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If we know the radius and depth of a parabolic reflector, we also know where the focus is. a. Find a generic formula for the focal length \(f\) of a parabolic reflector expressed in terms of its radius \(R\) and depth \(D\). The focal length \(\left|\frac{1}{4 a}\right|\) is the distance between the vertex and the focal point. Assume \(a>0\). b. Under what conditions does \(f=D ?\)

Short Answer

Expert verified
The focal length \(f\) is \(\frac{R^2}{4D}\). For \(f\) to equal \(D\), the radius \(R\) must be \(2D\).

Step by step solution

01

Understand Parabolic Reflector Properties

A parabolic reflector can be described by a parabolic equation of the form \(y=ax^2\). The focus of the parabola is located at \(\left(0, \frac{1}{4a}\right)\). Here, \(a\) is a constant and is positive.
02

Relate Radius and Depth to Parabola

The radius \(R\) is the horizontal distance from the vertex to the edge of the parabola at depth \(D\). The depth \(D\) is the vertical distance from the vertex to the point where \(x = R\) on the parabola.
03

Equation Setup

Using the parabola equation \(y = ax^2\), substitute \(x = R\) and \(y = D\): \(D = aR^2\).
04

Solve for \(a\)

Solve the equation \(D = aR^2\) for \(a\): \(a = \frac{D}{R^2}\).
05

Focal Length Formula

The focal length \(f\) is given by \(\frac{1}{4a}\). Substitute \(a = \frac{D}{R^2}\) into the focal length formula: \(f = \frac{1}{4 \cdot \frac{D}{R^2}} = \frac{R^2}{4D}\). Therefore, the focal length \(f\) is \(\frac{R^2}{4D}\).
06

Condition for \(f = D\)

Set the focal length \(f\) equal to the depth \(D\): \(D = \frac{R^2}{4D}\). Solve for \(R\): \(D^2 = \frac{R^2}{4}\), so \(R = 2D\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

parabola equations
A parabolic reflector is shaped like a parabola, which can be represented by a specific kind of mathematical equation. The standard form of a parabola that opens upwards is given by the equation:
ewline
\( y = ax^2 \)
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Here, a is a constant that determines the 'width' or 'narrowness' of the parabola. The point at which the parabola changes direction is called the vertex, located at the origin (0,0) in this case. The focus, which is a key part of a parabolic reflector, is given by the point \( \left( 0, \frac{1}{4a} \right) \). Understanding these components is crucial for solving further problems involving parabolic reflectors.
  • Vertex: The turning point of the parabola.
  • Focus: The point towards which the parabola curves.

This simple equation lays the groundwork for understanding more advanced concepts like focal length calculation and reflector geometry. As we proceed, keep this equation and its components in mind to see how they interrelate.
focal length calculation
The focal length of a parabolic reflector, represented as f, is the distance from its vertex to its focus point. For any parabola, this focal length can be found using the formula:
\( f = \frac{1}{4a} \)
In the context of a parabolic reflector, finding this focal length involves a few simple steps. We know that the reflector's curve follows the equation \( y = ax^2 \) and the radius R is the horizontal distance to the edge, while the depth D is the vertical distance to the point x = R. By substituting these values, we get:

\( D = aR^2 \)
Solving for a, we obtain:
\( a = \frac{D}{R^2} \)
Now, plugging this value of a into the focal length formula, we find:

\[ f = \frac{1}{4 \cdot \frac{D}{R^2}} = \frac{R^2}{4D} \]
Hence, the focal length calculation involves simple substitution and algebraic manipulation, allowing us to derive the distance based on the reflector's dimensions.
parabolic reflector geometry
The geometry of a parabolic reflector is key to its function, particularly in focusing light or other waves to a single point. This geometry is defined by its symmetrical, bowl-like shape and the way it can reflect rays parallel to its axis toward its focus.

In mathematical terms, this geometric relationship is described by the parabolic equation we discussed earlier:
\( y = ax^2 \)
This form means every point on the parabola is equidistant from the focus and a line called the directrix, giving it unique reflective properties. Some crucial terms and ideas in parabolic reflector geometry include:
  • Vertex: The central point of the parabola, from which the depth and radius are measured.
  • Focus: The point where all reflected rays converge.
  • Radius (R): The horizontal measure from the vertex to the edge.
  • Depth (D): The vertical measure from the vertex to the point corresponding to the radius.

Understanding these principles helps in designing and analyzing parabolic reflectors for various applications like satellite dishes, flashlights, and more.
radius and depth relationship
In a parabolic reflector, the radius R and depth D are intrinsically linked through the parabola's geometry. The relationship between these measures directly impacts the focal length and overall effectiveness of the reflector.

To establish this relationship, consider the parabolic equation at the point where x = R:
\( y = aR^2 \)
Since at this point, y = D, substitute to get:

\[ D = aR^2 \]
Solving for a, which represents the shape's curvature, we find:

\[ a = \frac{D}{R^2} \]
This equation helps determine how changes in one metric affect the other. For instance:
  • If the depth increases while the radius remains constant, the reflector becomes more

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Most popular questions from this chapter

(Graphing program optional.) a. On separate grids sketch the graphs of \(f(x)=\sqrt{-x+2}\) and \(g(x)=-\sqrt{x+2}\) b. Using interval notation, describe the domains of \(f(x)\) and \(g(x)\) c. Using interval notation, describe the ranges of \(f(x)\) and \(g(x)\) d. What is the simplest function \(h(x)\) from which both \(f(x)\) and \(g(x)\) could be created? e. Describe the transformations of \(h(x)\) to obtain \(f(x)\). Of \(h(x)\) to obtain \(g(x)\) f. Does the graph of \(f(x), g(x),\) or \(h(x)\) have any symmetries (across the \(x\) - or \(y\) -axis, or about the origin)?

Identify the \(x\) -intercepts of the following functions; then graph the functions to check your work. a. \(y=3 x+6\) b. \(y=(x+4)(x-1)\) c. \(y=(x+5)(x-3)(2 x+5)\)

On March \(2,2007,\) the conversion rate from U.S. dollars to euros was \(0.749 ;\) that is, on that day you could change \(\$ 1\) for 0.749 euros, the currency of the European Union. a. Was a U.S. dollar worth more or less than 1 euro? b. Using the March 2 exchange rate, construct a function \(C_{1}(d)\) that converts \(d\) dollars to euros. What is \(C_{1}(1) ?\) \(C_{1}(25) ?\) c. Now construct a second function \(\mathrm{C}_{2}(r)\) that converts \(r\) euros back to dollars. What is \(C_{2}(1) ? C_{2}(100) ?\) d. Show that \(C_{1}\) and \(C_{2}\) are inverses of each other. e. Reread the beginning of Exercise 8 , which describes a conversion process between Canadian and U.S. dollars. In that process the two formulas are not inverses of each other. Why not?

Which of the following are true statements for quadratic functions? a. The vertex and focal point always lie on the axis of symmetry. b. The graph of a parabola could have three horizontal intercepts. c. The graph of a parabola does not necessarily have a vertical intercept. d. If \(f(2)=0,\) then \(f\) has a horizontal intercept at 2 . e. The focal point always lies above the vertex.

Tom has a taste for adventure. He decides that he wants to bungee-jump off the Missouri River bridge. At any time \(t\) (in seconds from the moment he jumps) his height \(h(t)\) (in feet above the water level) is given by the function \(h(t)=20.5 t^{2}-123 t+190.5 .\) How close to the water will Tom get?

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