/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Evaluate the following expressio... [FREE SOLUTION] | 91Ó°ÊÓ

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Evaluate the following expressions for \(x=2\) and \(x=-2\). a. \(x^{-3}\) b. \(4 x^{-3}\) c. \(-4 x^{-3}\) d. \(-4 x^{3}\)

Short Answer

Expert verified
a. \(x=2: \frac{1}{8}\), \(x=-2: -\frac{1}{8}\). b. \(x=2: \frac{1}{2}\), \(x=-2: -\frac{1}{2}\). c. \(x=2: -\frac{1}{2}\), \(x=-2: \frac{1}{2}\). d. \(x=2: -32\), \(x=-2: 32\).

Step by step solution

01

Substitute for x in expression a

To evaluate the expression \(x^{-3}\) for \(x=2\) and \(x=-2\), substitute \(x\) with the given values: \(x^{-3} = 2^{-3}\)\(x^{-3} = (-2)^{-3}\).
02

Evaluate a for x = 2

Calculate \(2^{-3}\): \(2^{-3} = \frac{1}{2^{3}} = \frac{1}{8}\).
03

Evaluate a for x = -2

Calculate \((-2)^{-3}\): \((-2)^{-3} = \frac{1}{(-2)^{3}} = \frac{1}{-8} = -\frac{1}{8}\).
04

Substitute for x in expression b

To evaluate the expression \(4x^{-3}\) for \(x=2\) and \(x=-2\), substitute \(x\) with the given values: \(4x^{-3} = 4(2^{-3})\)\(4x^{-3} = 4((-2)^{-3})\).
05

Evaluate b for x = 2

Calculate \(4(2^{-3})\): \(4(2^{-3}) = 4 \times \frac{1}{8} = \frac{4}{8} = \frac{1}{2}\).
06

Evaluate b for x = -2

Calculate \(4((-2)^{-3})\): \(4((-2)^{-3}) = 4 \times -\frac{1}{8} = -\frac{4}{8} = -\frac{1}{2}\).
07

Substitute for x in expression c

To evaluate the expression \(-4x^{-3}\) for \(x=2\) and \(x=-2\), substitute \(x\) with the given values: \(-4x^{-3} = -4(2^{-3})\)\(-4x^{-3} = -4((-2)^{-3})\).
08

Evaluate c for x = 2

Calculate \(-4(2^{-3})\): \(-4(2^{-3}) = -4 \times \frac{1}{8} = -\frac{4}{8} = -\frac{1}{2}\).
09

Evaluate c for x = -2

Calculate \(-4((-2)^{-3})\): \(-4((-2)^{-3}) = -4 \times -\frac{1}{8} = \frac{4}{8} = \frac{1}{2}\).
10

Substitute for x in expression d

To evaluate the expression \(-4x^{3}\) for \(x=2\) and \(x=-2\), substitute \(x\) with the given values: \(-4x^{3} = -4(2^{3})\)\(-4x^{3} = -4((-2)^{3})\).
11

Evaluate d for x = 2

Calculate \(-4(2^{3})\): \(-4(2^{3}) = -4 \times 8 = -32\).
12

Evaluate d for x = -2

Calculate \(-4((-2)^{3})\): \(-4((-2)^{3}) = -4 \times -8 = 32\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponents
Exponents are a fundamental concept in mathematics. An exponent indicates how many times a number (the base) is multiplied by itself. For example, in the expression \(2^3\), 2 is the base and 3 is the exponent, meaning \(2 \times 2 \times 2 = 8\). Exponents greatly simplify expressing large numbers or repeated multiplication. When seen in general terms: \(a^n\) means you multiply \(a\) by itself \(n\) times. Special cases include \(a^1 = a\) and \(a^0 = 1\). This simple principle is the foundation for understanding more complex uses, such as negative exponents and algebraic substitution.
Negative Exponents
Negative exponents represent the reciprocal of a number raised to the corresponding positive exponent. For example, \(a^{-n} = \frac{1}{a^n}\). This is especially useful in transforming division problems into multiplication problems. Consider the example from the exercise: \(2^{-3} = \frac{1}{2^3} = \frac{1}{8}\). Likewise, \((-2)^{-3} = \frac{1}{(-2)^3} = \frac{1}{-8} = -\frac{1}{8}\). Remember that when dealing with negatives, the placement of the negative sign is crucial. If \(a\) is a negative base, make sure the entire base is in parentheses.
Substitution in Algebra
Substitution in algebra involves replacing a variable with a given number to simplify or solve an expression. Here, we are replacing \(x\) with given values and simplifying accordingly. For example, to evaluate \(4x^{-3}\) for \(x=2\), we substitute 2 in place of \(x\): \(4(2^{-3})\). We already know \(2^{-3} = \frac{1}{8}\), so the expression becomes \(4 \times \frac{1}{8} = \frac{4}{8} = \frac{1}{2}\). Doing the same for \(x=-2\), \(4((-2)^{-3}) = 4 \times -\frac{1}{8} = -\frac{4}{8} = -\frac{1}{2}\). Practice this concept using different numbers to better understand how substitution works in various contexts. Always pay attention to the signs and values involved in each substitution for accurate results.

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