/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 You are the marketing director f... [FREE SOLUTION] | 91Ó°ÊÓ

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You are the marketing director for a company that manufactures bodybuilding supplements and you are planning to run ads in Sports Illustrated and \(G Q\) Magazine. Based on readership data, you estimate that each one-page ad in Sports Illustrated will be read by 650,000 people in your target group, while each one-page ad in \(G Q\) will be read by \(150,000 .{ }^{9}\) You would like your ads to be read by at least three million people in the target group and, to ensure the broadest possible audience, you would like to place at least three fullpage ads in each magazine. Draw the feasible region that shows how many pages you can purchase in each magazine. Find the corner points of the region. (Round each coordinate to the nearest whole number.)

Short Answer

Expert verified
The feasible region for purchasing ads in Sports Illustrated and GQ Magazine is defined by the corner points (3, 15), (19, 3), and (3, 3), considering the constraints of at least three million target readers and at least three full-page ads in each magazine.

Step by step solution

01

Define Variables

Let's define the variables: - Let x be the number of one-page ads in Sports Illustrated - Let y be the number of one-page ads in GQ Magazine
02

Write Down the Constraints

According to the problem, we have the following constraints: 1. At least three million target readers: \(650,000x + 150,000y \geq 3,000,000\) 2. At least three full-page ads in each magazine: \(x \geq 3\), \(y \geq 3\)
03

Sketch the Feasible Region

In order to draw the feasible region, we need to sketch the inequalities on a coordinate plane (x, y). For each constraint: 1. \(650,000x + 150,000y \geq 3,000,000\) => \(y \geq \frac{3,000,000 - 650,000x}{150,000}\) 2. \(x \geq 3\) 3. \(y \geq 3\) For each inequality, sketch the region where the inequality is satisfied (above/below/right/left the line). Then, overlay the graphs of all three inequalities and find the intersection of all three regions. This intersection is the feasible region.
04

Find the corner points of the feasible region

To find the corner points of the feasible region, we need to identify the intersection points of the lines from step 3 or any points where the inequality changes. The corner points can be found by solving the systems of linear equations made up from the boundaries of the inequalities: 1. Intersection between constraints 1 and 2: Solve \(650,000x + 150,000y = 3,000,000\) \(x = 3\) 2. Intersection between constraints 1 and 3: Solve \(650,000x + 150,000y = 3,000,000\) \(y = 3\) 3. Intersection between constraints 2 and 3: The point (3, 3) Once the coordinates of the corner points are found, round each coordinate to the nearest whole number.
05

List the corner points

Write down the corner points you found in step 4, rounded to the nearest whole number. The exact corner points are (3, 15), (19, 3), and (3, 3). The rounded corner points are as follows: 1. (3, 15) 2. (19, 3) 3. (3, 3) These are the corner points of the feasible region that represent the possible number of one-page ads in Sports Illustrated and \(GQ\) Magazine considering the given constraints.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Feasible Region
When solving a linear programming problem, the feasible region is a crucial concept. It represents all possible solutions that satisfy the given constraints. In our marketing exercise, this region reflects the combinations of ads in Sports Illustrated and GQ Magazine, which meet the business goals set by the marketing director.

To find the feasible region, we first graph the inequalities derived from the constraints. Each inequality defines a half-plane, and the feasible region is the overlapping area where all conditions are simultaneously met. This region on the graph shows every viable option for how many ads can be placed in each magazine.
  • This region can be bounded or unbounded, being a polygon or an open region, determined by the nature of the constraints.
  • In our problem, the feasible region is a polygon defined by straight lines from the inequalities.
Constraints
Constraints are the conditions or limits that must be satisfied in a linear programming problem. They are usually expressed as linear inequalities. For our exercise, the constraints ensure that our advertising reaches enough people while maintaining a minimum number of ads in each magazine.

In this particular problem, we have three constraints:
  • The total readership must reach at least three million people, expressed by the inequality: \(650,000x + 150,000y \geq 3,000,000\).
  • There must be at least three ads in Sports Illustrated: \(x \geq 3\).
  • Similarly, at least three ads must be placed in GQ Magazine: \(y \geq 3\).
These constraints construct boundaries within which the feasible region is defined. They guide the graphing of the problem, helping to find solutions that satisfy all necessary conditions.
Corner Points
Corner points of the feasible region are the vertices of the polygon created by the intersecting lines of the constraints. These points are significant because, in linear programming, the optimal solution often lies at one of these vertices.

To find these points, we look at where the boundary lines intersect. In our exercise:
  • Solving the system of equations formed by \(650,000x + 150,000y = 3,000,000\) and \(x = 3\), we find one intersection.
  • Another intersection is from \(650,000x + 150,000y = 3,000,000\) and \(y = 3\).
  • The point \((3, 3)\) is found where the constraints \(x \geq 3\) and \(y \geq 3\) meet.
Rounded to the nearest whole number, the corner points are \((3, 15)\), \((19, 3)\), and \((3, 3)\). These represent the potential solutions for ad placements.
Inequalities
Inequalities are mathematical expressions that define the constraints of a linear programming problem. They show the relationship between variables in terms of greater than, less than, or equal to.

In our exercise, inequalities are used to express the minimum requirements for advertisement reach and quantity:
  • \(650,000x + 150,000y \geq 3,000,000\): This inequality ensures the total readership goal.
  • \(x \geq 3\) and \(y \geq 3\): These inequalities ensure a minimum number of ads in each magazine.
These inequalities define the feasible region on a coordinate plane by marking out areas where the requirements are fulfilled. By understanding and graphing these inequalities, students can visually interpret which combinations of advertisement placements are possible within the given limits.

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Most popular questions from this chapter

Your salami manufacturing plant can order up to 1,000 pounds of pork and 2,400 pounds of beef per day for use in manufacturing its two specialties: "Count Dracula Salami" and "Frankenstein Sausage." Production of the Count Dracula variety requires 1 pound of pork and 3 pounds of beef for each salami, while the Frankenstein variety requires 2 pounds of pork and 2 pounds of beef for every sausage. In view of your heavy investment in advertising Count Dracula Salami, you have decided that at least onethird of the total production should be Count Dracula. On the other hand, due to the health-conscious consumer climate. your Frankenstein Sausage (sold as having less beef) is earning your company a profit of \(\$ 3\) per sausage, while sales of the Count Dracula variety are down and it is earning your company only \(\$ 1\) per salami. Given these restrictions, how many of each kind of sausage should you produce to maximize profits, and what is the maximum possible profit? HINT [See Example 3.]

$$ \begin{array}{ll} \text { Maximize } & p=x+y+z+w \\ \text { subject to } & x+y+z \leq 3 \\ & y+z+w \leq 3 \\ & x+z+w \leq 4 \\ & x+y+w \leq 4 \\ & x \geq 0, y \geq 0, z \geq 0, w \geq 0 . \end{array} $$

$$ \begin{array}{ll} \text { Maximize } & p=x+5 y \\ \text { subject to } & x+y \leq 6 \\ & -x+3 y \leq 4 \\ & x \geq 0, y \geq 0 . \end{array} $$

Politics The political pollster Canter is preparing for a national election. It would like to poll at least 1,500 Democrats and 1,500 Republicans. Each mailing to the East Coast gets responses from 100 Democrats and 50 Republicans. Each mailing to the Midwest gets responses from 100 Democrats and 100 Republicans. And each mailing to the West Coast gets responses from 50 Democrats and 100 Republicans. Mailings to the East Coast cost \(\$ 40\) each to produce and mail, mailings to the Midwest cost \(\$ 60\) each, and mailings to the West Coast cost \(\$ 50\) each. How many mailings should Canter send to each area of the country to get the responses it needs at the least possible cost? What will it cost?

Your friend Janet is telling everyone that if there are only two constraints in a linear programming problem, then, in any optimal basic solution, at most two unknowns (other than the objective) will be nonzero. Is she correct? Explain.

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