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Require the use of counting techniques from the last chapter. A bag contains three red marbles, two green ones, one fluorescent pink one, two yellow ones, and two orange ones. Suzan grabs four at random. Find the probabilities of the indicated events. She gets one of each color other than fluorescent pink, given that she gets at least one red one.

Short Answer

Expert verified
The probability that Suzan picks one of each color other than fluorescent pink, given that she gets at least one red marble, is \(\frac{24}{175}\).

Step by step solution

01

Calculate the total number of ways to pick 4 marbles with at least one red marble

First, let's find the total possible ways Suzan can pick 4 marbles from the bag. Since there are 10 marbles in the bag, the total possible ways to pick 4 marbles is given by the combination formula: \[C(n, k) = \frac{n!}{k! (n - k)!} \] Where \(n\) is the total number of marbles in the bag and \(k\) is the number of marbles Suzan wants to pick. In this case, \(n = 10\) and \(k = 4\). \[C(10, 4) = \frac{10!}{4! (10 - 4)!} = 210\] Now, we need to find the total number of ways Suzan can pick 4 marbles without any red marble. Since there are 7 marbles in the bag other than red (2 green, 1 pink, 2 yellow, and 2 orange), the total possible ways to pick 4 marbles without any red marble is given by the combination formula with \(n = 7\) and \(k = 4\). \[C(7, 4) = \frac{7!}{4! (7 - 4)!} = 35\] Therefore, the total number of ways to pick 4 marbles with at least one red marble is the difference between the total possible ways and the ways without any red marble: \[210 - 35 = 175\]
02

Calculate the number of ways she can pick one marble of each of the selected colors

To find the number of ways Suzan can pick one marble of each of the selected colors (i.e., one red, one green, one yellow, and one orange), we need to select one marble from each color category using the combination formula. For red, green, yellow, and orange marbles, the number of ways to pick one marble is: \- Red: \(C(3, 1) = \frac{3!}{1! (3 - 1)!} = 3\) \- Green: \(C(2, 1) = \frac{2!}{1! (2 - 1)!} = 2\) \- Yellow: \(C(2, 1) = \frac{2!}{1! (2 - 1)!} = 2\) \- Orange: \(C(2, 1) = \frac{2!}{1! (2 - 1)!} = 2\) Now, we need to multiply the number of ways for each color together: \[3 \times 2 \times 2 \times 2 = 24\]
03

Calculate the probability

To find the probability of picking one marble of each of the selected colors, given that she gets at least one red marble, we need to divide the number of ways she can pick one marble of each of the selected colors by the total number of ways to pick 4 marbles with at least one red marble: \[P(1R, 1G, 1Y, 1O | \text{at least 1 R}) = \frac{24}{175}\] Therefore, the probability that Suzan picks one of each color other than fluorescent pink, given that she gets at least one red marble, is \(\frac{24}{175}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Counting Techniques
Counting techniques are essential tools in solving probability problems, especially when we need to find the number of ways to perform a specific action. In our problem, we want to count the number of ways Suzan can select a certain combination of marbles. One common technique is the combination formula, which helps determine how many ways a subset can be picked from a larger set without regard to the order.

The formula for combinations is given by:
  • If you have a set of size \( n \) and you want to select \( k \) items, the number of combinations is \( C(n, k) = \frac{n!}{k!(n-k)!} \).
In the exercise, where Suzan must pick 4 marbles out of 10, and in separate calculations, 4 out of 7, the combination formula allows us to calculate the different ways she can choose these marbles. It is crucial to understand these counting techniques as they provide a foundation for calculating probabilities in more complex situations.

Such problems often arise in real-life scenarios, such as determining different combinations of meal ingredients or selecting a team from a group of candidates. Being proficient in counting techniques greatly aids in the analysis of these situations.
Combinatorics
Combinatorics is the branch of mathematics that deals with counting, arrangement, and combination of objects. It’s used extensively in probability to calculate possible outcomes. In the given problem, combinatorics helps us determine how many ways Suzan can choose marbles from different colors.

One of the initial steps was finding the total number of ways to choose the marbles without any color restrictions, which is calculated using combinations:
  • Total ways to select 4 marbles from 10: \( C(10, 4) = 210 \).
  • Ways to select marbles, avoiding all reds: \( C(7, 4) = 35 \).
  • Thus, ways with at least one red: \( 210 - 35 = 175 \).
Alongside understanding these calculations, who might already know include arrangements which can consider scenarios like ordering objects but were not used in this problem.

However, combinatorics is not just limited to choosing items from a set. It includes permutations (where order matters) and other complex arrangements. Practical uses are everywhere, from logistics planning to software configurations. Learning about combinatorics can open new ways to solve problems efficiently in daily life and professional settings.
Conditional Probability
Conditional probability is the likelihood of an event occurring given that another event has already occurred. In this exercise, we are looking for the probability that Suzan picks marbles of specific colors, assuming she's already picked at least one red marble.

To calculate conditional probability, you use the formula:
  • \( P(A | B) = \frac{P(A \cap B)}{P(B)} \).
Here, \( A \) is the event of getting one marble of each of the selected colors (red, green, yellow, and orange), and \( B \) is the event that at least one red marble is picked.

The exercise walks through identifying \( P(A \cap B) \) (which finds the favorable ways to pick each marble color) and dividing it by \( P(B) \) (ways to pick marbles with at least one red). This concept is vital because it alters how probabilities are calculated based on specific conditions. Understanding conditional probability is crucial to many fields, such as statistics and risk analysis, where decisions are based on assumed or known conditions. It's a powerful tool that becomes second nature with practice, giving deeper insights into how events interact with each other.

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Most popular questions from this chapter

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