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On March \(2,2007,\) the conversion rate from U.S. dollars to euros was \(0.749 ;\) that is, on that day you could change \(\$ 1\) for 0.749 euros, the currency of the European Union. a. Was a U.S. dollar worth more or less than 1 euro? b. Using the March 2 exchange rate, construct a function \(C_{1}(d)\) that converts \(d\) dollars to euros. What is \(C_{1}(1) ?\) \(C_{1}(25) ?\) c. Now construct a second function \(\mathrm{C}_{2}(r)\) that converts \(r\) euros back to dollars. What is \(C_{2}(1) ? C_{2}(100) ?\) d. Show that \(C_{1}\) and \(C_{2}\) are inverses of each other. e. Reread the beginning of Exercise 8 , which describes a conversion process between Canadian and U.S. dollars. In that process the two formulas are not inverses of each other. Why not?

Short Answer

Expert verified
a. Lessb. \(C_{1}(1) = 0.749\) and \(C_{1}(25) = 18.725\)c. \(C_{2}(1) ≈ 1.335\) and \(C_{2}(100) ≈ 133.51\)d. Yese. Different conversion rates

Step by step solution

01

Determine if a U.S. dollar is worth more or less than 1 euro

Given that the conversion rate from U.S. dollars to euros is 0.749, you can exchange \(1\) U.S. dollar for 0.749 euros. This means that \(1\) U.S. dollar is worth less than \(1\) euro because \(0.749 < 1\).
02

Construct the function to convert dollars to euros

To convert \(d\) dollars to euros using the given exchange rate, multiply \(d\) by 0.749. This gives the function \(C_{1}(d) = 0.749d\).
03

Evaluate the function at specific values

Using the function \(C_{1}(d) = 0.749d\): \1. \(C_{1}(1) = 0.749 \times 1 = 0.749\). \2. \(C_{1}(25) = 0.749 \times 25 = 18.725\).
04

Construct the function to convert euros back to dollars

To convert euros back to dollars, you need to divide by the exchange rate. Thus the function is \(C_{2}(r) = \frac{r}{0.749}\).
05

Evaluate the function at specific values

Using the function \(C_{2}(r) = \frac{r}{0.749}\): \1. \(C_{2}(1) = \frac{1}{0.749} ≈ 1.335\). \2. \(C_{2}(100) = \frac{100}{0.749} ≈ 133.51\).
06

Show that the functions are inverses

To show that \(C_{1}\) and \(C_{2}\) are inverses, we need to show that \(C_{2}(C_{1}(d)) = d\) and \(C_{1}(C_{2}(r)) = r\): \1. \(C_{2}(C_{1}(d)) = C_{2}(0.749d) = \frac{0.749d}{0.749} = d\). \2. \(C_{1}(C_{2}(r)) = C_{1}(\frac{r}{0.749}) = 0.749 \times \frac{r}{0.749} = r\). Thus, \(C_{1}\) and \(C_{2}\) are inverses of each other.
07

Explain why the conversion formulas in Exercise 8 are not inverses

For the Canadian and U.S. dollar conversions described in Exercise 8, the two formulas are not inverses because the conversion rates likely change over time or the given exchange rates aren't reciprocal. For instance, if different rates were used for converting U.S. dollars to Canadian dollars and vice versa, the functions wouldn't be perfect inverses.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inverse Functions
When working with currency conversions, inverse functions play a crucial role. An inverse function essentially 'reverses' another function. If you have a function that converts dollars to euros, the inverse will convert euros back to dollars, and vice versa.
To show that two functions are inverses of each other, you must demonstrate that applying one function and then the other returns the original value. Mathematically, this means, for functions \( f \) and \( g \), they are inverses if:
  • \f{ f(g(x)) = x }
  • \f{ g(f(x)) = x }

In the exercise, the conversion from dollars to euros is given by \( C_1(d) = 0.749d \). Its inverse, converting euros back to dollars, is \( C_2(r) = \frac{r}{0.749} \).
By evaluating:
  • \f{ C_2(C_1(d)) = C_2(0.749d) = \frac{0.749d}{0.749} = d }
  • \f{ C_1(C_2(r)) = C_1\left(\frac{r}{0.749}\right) = 0.749 \times \frac{r}{0.749} = r }

These calculations confirm that \( C_1 \) and \( C_2 \) are indeed inverse functions.
Exchange Rates
Exchange rates indicate how much of one currency you can exchange for another. It's a crucial concept in international finance, travel, and trade. In the problem, the exchange rate from U.S. dollars to euros is given as 0.749. This means you can trade 1 U.S. dollar for 0.749 euros.
Exchange rates fluctuate due to various factors:
  • Market demand and supply
  • Economic indicators
  • Political stability
  • Interest rates

Understanding these shifts helps in making informed decisions about currency conversions. For example, if the exchange rate changes and 1 U.S. dollar equals 0.8 euros, the value of the U.S. dollar has increased relative to the euro.
Using the current exchange rate in our example:
  • \( C_1(d) = 0.749d \) converts dollars to euros.
  • \( C_2(r) = \frac{r}{0.749} \) converts euros back to dollars.

Knowing the exchange rate allows you to construct these conversion functions and use them for practical computations.
Function Evaluation
Function evaluation is the process of substituting a specific value for the variable in a function and then performing the operations defined by the function. This is a fundamental concept in mathematics that applies to various real-world scenarios, including currency conversion.
For example, given the function \( C_1(d) = 0.749d \), to find out how many euros 25 dollars would convert to, you substitute 25 for \(d\):
\( C_1(25) = 0.749 \times 25 = 18.725 \text{ euros} \)
Similarly, for the inverse function \( C_2(r) = \frac{r}{0.749} \), to find out how many dollars 100 euros would convert to, you substitute 100 for \( r \):
\( C_2(100) = \frac{100}{0.749} \approx 133.51 \text{ dollars} \)
By evaluating these functions at specific values, you can solve real-life problems easily. Function evaluation provides clarity and precision in applying mathematical functions to everyday tasks, such as financial planning and currency exchange.

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Most popular questions from this chapter

Find the equation of the graph of a parabola that has the following properties: \(\bullet\) The \(x\) -intercepts of the graph are at (2,0) and \((3,0),\) and \(\bullet\) The parabola is the graph of \(y=x^{2}\) vertically stretched by a factor of 4 .

Let \((h, k)\) be the coordinates of the vertex of a parabola. Then \(h\) equals the average of the two real zeros of the function (if they exist). For each of the following use this to find \(h,\) and then put the equations into the vertex form, \(y=a(x-h)^{2}+k\) a. A parabola with equation \(y=x^{2}+2 x-8\) b. A parabola with equation \(y=-x^{2}-3 x+4\)

For each part, draw a rough sketch of a graph of a function of the type \(f(x)=a x^{2}+b x+c\) a. Where \(a>0, c>0,\) and the function has no real zeros. b. Where \(a<0, c>0,\) and the function has two real zeros. c. Where \(a \geq 0\) and the function has one real zero.

(Graphing program optional) a. Write each of the following functions in both the \(a-b-c\) and the \(a-h-k\) forms. Is one form easier than the other for finding the vertex? The \(x\) - and \(y\) -intercepts? \(y_{1}=2 x^{2}-3 x-20 \quad y_{3}=3 x^{2}+6 x+3\) \(y_{2}=-2(x-1)^{2}-3 \quad y_{4}=-(2 x+4)(x-3)\) b. Find the vertex and \(x\) - and \(y\) -intercepts and construct a graph by hand for each function in part (a). If you have access to a graphing program, check your work.

A quadratic function has two complex roots, \(r_{1}=1+i\) and \(r_{2}=1-i\). Use the Factor Theorem to find the equation of this quadratic, assuming \(a=1\), and then put it into standard form.

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