15 \] Since \(D \ne 0\), we proceed to step 3.
03

Solve for x and y using substitution or row echelon form

As the determinant is non-zero, this system of linear equations has a unique solution. We will use the method of substitution to find the values of x and y. From the first equation: \(x - 3y = -1\), let's isolate x: \(x = 3y -1\). Now, substitute x in the second equation, \(4x + 3y = 11\): \[4(3y - 1) + 3y = 11\] Solve for y: \(12y - 4 + 3y = 11\), \(15y = 15\), \(y = 1\) Now that we have found the value for y, substitute it back into the equation for x to find the value for x: \(x = 3(1) - 1\), \(x = 2\)
04

Conclusion

The system of linear equations has a unique solution, with \(x = 2\) and \(y = 1\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Matrix Representation
Matrix representation is a technique used to simplify systems of linear equations. By organizing the coefficients of variables into a matrix, it becomes easier to apply mathematical methods for solving the system. For the given system of equations:
  • Equation 1: \(x - 3y = -1\)
  • Equation 2: \(4x + 3y = 11\)
We can represent this system in matrix form as:\[\begin{bmatrix}1 & -3 & | & -1\4 & 3 & | & 11\end{bmatrix}\]Here, the numbers before the variables \(x\) and \(y\) are placed into a matrix, with the constants on the right side forming an augmented column. Using a matrix allows us to apply systematic methods to find solutions.
Determinant Calculation
Calculating the determinant is a crucial step in analyzing a system of linear equations. The determinant provides insight into the nature of the solutions of the system, especially if the system has two variables as in a 2x2 matrix:
  • The formula for the determinant \(D\) of a matrix \(\begin{bmatrix} a & b \ c & d \end{bmatrix}\) is \(D = ad - bc\).
Let's calculate the determinant for our matrix:\[D = \begin{vmatrix} 1 & -3 \ 4 & 3 \end{vmatrix} = (1 \times 3) - (-3 \times 4) = 3 + 12 = 15\]Since the determinant \(D\) is not equal to zero, we know that the system of equations has a unique solution. A non-zero determinant confirms that the system has an exact and unambiguous solution.
Unique Solution
A unique solution means there is a distinct set of values for the variables that satisfy all the equations in the system. When the determinant of the coefficient matrix is not zero, it ensures that the lines represented by the equations intersect at exactly one point. This unique point of intersection is our solution.
In our example, the determinant \(D\) is 15, indicating a unique solution exists. This occurs when both equations intersect at the single point \((x, y) = (2, 1)\). Understanding that the uniqueness of a solution is linked to a non-zero determinant helps in solving systems methodically and accurately.
Always remember, a unique solution signifies the equations form lines or planes that are neither parallel nor coincident.
Substitution Method
The substitution method is a competent technique to find the solution of a system of linear equations after confirming the existence of a unique solution. Here’s how you use it:
  • First, solve one of the equations for one variable in terms of the other. From our equations, we get \(x = 3y - 1\) from \(x - 3y = -1\).
  • Next, substitute this expression for \(x\) into the other equation \(4x + 3y = 11\).
Now solve for \(y\):\[4(3y - 1) + 3y = 11\]Expand and simplify:\[12y - 4 + 3y = 11\]Combine like terms:\[15y = 15\]Divide by 15 to solve for \(y\):\[y = 1\]Substitute \(y\) back into the expression for \(x\):\[x = 3(1) - 1 = 2\]This methodical substitution grants us the solution, verifying our system means \((x, y) = (2, 1)\) is valid. The substitution method is especially helpful when systems have a clear and unique solution, as it reduces complexity and focuses directly on isolating variables.

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Most popular questions from this chapter

(a) write each system of equations as a matrix equation and (b) solve the system of equations by using the inverse of the coefficient matrix. $$ \begin{array}{l} \begin{aligned} x_{1}+x_{2}+2 x_{3}+x_{4} &=b_{1} \\ 4 x_{1}+5 x_{2}+9 x_{3}+x_{4} &=b_{2} \\ 3 x_{1}+4 x_{2}+7 x_{3}+x_{4} &=b_{3} \\ 2 x_{1}+3 x_{2}+4 x_{3}+2 x_{4} &=b_{4} \end{aligned}\\\ \text { where } \quad \text { (i) } b_{1}=3, b_{2}=6, b_{3}=5, b_{4}=7\\\ \text { and (ii) } b_{1}=1, b_{2}=-1, b_{3}=0, b_{4}=-4 \end{array} $$

Figures for life expectancy at birth of Massachusetts residents in 2002 are \(81.0,76.1\), and \(82.2\) yr for white, black, and Hispanic women, respectively, and \(76.0,69.9\), and \(75.9\) years for white, black, and Hispanic men, respectively. Express this information using a \(2 \times 3\) matrix and a \(3 \times 2\) matrix.

Solve the system of linear equations using the Gauss-Jordan elimination method. $$ \begin{aligned} x_{1}-2 x_{2}+x_{3} &=6 \\ 2 x_{1}+x_{2}-3 x_{3} &=-3 \\ x_{1}-3 x_{2}+3 x_{3} &=10 \end{aligned} $$

Bob, a nutritionist who works for the University Medical Center, has been asked to prepare special diets for two patients, Susan and Tom. Bob has decided that Susan's meals should contain at least \(400 \mathrm{mg}\) of calcium, \(20 \mathrm{mg}\) of iron, and \(50 \mathrm{mg}\) of vitamin \(\mathrm{C}\). whereas Tom's meals should contain at least \(350 \mathrm{mg}\) of calcium, \(15 \mathrm{mg}\) of iron, and \(40 \mathrm{mg}\) of vitamin \(\mathrm{C}\). Bob has also decided that the meals are to be prepared from three basic foods: food \(\mathrm{A}\), food \(\mathrm{B}\), and food \(\mathrm{C}\). The special nutritional contents of these foods are summarized in the accompanying table. Find how many ounces of each type of food should be used in a meal so that the minimum requirements of calcium, iron, and vitamin \(\mathrm{C}\) are met for each patient's meals. $$ \begin{array}{lccc} \hline && {\text { Contents (mg/oz) }} & \\ & \text { Calcium } & \text { Iron } & \text { Vitamin C } \\ \hline \text { Food A } & 30 & 1 & 2 \\ \hline \text { Food B } & 25 & 1 & 5 \\ \hline \text { Food C } & 20 & 2 & 4 \\ \hline \end{array} $$

Write the given system of linear equations in matrix form. $$ \begin{array}{l} 2 x-3 y=7 \\ 3 x-4 y=8 \end{array} $$

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