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Find a system of inequalities whose solution set is empty.

Short Answer

Expert verified
The system of inequalities \(y > x + 1\) and \(y < x - 1\) has an empty solution set because there are no points (x,y) that can simultaneously satisfy both inequalities.

Step by step solution

01

Define two contradicting inequalities

We can define two linear inequalities which contradict each other such that no pair (x, y) can satisfy both inequalities at the same time. Consider the following inequalities: \(y > x + 1\) and \(y < x - 1\).
02

Analyze the defined inequalities

Let's visualize these inequalities by plotting them on a coordinate plane. The inequality \(y > x + 1\) is satisfied by the points that lie above the line \(y = x + 1\), while the inequality \(y < x - 1\) is satisfied by the points that lie below the line \(y = x - 1\). These two inequalities contradict each other, as there are no points (x, y) that can simultaneously satisfy both inequalities.
03

Determine if the solution set is empty

By analyzing the inequalities, we notice that there are no points (x,y) that lie both above the line \(y = x + 1\) and below the line \(y = x - 1\). Therefore, the solution set of this system of inequalities is empty.

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