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(Graphing program optional.) Create a quadratic function in the vertex form \(y=a(x-h)^{2}+k,\) given the specified values for \(a\) and the vertex \((h, k) .\) Then rewrite the function in the standard form \(y=a x^{2}+b x+c .\) If available, use technology to check that the graphs of the two forms are the same. a. \(a=1,(h, k)=(2,-4)\) c. \(a=-2,(h, k)=(-3,1)\) b. \(a=-1,(h, k)=(4,3)\) d. \(a=\frac{1}{2},(h, k)=(-4,6)\)

Short Answer

Expert verified
a) y = x^2 - 4x; b) y = -x^2 + 8x - 13; c) y = -2x^2 - 12x - 17; d) y = \frac{1}{2}x^2 + 4x + 14.

Step by step solution

01

Identify the vertex form of the quadratic function

The vertex form of a quadratic function is given by \(y = a(x - h)^2 + k\). For each part, we use the given values of \(a\), \(h\), and \(k\) to write the vertex form first.
02

Part a: Use the given values to form the vertex equation

For part a, \(a = 1\), \(h = 2\), and \(k = -4\). The vertex form becomes: \[ y = 1(x - 2)^2 - 4 \]
03

Expand to rewrite in standard form

First, expand the squared term: \((x - 2)^2 = x^2 - 4x + 4\). Then, multiply by \(a = 1\) and combine with \(k = -4\): \[ y = 1(x^2 - 4x + 4) - 4 \ y = x^2 - 4x + 4 - 4 \ y = x^2 - 4x \]
04

Part b: Use the given values to form the vertex equation

For part b, \(a = -1\), \(h = 4\), and \(k = 3\). The vertex form becomes: \[ y = -1(x - 4)^2 + 3 \]
05

Expand to rewrite in standard form

First, expand the squared term: \((x - 4)^2 = x^2 - 8x + 16\). Then, multiply by \(a = -1\) and combine with \(k = 3\): \[ y = -1(x^2 - 8x + 16) + 3 \ y = -x^2 + 8x - 16 + 3 \ y = -x^2 + 8x - 13 \]
06

Part c: Use the given values to form the vertex equation

For part c, \(a = -2\), \(h = -3\), and \(k = 1\). The vertex form becomes: \[ y = -2(x + 3)^2 + 1 \]
07

Expand to rewrite in standard form

First, expand the squared term: \((x + 3)^2 = x^2 + 6x + 9\). Then, multiply by \(a = -2\) and combine with \(k = 1\): \[ y = -2(x^2 + 6x + 9) + 1 \ y = -2x^2 - 12x - 18 + 1 \ y = -2x^2 - 12x - 17 \]
08

Part d: Use the given values to form the vertex equation

For part d, \(a = \frac{1}{2}\), \(h = -4\), and \(k = 6\). The vertex form becomes: \[ y = \frac{1}{2}(x + 4)^2 + 6 \]
09

Expand to rewrite in standard form

First, expand the squared term: \((x + 4)^2 = x^2 + 8x + 16\). Then, multiply by \(a = \frac{1}{2}\) and combine with \(k = 6\): \[ y = \frac{1}{2}(x^2 + 8x + 16) + 6 \ y = \frac{1}{2}x^2 + 4x + 8 + 6 \ y = \frac{1}{2}x^2 + 4x + 14 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertex Form
Quadratic functions can be written in a special format called the vertex form, which makes it easier to identify the vertex of the parabola. The vertex form is given by:
\( y = a(x - h)^2 + k \).
- Here, \(a\) is the coefficient that stretches or compresses the parabola.
- \(h\) and \(k\) are the coordinates of the vertex of the parabola.
For example, take part (a) of the exercise:
The given values are \(a = 1, h = 2, k = -4\).
The vertex form becomes:
\(y = 1(x - 2)^2 - 4 \).
From this equation, you can see that the parabola has a vertex at \( (2, -4) \). It opens upwards because the coefficient \((a = 1)\) is positive.
Standard Form
Another way to express quadratic functions is the standard form: \( y = ax^2 + bx + c \).
Here, \(a, b,\) and \(c\) are constants. This form is useful for identifying the y-intercept (\b{c}\b) and for some algebraic manipulations.
To convert from vertex form to standard form, you expand and simplify the equation.
Using part (b)'s example, with \(a = -1, h = 4, k = 3 \):
Vertex form: \( y = -1(x - 4)^2 + 3 \)
First, expand \( (x - 4)^2 \rightarrow x^2 - 8x + 16 \).
Then, the equation becomes: \( y = -1(x^2 - 8x + 16) + 3 \).
Distribute the -1: \( y = -x^2 + 8x - 16 + 3 \).
Combine like terms to get: \( y = -x^2 + 8x - 13 \).
Now, you have the standard form: \( y = -x^2 + 8x - 13 \).
Graphing
Graphing quadratic functions helps visualize their properties, like the vertex, axis of symmetry, and direction of opening.

  • Vertex: In the vertex form, \((h, k)\) is the vertex of the parabola.
  • Axis of Symmetry: It is the vertical line that passes through the vertex, given by \( x = h \).
  • Direction: If \( a > 0 \), the parabola opens upwards. If \( a < 0 \), it opens downwards.
For instance, part (c) with \( a = -2, h = -3, k = 1 \):
The equation in vertex form is: \( y = -2(x + 3)^2 + 1 \).
It converts to standard form as: \( y = -2x^2 - 12x - 17 \).
On the graph:
- The vertex is at \(( -3, 1 )\).
- It opens downwards because \( a = -2\) is negative.
- The axis of symmetry is \( x = -3 \).
These aspects help in correctly drawing the graph. Utilizing technology and graphing programs can further verify accuracy.

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