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a. \(B\) is inversely proportional to \(x^{4}\). What is the effect on \(B\) of doubling \(x\) ? b. \(Z\) is inversely proportional to \(x^{p}\), where \(p\) is a positive integer. What is the effect on \(Z\) of doubling \(x\) ?

Short Answer

Expert verified
a. B is reduced to \(\frac{1}{16}\) of its value. b. Z is reduced to \(\frac{1}{2^p}\) of its value.

Step by step solution

01

Understanding inverse proportionality

If a variable is inversely proportional to another variable, it means that as one variable increases, the other decreases in such a way that their product remains constant.
02

(Part a): Express the relationship mathematically

Given that B is inversely proportional to \(x^4\), we can write: \[ B = \frac{k}{x^4} \] where k is a constant of proportionality.
03

(Part a): Examine the effect of doubling x

If x is doubled, let the new value of x be 2x. Substitute 2x into the equation: \[ B_{new} = \frac{k}{(2x)^4} = \frac{k}{16x^4} \] This shows that B is now divided by 16.
04

(Part a): Conclude the effect on B

When x is doubled, B is reduced to \(\frac{1}{16}\) of its original value.
05

(Part b): Express the relationship mathematically

Given that Z is inversely proportional to \(x^p\), we can write: \[ Z = \frac{k}{x^p} \] where k is a constant of proportionality.
06

(Part b): Examine the effect of doubling x

If x is doubled, let the new value of x be 2x. Substitute 2x into the equation: \[ Z_{new} = \frac{k}{(2x)^p} = \frac{k}{2^p \cdot x^p} \] This shows that Z is now divided by \(2^p\).
07

(Part b): Conclude the effect on Z

When x is doubled, Z is reduced to \(\frac{1}{2^p}\) of its original value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

inverse variation
Inverse variation is an important concept in mathematics, often encountered in various fields such as physics, economics, and engineering. Inverse variation describes a relationship where the product of two variables is constant. This means that as one variable increases, the other decreases proportionally to keep their product the same. This relationship is expressed mathematically as: \[ y = \frac{k}{x} \] where \(k\) is a constant. In the given exercise, \(B\) and \(Z\) are inversely proportional to \(x^4\) and \(x^p\) respectively. Understanding inverse variation helps predict how changes in one variable affect another. When \(x\) is doubled, because \(B\) and \(Z\) are in inverse relationships with powers of \(x\), these variables respond by being reduced by a certain factor.
mathematical relationships
Mathematical relationships are fundamental to understanding numerous concepts across different domains. They describe how one quantity changes with respect to another. The relationship can be linear, quadratic, exponential, or, as in this exercise, inverse. Inverse relationships specifically denote situations where one variable increases while the other decreases.
For example:
  • In part (a), \(B\) is inversely proportional to \(x^4\).
  • In part (b), \(Z\) is inversely proportional to \(x^p\), where \(p\) is any positive integer.
By understanding these relationships, we can determine how changing one variable affects another. Doubling \(x\) impacts \(B\) and \(Z\) differently based on their particular inverse relationship expressions.
constant of proportionality
The constant of proportionality is a key concept that links variables in proportional relationships. In inverse relationships, this constant remains unchanged even when variables vary. It represents the fixed product of the two variables. In our examples:
  • For \(B\): \( B = \frac{k}{x^4} \)
  • For \(Z\): \( Z = \frac{k}{x^p} \)
Here, \(k\) is the constant of proportionality. When \(x\) is doubled, the new equations become:
  • \( B_{new} = \frac{k}{(2x)^4} = \frac{k}{16x^4} \) for \(B\)
  • \( Z_{new} = \frac{k}{(2x)^p} = \frac{k}{2^p \cdot x^p} \) for \(Z\)
This demonstrates that \(k\) remains constant, but \(B\) and \(Z\) are adjusted by other factors \(16\) and \(2^p\) respectively, due to the change in \(x\). Understanding this helps in predicting how the variables interdependently adjust.

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Most popular questions from this chapter

Given \(h(x)=0.5 x^{2}\) a. Calculate \(h(2)\) and compare this value with \(h(6)\). b. Calculate \(h(5)\) and compare this value with \(h(15)\). c. What happens to the value of \(h(x)\) if \(x\) triples in value? d. What happens to the value of \(h(x)\) if \(x\) is divided by \(3 ?\)

Construct formulas to represent the following relationships. a. The distance, \(d\), traveled by a falling object is directly proportional to the square of the time, \(t\), traveled. b. The energy, \(E,\) released is directly proportional to the mass, \(m,\) of the object and the speed of light, \(c,\) squared. c. The area, \(A,\) of a triangle is directly proportional to its base, \(b,\) and height, \(h\). d. The reaction rate, \(R,\) is directly proportional to the concentration of oxygen, \(\left[\mathrm{O}_{2}\right],\) and the square of the concentration of nitric oxide, [NO]. e. When you drop a small sphere into a dense fluid such as oil, it eventually acquires a constant velocity, \(v,\) that is directly proportional to the square of its radius, \(r\)

(Graphing program required.) Determine which of the graphs of the following pairs of functions intersect. If the graphs intersect, find the point or points of intersection. a. \(y=2 x \quad y=4 x^{2}\) d. \(y=x^{-1} \quad y=x^{-2}\) b. \(y=4 x^{2} \quad y=4 x^{3}\) e. \(y=4 x^{-2} \quad y=4 x^{-3}\) c. \(y=x^{-2} \quad y=4 x^{2}\)

a. Assume \(L\) is directly proportional to \(x^{5}\). What is the effect of doubling \(x\) ? b. Assume \(M\) is directly proportional to \(x^{p},\) where \(p\) is a positive integer. What is the effect of doubling \(x\) ?

A graphing program is useful for many of the exercises in this section. Sketch by hand and compare the graphs of the following: $$ \begin{array}{lll} y_{1}=x^{2} & y_{2}=-x^{2} & y_{3}=2 x^{2} \\ y_{4}=-2 x^{2} & y_{5}=\frac{1}{2} x^{2} & y_{6}=-\frac{1}{2} x^{2} \end{array} $$

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