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The price of a home in Medford was \(\$ 100,000\) in 1985 and rose to \(\$ 200,000\) in 2005 . a. Create two models, \(f(t)\) assuming linear growth and \(g(t)\) assuming exponential growth, where \(t=\) number of years after \(1985 .\) b. Fill in the following table representing linear growth and exponential growth for \(t\) years after \(1985 .\) c. Which model do you think is more realistic?

Short Answer

Expert verified
Linear model: \(f(t) = 100,000 + 5,000t\). Exponential model: \(g(t) = 100,000 \times 1.03526^t\). The exponential model is more realistic due to compounded growth factors.

Step by step solution

01

- Define the variable

Let \(t\) represent the number of years after 1985.
02

- Determine linear growth model

In a linear growth model, the price increases by a constant amount each year. Given the home price was \(\(100,000)\) in 1985 and \(\)200,000)\) in 2005, calculate the yearly increase. \[ \text{Yearly Increase} = \frac{200,000 - 100,000}{2005 - 1985} = \frac{100,000}{20} = 5,000 \] The linear growth model can be formulated as \(f(t) = 100,000 + 5,000t\).
03

- Determine exponential growth model

In an exponential growth model, the price increases by a certain percentage each year. Use the general formula for exponential growth: \[ g(t) = 100,000 \times (1 + r)^t \] where \(r\) is the growth rate. Given \(g(20) = 200,000\) when \(t = 20\), solve for \(r\): \[ 200,000 = 100,000 \times (1 + r)^{20} \] \[ 2 = (1 + r)^{20} \] Taking the 20th root of both sides: \[ 1 + r = 2^{\frac{1}{20}} \] \[ 1 + r \approx 1.03526 \] \[ r \approx 0.03526 \] The exponential growth model is \(g(t) = 100,000 \times 1.03526^t\).
04

- Fill in the table

Use the models derived to fill in the table for specific values of \(t\). For linear growth: \[ f(t) = 100,000 + 5,000t \] For exponential growth: \[ g(t) = 100,000 \times 1.03526^t \] Fill in the table for selected values of \(t\) (e.g., 0, 5, 10, 15, 20).
05

- Comparison and conclusion

Compare the values obtained from linear and exponential models. Consider factors like consistent rate vs. increasing rate of growth to determine which model is more realistic. Typically, housing prices are influenced by compounded factors, making the exponential model more realistic.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Growth
Linear growth occurs when a quantity increases by the same fixed amount each period. This type of growth can be represented using a straight line equation, which makes it quite straightforward to analyze and predict outcomes. In our exercise, the home price increased from \(\$100,000\) in 1985 to \(\$200,000\) in 2005, a span of 20 years. To find the yearly increase, we apply the formula: \[ \text{Yearly Increase} = \frac{200,000 - 100,000}{2005 - 1985} = 5,000 \] This means the home's price increased by \(\$5,000\) each year. Thus, the linear growth model is: \[ f(t) = 100,000 + 5,000t \] where \(t\) represents the number of years after 1985. So at \(t = 10\) years (1995), the home price would be \(f(10) = 100,000 + 5,000 \times 10 = 150,000\). This simple relationship helps to easily predict future values.
Exponential Growth
Exponential growth occurs when the rate of increase is proportional to the current value, leading to growth that accelerates over time. It can be described with the equation: \[ g(t) = P \times (1 + r)^t \] where \(P\) is the initial amount, \(r\) is the growth rate, and \(t\) is time. For the home price, given \( g(20) = 200,000 \) and \( P = 100,000 \), we need to find \( r \). By solving: \[ 200,000 = 100,000 \times (1 + r)^{20} \] We get: \[ 2 = (1 + r)^{20} \] Taking the 20th root on both sides gives: \[ 1 + r = 2^{ \frac{1}{20} } \approx 1.03526 \] Thus, \( r \approx 0.03526 \) or 3.526\%. The exponential growth model becomes: \[ g(t) = 100,000 \times 1.03526^t \] This model implies the price grows faster over time, as the rate compounds.
Modeling Functions
Modeling functions are mathematical expressions that represent real-world situations. They allow us to predict future behavior based on current data.
In this exercise, we used both linear and exponential models to showcase different types of growth over time.
The linear model \( f(t) = 100,000 + 5,000t \) shows a constant rate of increase, making it easy to predict future values. It's useful for scenarios where changes are consistent and predictable.
The exponential model \( g(t) = 100,000 \times 1.03526^t \) captures compounding growth, which is more realistic for many real-world phenomena, like population growth, inflation, and, in our case, housing prices. Exponential growth reflects how percentages can create larger increments over time.
These models highlight the importance of understanding different types of growth and choosing the appropriate one to make informed predictions.

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