/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Sketch the region that correspon... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the region that corresponds to the given inequalities, say whether the region is bounded or unbounded, and find the coordinates of all corner points (if any). $$ \begin{aligned} &30 x+20 y \geq 600 \\ &10 x+40 y \geq 400 \\ &20 x+30 y \geq 600 \\ &x \geq 0, y \geq 0 \end{aligned} $$

Short Answer

Expert verified
The bounded region corresponds to the intersecting shaded regions in the first quadrant, formed by graphing the inequalities \(y \geq 30 - \frac{3}{2}x\), \(y \geq 10 - \frac{1}{4}x\), \(y \geq 20 - \frac{2}{3}x\), \(x \geq 0\), and \(y \geq 0\). The corner points of this region are \(A (12, 18)\), \(B (18, 12)\), and \(C (24, 10)\).

Step by step solution

01

Rearrange inequalities

Solve each inequality for the dependent variable y regarding the non-negative constraints: 1. \(30x + 20y \geq 600\): Divide by 20: \(y \geq 30 - \frac{3}{2}x\) 2. \(10x + 40y \geq 400\): Divide by 10: \(y \geq 10 - \frac{1}{4}x\) 3. \(20x + 30y \geq 600\): Divide by 10: \(y \geq 20 - \frac{2}{3}x\) Now, we have: $$ \begin{aligned} &y \geq 30 - \frac{3}{2}x \\ &y \geq 10 - \frac{1}{4}x \\ &y \geq 20 - \frac{2}{3}x \\ &x \geq 0, y \geq 0 \end{aligned} $$
02

Graph the inequalities

On a coordinate plane, sketch the lines corresponding to each inequality boundary by selecting two points for each equation and connecting them: 1. \(y = 30 - \frac{3}{2}x\): Choose \(x = 0\) and \(x = 20\). 2. \(y = 10 - \frac{1}{4}x\): Choose \(x = 0\) and \(x = 40\). 3. \(y = 20 - \frac{2}{3}x\): Choose \(x = 0\) and \(x = 30\). The constraint \(x \geq 0\) and \(y \geq 0\) indicates that we are limited to the first quadrant of the coordinate plane. Shade the regions above the lines (representing the "\(\geq\)" inequality), only in the first quadrant.
03

Determine if the region is bounded or unbounded

Observe the intersecting shaded regions created in step 2. As the overlapping region is enclosed within the given inequalities and the axes (x-axis and y-axis), it is bounded.
04

Calculate the coordinates of corner points

To find the corner points of the bounded region, we need to determine the points of intersection between the lines. There are three lines, which means we must solve three systems of equations resulting in three points of intersection: 1. Point A: \( \begin{cases} 30 - \frac{3}{2}x = 10 - \frac{1}{4}x \\ 20 - \frac{2}{3}x = 10 - \frac{1}{4}x \end{cases} \) 2. Point B: \( \begin{cases} 30 - \frac{3}{2}x = 20 - \frac{2}{3}x \\ 20 - \frac{2}{3}x = 10 - \frac{1}{4}x \end{cases} \) 3. Point C: \( \begin{cases} 30 - \frac{3}{2}x = 10 - \frac{1}{4}x \\ 10 - \frac{1}{4}x = 20 - \frac{2}{3}x \end{cases} \) Solving each system of equations gives us: 1. Point A: \((12, 18)\) 2. Point B: \((18, 12)\) 3. Point C: \((24, 10)\) #Summary# The region is bounded, and the corner points are \(A (12, 18)\), \(B (18, 12)\), and \(C (24, 10)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Inequalities
When we talk about linear inequalities, we're discussing expressions where two linear expressions are compared using inequality signs like >, <, >=, and <=. Unlike equalities (equations), which denote exact values, inequalities allow for a range of values. For instance, the inequality 3x + 2y >= 6 tells us that the sum of three times x and two times y is greater than or equal to 6. In the system of inequalities from our exercise, we're dealing with multiple linear inequalities that together define a common solution region.

To visualize these solutions, we need to express each inequality in terms of y, allowing us to graph them in a two-dimensional coordinate system. The goal is to identify the region of the plane where all inequalities hold true simultaneously.
Graphing Inequalities
The process of graphing inequalities is a straightforward extension of graphing linear equations. With an inequality, instead of drawing a line to represent an equation, we shade an entire region of the graph. This shaded area represents all possible solutions to the inequality. For instance, when graphing y >= 30 - 3x/2, you would first graph the line y = 30 - 3x/2 as if it were an equation. Then, since the inequality is >=, you would shade the area above the line. This indicates that every point in that shaded area is a solution. When working with a system of inequalities, we graph each one on the same coordinate plane and look for the overlapping shaded areas, which indicate where all the inequalities are satisfied simultaneously.

Remember, the inequality sign tells us which side of the line to shade. For > or >=, we shade above the line. For < or <=, we shade below. Also, if the inequality is strict (> or <), the line is dashed to show that points on the line itself are not included in the solution.
Bounded Region
When graphing the system of inequalities, we determine whether the solution set is a bounded region or an unbounded one. A bounded region has a finite area, entirely enclosed by lines or curves, and it has edges that we can trace. In the context of our exercise, where all inequalities are in the first quadrant and intersect with each other and the axes, the overlapping shaded areas create a polygon. This polygon is the bounded region with a definite boundary. An unbounded region, in contrast, extends infinitely in at least one direction and thus does not form a closed shape. The bounded nature of the region is particularly important when solving optimization problems because it guarantees that a maximum or minimum value exists within the region.
Corner Points
The corner points (also known as vertices) of a bounded region are points of intersection where the boundary lines meet. They are crucial in optimization problems because, according to the linear programming principle, the optimal solution lies at one of these corner points. To find them, we solve a system of equations made from each pair of boundary lines. In our exercise, we calculate where each pair of lines intersects by setting the equations equal to each other and solving for x and y. Once we find the corner points, we can evaluate any objective function at these points to find the optimal solution.

From our step by step solution, we found that the corner points were at (12, 18), (18, 12), and (24, 10). Determining these points allows us to proceed with related tasks, such as optimization or further analysis of the feasible region.

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Most popular questions from this chapter

Finance Senator Porkbarrel habitually overdraws his three bank accounts, at the Congressional Integrity Bank, Citizens' Trust, and Checks R Us. There are no penalties because the overdrafts are subsidized by the taxpayer. The Senate Ethics Committee tends to let slide irregular banking activities as long as they are not flagrant. At the moment (due to Congress" preoccupation with a Supreme Court nominee), a total overdraft of up to \(\$ 10,000\) will be overlooked. Porkbarrel's conscience makes him hesitate to overdraw accounts at banks whose names include expressions like "integrity" and "citizens' trust." The effect is that his overdrafts at the first two banks combined amount to no more than one-quarter of the total. On the other hand, the financial officers at Integrity Bank, aware that Senator Porkbarrel is a member of the Senate Banking Committee, "suggest" that he overdraw at least \(\$ 2,500\) from their bank. Find the amount he should overdraw from each bank in order to avoid investigation by the Ethics Committee and overdraw his account at Integrity by as much as his sense of guilt will allow.

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