Chapter 8: Problem 3
Evaluate the following expressions for \(x=2\) and \(x=-2\). a. \(x^{-3}\) b. \(4 x^{-3}\) c. \(-4 x^{-3}\) d. \(-4 x^{3}\)
Short Answer
Expert verified
a. \(x=2: \frac{1}{8}\), \(x=-2: -\frac{1}{8}\). b. \(x=2: \frac{1}{2}\), \(x=-2: -\frac{1}{2}\). c. \(x=2: -\frac{1}{2}\), \(x=-2: \frac{1}{2}\). d. \(x=2: -32\), \(x=-2: 32\).
Step by step solution
01
Substitute for x in expression a
To evaluate the expression \(x^{-3}\) for \(x=2\) and \(x=-2\), substitute \(x\) with the given values: \(x^{-3} = 2^{-3}\)\(x^{-3} = (-2)^{-3}\).
02
Evaluate a for x = 2
Calculate \(2^{-3}\): \(2^{-3} = \frac{1}{2^{3}} = \frac{1}{8}\).
03
Evaluate a for x = -2
Calculate \((-2)^{-3}\): \((-2)^{-3} = \frac{1}{(-2)^{3}} = \frac{1}{-8} = -\frac{1}{8}\).
04
Substitute for x in expression b
To evaluate the expression \(4x^{-3}\) for \(x=2\) and \(x=-2\), substitute \(x\) with the given values: \(4x^{-3} = 4(2^{-3})\)\(4x^{-3} = 4((-2)^{-3})\).
05
Evaluate b for x = 2
Calculate \(4(2^{-3})\): \(4(2^{-3}) = 4 \times \frac{1}{8} = \frac{4}{8} = \frac{1}{2}\).
06
Evaluate b for x = -2
Calculate \(4((-2)^{-3})\): \(4((-2)^{-3}) = 4 \times -\frac{1}{8} = -\frac{4}{8} = -\frac{1}{2}\).
07
Substitute for x in expression c
To evaluate the expression \(-4x^{-3}\) for \(x=2\) and \(x=-2\), substitute \(x\) with the given values: \(-4x^{-3} = -4(2^{-3})\)\(-4x^{-3} = -4((-2)^{-3})\).
08
Evaluate c for x = 2
Calculate \(-4(2^{-3})\): \(-4(2^{-3}) = -4 \times \frac{1}{8} = -\frac{4}{8} = -\frac{1}{2}\).
09
Evaluate c for x = -2
Calculate \(-4((-2)^{-3})\): \(-4((-2)^{-3}) = -4 \times -\frac{1}{8} = \frac{4}{8} = \frac{1}{2}\).
10
Substitute for x in expression d
To evaluate the expression \(-4x^{3}\) for \(x=2\) and \(x=-2\), substitute \(x\) with the given values: \(-4x^{3} = -4(2^{3})\)\(-4x^{3} = -4((-2)^{3})\).
11
Evaluate d for x = 2
Calculate \(-4(2^{3})\): \(-4(2^{3}) = -4 \times 8 = -32\).
12
Evaluate d for x = -2
Calculate \(-4((-2)^{3})\): \(-4((-2)^{3}) = -4 \times -8 = 32\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponents
Exponents are a fundamental concept in mathematics. An exponent indicates how many times a number (the base) is multiplied by itself. For example, in the expression \(2^3\), 2 is the base and 3 is the exponent, meaning \(2 \times 2 \times 2 = 8\). Exponents greatly simplify expressing large numbers or repeated multiplication. When seen in general terms: \(a^n\) means you multiply \(a\) by itself \(n\) times. Special cases include \(a^1 = a\) and \(a^0 = 1\). This simple principle is the foundation for understanding more complex uses, such as negative exponents and algebraic substitution.
Negative Exponents
Negative exponents represent the reciprocal of a number raised to the corresponding positive exponent. For example, \(a^{-n} = \frac{1}{a^n}\). This is especially useful in transforming division problems into multiplication problems. Consider the example from the exercise: \(2^{-3} = \frac{1}{2^3} = \frac{1}{8}\). Likewise, \((-2)^{-3} = \frac{1}{(-2)^3} = \frac{1}{-8} = -\frac{1}{8}\). Remember that when dealing with negatives, the placement of the negative sign is crucial. If \(a\) is a negative base, make sure the entire base is in parentheses.
Substitution in Algebra
Substitution in algebra involves replacing a variable with a given number to simplify or solve an expression. Here, we are replacing \(x\) with given values and simplifying accordingly. For example, to evaluate \(4x^{-3}\) for \(x=2\), we substitute 2 in place of \(x\): \(4(2^{-3})\). We already know \(2^{-3} = \frac{1}{8}\), so the expression becomes \(4 \times \frac{1}{8} = \frac{4}{8} = \frac{1}{2}\). Doing the same for \(x=-2\), \(4((-2)^{-3}) = 4 \times -\frac{1}{8} = -\frac{4}{8} = -\frac{1}{2}\). Practice this concept using different numbers to better understand how substitution works in various contexts. Always pay attention to the signs and values involved in each substitution for accurate results.