/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 Use the given information to fin... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the given information to find the indicated probability. \(P(A)=.1, P(B)=.6, P(A \cap B)=.05 .\) Find \(P(A \cup B)\)

Short Answer

Expert verified
The probability of either event A or event B occurring is \(0.65\).

Step by step solution

01

We are given the following information: - \(P(A) = 0.1\) - \(P(B) = 0.6\) - \(P(A \cap B) = 0.05\) #Step 2: Apply the formula for the probability of the union of two events#

We want to find the probability of either A or B occurring (\(A \cup B\)). We can use the formula: \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\) #Step 3: Substitute the given probabilities into the formula#
02

Now, we will substitute the given probabilities in the formula: \(P(A \cup B) = 0.1 + 0.6 - 0.05\) #Step 4: Calculate the final probability#

Finally, we will compute the probability: \(P(A \cup B) = 0.65\) So, the probability of either event A or event B occurring is \(0.65\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Union of Events
In probability theory, the union of events A and B, denoted as \( A \cup B \), represents the occurrence of at least one of the events. This means that either event A, event B, or both events happen. Understanding the union is crucial when calculating probabilities as it helps to consider all possible outcomes that satisfy at least one of the events.

For instance, if you are trying to calculate the probability of it raining or being windy, you would consider the union of the two events. The probability of the union of A and B is achieved by a specific formula that accounts for the overlap, ensuring that shared outcomes are not counted twice.

The formula for the probability of a union is particularly useful when dealing with more than one event, allowing for a comprehensive understanding of potential outcomes.
Intersection of Events
The intersection of events, denoted as \( A \cap B \), refers to the situation when both events A and B occur simultaneously. In simpler terms, it is the overlap between the two events where both happen at the same time. The importance of intersections in probability can be highlighted by understanding scenarios where two simultaneous outcomes are of interest.

Think of rolling a die; if you want the intersection of rolling an even number and a number greater than two, your intersection is numbers four and six. In this exercise, we were given a specific probability for the intersection of events, which is integral in calculating other probabilities, like the union.

Understanding intersections helps in not overestimating probabilities by clarifying when exactly two events occur together.
Probability Formula
The probability formula for the union of two events is:\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]. This formula is crucial because it allows you to calculate the probability of either event A or event B happening, while ensuring you're not double-counting scenarios where both occur.

By using the formula, you’re effectively adding the individual probabilities of each event and then subtracting the probability of their intersection, since it has been counted twice. This adjustment ensures that the calculation accurately reflects the real-world scenarios being measured.

For this exercise, applying the formula provides a clear method for arriving at the correct probability. Understanding how to use this formula is key in many areas of probability and statistics, helping solve problems that involve multiple events.
Event Occurrence
Event occurrence in probability refers to the situations where specific events happen. Knowing whether an event occurs helps determine relevant probabilities. In the exercise, you deal with events A and B and are given probabilities for them occurring individually, as well as their overlap.

When you calculate probabilities, you assess how often an event is likely to occur based on the known data. This knowledge aids in planning and predicting, making probability a powerful tool in decision-making, everyday life, and science.

The provided probabilities, like \( P(A) = 0.1 \) and \( P(B) = 0.6 \), give tangible insights into how often these events might occur and help quantitatively describe the likelihood of various outcomes. Understanding event occurrence is foundational to mastering probability.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Based on the following table, which shows the performance of a selection of 100 stocks after one year. (Take S to be the set of all stocks represented in the table.) $$ \begin{array}{|r|c|c|c|c|} \hline & \multicolumn{3}{|c|} {\text { Companies }} & \\ \cline { 2 - 4 } & \begin{array}{c} \text { Pharmaceutical } \\ \boldsymbol{P} \end{array} & \begin{array}{c} \text { Electronic } \\ \boldsymbol{E} \end{array} & \begin{array}{c} \text { Internet } \\ \boldsymbol{I} \end{array} & \text { Total } \\ \hline \begin{array}{r} \text { Increased } \\ \boldsymbol{V} \end{array} & 10 & 5 & 15 & 30 \\ \hline \begin{array}{r} \text { Unchanged }^{*} \\ \boldsymbol{N} \end{array} & 30 & 0 & 10 & 40 \\ \hline \begin{array}{r} \text { Decreased } \\ \boldsymbol{D} \end{array} & 10 & 5 & 15 & 30 \\ \hline \text { Total } & 50 & 10 & 40 & 100 \\ \hline \end{array} $$ If a stock stayed within \(20 \%\) of its original value, it is classified as "unchanged." \(\nabla\) Calculate \(\frac{n(V \cap I)}{n(I)}\). What does the answer represent?

An experiment is given together with an event. Find the (modeled) probability of each event, assuming that the coins and dice are distinguishable and fair, and that what is observed are the faces or numbers uppermost. Three coins are tossed; the result is at most one head.

Risk Analysis An auto insurance company classifies each motorist as "high- risk" if the motorist has had at least one moving violation during the past calendar year and "low risk" if the motorist has had no violations during the past calendar year. According to the company's data, a high-risk motorist has a \(50 \%\) chance of remaining in the high-risk category the next year and a \(50 \%\) chance of moving to the low-risk category. A low-risk motorist has a \(10 \%\) chance of moving to the high-risk category the next year and a \(90 \%\) chance of remaining in the low-risk category. In the long term, what percentage of motorists fall in each category?

Determine whether the information shown is consistent with a probability distribution. If not, say why. \(P(A)=.2 ; P(B)=.4 ; P(A \cap B)=.2\)

Polls According to the New York Times/CBS poll of March 2005, referred to in Exercise \(65,72 \%\) of those polled ranked neither Iraq nor North Korea as the top foreign policy issue. \({ }^{33}\) What is the probability that a randomly selected person polled ranked either Iraq or North Korea as the top foreign policy issue?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.