/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 I Purchasing Cheapskate Electron... [FREE SOLUTION] | 91Ó°ÊÓ

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I Purchasing Cheapskate Electronics Store needs to update its inventory of stereos, TVs, and DVD players. There are three suppliers it can buy from: Nadir offers a bundle consisting of 5 stereos, 10 TVs, and 15 DVD players for \(\$ 3,000\). Blunt offers a bundle consisting of 10 stereos, \(10 \mathrm{TVs}\), and 10 DVD players for \(\$ 4,000\). Sonny offers a bundle consisting of 15 stereos, \(10 \mathrm{TVs}\), and 10 DVD players for \(\$ 5,000\). Cheapskate Electronics needs at least 150 stereos, \(200 \mathrm{TVs}\), and 150 DVD players. How can it update its inventory at the least possible cost? What is the least possible cost?

Short Answer

Expert verified
The least possible cost to update the inventory is \(\$80,000\) by purchasing 20 bundles from Blunt, meeting the required number of stereos, TVs, and DVD players.

Step by step solution

01

Set up the system of inequalities

According to the minimum requirements for each type of item, we can write the following inequality constraints: 1. For stereos: \(5x + 10y + 15z \geq 150 \) 2. For TVs: \(10x + 10y + 10z \geq 200 \) 3. For DVD players: \(15x + 10y + 10z \geq 150 \) 4. Non-negativity constraints: \(x, y, z \geq 0 \)
02

Simplify the inequalities

We can simplify the inequalities by dividing through by common factors: 1. For stereos: \( x + 2y + 3z \geq 30 \) 2. For TVs: \( x + y + z \geq 20 \) 3. For DVD players: \( 3x + 2y + 2z \geq 30\)
03

Solve the system of inequalities using linear programming methods

The system of inequalities consists of a feasible region defined by the inequalities. We can use linear programming methods, such as the Simplex Method or the graphical method, to find the optimal solution that minimizes the cost function. Since this is a three-variable problem, using the Simplex Method will be more efficient. Using the Simplex Method, we find the optimal solution to be \(x = 0, y = 20, z = 0 \), which means that purchasing 20 bundles from Blunt is the most cost-effective way to update the inventory.
04

Calculate the least possible cost

Now we can plug the optimal solution into the cost function: C(0, 20, 0) = 3000(0) + 4000(20) + 5000(0) = \(\$ 80,000\) So, the least possible cost to update the inventory is \(\$80,000\). The best option for the electronics store is to purchase 20 bundles from Blunt at a total cost of 80,000 dollars.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

System of Inequalities
A system of inequalities consists of multiple inequality constraints that must be satisfied simultaneously. In our scenario, Cheapskate Electronics has certain requirements for stereos, TVs, and DVD players:
  • At least 150 stereos
  • At least 200 TVs
  • At least 150 DVD players
We express these requirements as inequalities. Each supplier offers different bundles of these electronics at a fixed price. For example, Nadir offers 5 stereos, 10 TVs, and 15 DVD players. If we denote the quantity of Nadir bundles as \(x\), Blunt as \(y\), and Sonny as \(z\), we can write the inequalities based on the bundles and the electronic needs:
  • For stereos: \(5x + 10y + 15z \geq 150\)
  • For TVs: \(10x + 10y + 10z \geq 200\)
  • For DVD players: \(15x + 10y + 10z \geq 150\)
Additionally, ensuring non-negative quantities means \(x, y, z \geq 0\). Simplifying these inequalities, leads to a more efficient problem-solving process. This simplification helps in the next steps of linear programming.
Simplex Method
The Simplex Method is a powerful algorithm used in linear programming to find the optimal solution to a problem with multiple linear inequalities. It is especially useful in situations where the problem involves more than two variables, as in the case of Cheapskate Electronics' inventory issue. In the Simplex Method, we begin with a feasible solution and iteratively move towards the optimal solution by traversing through the 'corners' of the solution space defined by the system of inequalities. Each corner is a potential solution. The Simplex Method continues until it finds the minimum (or maximum, in other cases) value of the objective function, which in this exercise is cost minimization. Using this method allows us to efficiently handle and solve linear programming problems even with constraints from different suppliers, catering to diverse needs in an optimal manner.
Optimization
Optimization is the process of finding the best solution among a set of feasible solutions. In linear programming, it revolves around maximizing or minimizing a particular objective function subject to constraints.For instance, in the problem faced by Cheapskate Electronics, the objective is to minimize the total cost, represented by the equation:\[ C = 3000x + 4000y + 5000z \]subject to the simplified inequalities:
  • \(x + 2y + 3z \geq 30\)
  • \(x + y + z \geq 20\)
  • \(3x + 2y + 2z \geq 30\)
The solution aims to satisfy these equations while minimizing the cost, balancing quality, and quantity demands with the price constraints of each supplier.
Cost Minimization
Cost minimization involves finding the least expensive way to meet specific requirements or objectives. In linear programming, this is achieved through optimizing the given equations and inequalities.In the Cheapskate Electronics example, the goal is to minimize the total expenditure while still fulfilling the inventory needs of stereos, TVs, and DVD players. This ensures that the business can meet customer demands without overspending.By applying the optimal purchase strategy (in this case, buying 20 bundles from Blunt), the company achieves its requirement at the minimal possible cost of \(\$80,000\). This strategic purchase showcases a precise example of cost minimization, ensuring efficiency and budget management within the constraints.

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Most popular questions from this chapter

Agriculture \(^{30}\) Your farm encompasses 900 acres, and you are planning to grow soybeans, corn, and wheat in the coming planting season. Fertilizer costs per acre are: \(\$ 5\) for soybeans, \(\$ 2\) for corn, and \(\$ 1\) for wheat. You estimate that each acre of soybeans will require an average of 5 hours of labor per week, while tending to corn and wheat will each require an average of 2 hours per week. Based on past yields and current market prices, you estimate a profit of \(\$ 3,000\) for each acre of soybeans, \(\$ 2,000\) for each acre of corn, and \(\$ 1,000\) for each acre of wheat. You can afford to spend no more than \(\$ 3,000\) on fertilizer, but your labor union contract stipulates at least 2,000 hours per week of labor. How many acres of each crop should you plant to maximize total profits? In this event, will you be using more than 2,000 hours of labor?

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