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A graphing program is useful for many of the exercises in this section. Sketch by hand and compare the graphs of the following: $$ \begin{array}{lll} y_{1}=x^{2} & y_{2}=-x^{2} & y_{3}=2 x^{2} \\ y_{4}=-2 x^{2} & y_{5}=\frac{1}{2} x^{2} & y_{6}=-\frac{1}{2} x^{2} \end{array} $$

Short Answer

Expert verified
Upward parabolas: \( y_1, y_3, y_5 \), Downward parabolas: \( y_2, y_4, y_6 \), Narrower:\( y_3, y_4 \), Wider: \( y_5, y_6 \).

Step by step solution

01

Identify the given functions

Given functions are: 1. \( y_1 = x^2 \)2. \( y_2 = -x^2 \)3. \( y_3 = 2x^2 \)4. \( y_4 = -2x^2 \)5. \( y_5 = \frac{1}{2}x^2 \)6. \( y_6 = -\frac{1}{2}x^2 \)
02

Sketch \( y_1 = x^2 \)

Draw a parabola that opens upwards. This is the basic quadratic function.
03

Sketch \( y_2 = -x^2 \)

Draw a parabola that opens downwards. This is the reflection of \( y_1 = x^2 \) across the x-axis.
04

Sketch \( y_3 = 2x^2 \)

Draw a parabola that opens upwards and is narrower than \( y_1 = x^2 \). The coefficient 2 makes the parabola steeper.
05

Sketch \( y_4 = -2x^2 \)

Draw a parabola that opens downwards and is narrower than \( y_2 = -x^2 \). The coefficient -2 makes the parabola steeper.
06

Sketch \( y_5 = \frac{1}{2}x^2 \)

Draw a parabola that opens upwards and is wider than \( y_1 = x^2 \). The coefficient \( \frac{1}{2} \) makes the parabola broader.
07

Sketch \( y_6 = -\frac{1}{2}x^2 \)

Draw a parabola that opens downwards and is wider than \( y_2 = -x^2 \). The coefficient \( -\frac{1}{2} \) makes the parabola broader.
08

Compare the graphs

Compare the shapes and orientations of all the graphs:- \( y_1 = x^2 \) and \( y_3 = 2x^2 \) are both upward parabolas where \( y_3 \) is narrower.- \( y_1 = x^2 \) and \( y_5 = \frac{1}{2}x^2 \) are both upward parabolas where \( y_5 \) is wider.- \( y_2 = -x^2 \) and \( y_4 = -2x^2 \) are both downward parabolas where \( y_4 \) is narrower.- \( y_2 = -x^2 \) and \( y_6 = -\frac{1}{2}x^2 \) are both downward parabolas where \( y_6 \) is wider.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Parabolas
A parabola is a symmetrical, U-shaped curve that represents the graph of a quadratic function. The general form of a quadratic function is given by the equation \( y = ax^2 + bx + c \). In this exercise, all the quadratic functions have no linear term or constant term, so they simplify to \( y = ax^2 \). The vertex of these parabolas is at the origin (0,0). The direction in which the parabola opens depends on the coefficient \( a \). If \( a \) is positive, the parabola opens upwards, forming a minimum point at the vertex. If \( a \) is negative, it opens downwards, forming a maximum point at the vertex. Parabolas are useful in many fields such as physics, engineering, and finance because they describe naturally occurring phenomena like projectile motion and optimization problems.
Reflection Across the X-Axis
Reflection across the x-axis involves flipping a graph over the x-axis. When we reflect a parabola across the x-axis, its orientation changes from up to down or vice versa. For instance, in our problem:
  • The function \( y_1 = x^2 \) gives an upward-opening parabola.
  • The function \( y_2 = -x^2 \) which reflects \( y_1 \) across the x-axis, results in a downward-opening parabola.
The reflection shows that multiplying the quadratic term by -1 changes the direction in which the graph opens but does not alter the shape or the width of the parabola. This is a crucial concept for understanding the symmetry in quadratic functions.
Coefficient Impact on Graph Shape
The coefficient \( a \) in the quadratic function \( y = ax^2 \) controls the width and the steepness of the parabola. Its absolute value determines whether the parabola will be steeper (narrower) or shallower (wider).
  • For \( y_3 = 2x^2 \), the positive coefficient 2 makes the parabola narrower than the basic parabola \( y_1 = x^2 \).
  • Conversely, for \( y_5 = \frac{1}{2}x^2 \), the coefficient \( \frac{1}{2} \) makes the parabola wider.
  • A negative coefficient, as seen in \( y_4 = -2x^2 \) and \( y_6 = -\frac{1}{2}x^2 \), still affects the width in the same way but inverts the direction of the parabola.
Graphs with larger coefficients open more narrowly because the vertical stretching effect is more pronounced. Meanwhile, graphs with smaller coefficients open more widely due to vertical compression. This is essential in understanding how different quadratic equations can represent various ranges of values.
Graph Comparison
When comparing the graphs of different quadratic functions, we consider both their shape and orientation. Looking at our functions:
  • \( y_1 = x^2 \) is the standard upward-opening parabola, and its negative counterpart, \( y_2 = -x^2 \), opens downward.
  • \( y_3 = 2x^2 \) and \( y_4 = -2x^2 \) are both steeper than \( y_1 = x^2 \) and \( y_2 = -x^2 \), respectively.
  • \( y_5 = \frac{1}{2}x^2 \) and \( y_6 = -\frac{1}{2}x^2 \) are broader than \( y_1 = x^2 \) and \( y_2 = -x^2 \), respectively.
By analyzing these comparisons, one can observe how quadratics with positive coefficients form parabolas that open upward, and those with negative coefficients open downward. Furthermore, larger coefficients lead to narrower graphs, whereas smaller coefficients result in wider graphs. Understanding these differences helps in graphing and solving quadratic equations effectively.

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Most popular questions from this chapter

(Graphing program recommended.) In Exercise 15 we looked at how much a single load (a person's weight) could bend a plank downward by being placed at its midpoint. Now we look at what a continuous load, such as a solid row of books spread evenly along a shelf, can do. A long row of paperback fiction weighs about 10 pounds for each foot of the row. Typical hardbound books weigh about \(20 \mathrm{lb} / \mathrm{ft}\), and oversize hardbounds such as atlases, encyclopedias, and dictionaries weigh around \(36 \mathrm{lb} / \mathrm{ft}\). The following function is used to model the deflection \(D\) (in inches) of a \(1^{\prime \prime} \times 12^{\prime \prime}\) common pine board spanning a length of \(L\) feet carrying a continuous row of books: $$ D=\left(4.87 \cdot 10^{-4}\right) \cdot W \cdot L^{4} $$ where \(W\) is the weight per foot of the type of books along the shelf. This deflection model is quite good for deflections up to 1 inch; beyond that the fourth power causes the deflection value to increase very rapidly into unrealistic numbers. a. How much deflection does the formula predict for a shelf span of 30 inches with oversize books? Would you recommend a stronger, thicker shelf? b. Plot \(D_{\text {hardbound }}, D_{\text {paperback }},\) and \(D_{\text {oversize }}\) on the same graph. Put \(L\) on the horizontal axis with values up to 4 feet. c. For each kind of book identify what length, \(L,\) will cause a deflection of 0.5 inch in a \(1^{\prime \prime} \times 12^{\prime \prime}\) pine shelf.

Solve the following formulas for the indicated variable. a. \(V=l w h,\) solve for \(l\) b. \(A=\frac{h b}{2},\) solve for \(b\) c. \(P=2 l+2 w\), solve for \(w\) d. \(S=2 x^{2}+4 x h,\) solve for \(h\)

A cube of edge length \(x\) has a surface area \(S(x)=6 x^{2}\) and a volume \(V(x)=x^{3}\). We constructed the function \(R(x)=\frac{S(x)}{V(x)}=\frac{6 x^{2}}{x^{3}}=\frac{6}{x} .\) Consider \(\mathrm{R}(\mathrm{x})\) as an abstract function. What is the domain? Construct a small table of values, including negative values of \(\mathrm{x},\) and plot the graph. Describe what happens to \(\mathrm{R}(\mathrm{x})\) when \(\mathrm{x}\) is positive and \(x \rightarrow 0\). What happens to \(\mathrm{R}(\mathrm{x})\) when \(\mathrm{x}\) is negative and \(x \rightarrow 0 ?\)

a. Construct an equation to represent a relationship where w is directly proportional to both \(y\) and \(z\) and inversely proportional to the square of \(x\). b. Assume that \(w=10\) when \(y=12, z=15,\) and \(x=6 .\) Find \(k,\) the constant of proportionality. c. Using your equation from part (b), find \(x\) when \(w=2\), \(y=5,\) and \(z=6\)

a. Which eventually dominates, \(y=(1.001)^{x}\) or \(y=x^{1000} ?\) b. As the independent variable approaches \(+\infty\), which function eventually approaches zero faster, an exponential decay function or a power function with negative integer exponent?

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