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Represents an exponential function. Construct that function and then identify the corresponding growth or decay rate in percentage form. $$ \begin{array}{ccccc} \hline x & 0 & 1 & 2 & 3 \\ y & 225.00 & 221.63 & 218.30 & 215.03 \\ \hline \end{array} $$

Short Answer

Expert verified
The function is \( y = 225 \times (0.9849)^x \) with a decay rate of 1.51%.

Step by step solution

01

Determine the Initial Value

The initial value of the function is the value of y when x = 0. From the table, when x = 0, y = 225. Therefore, the initial value is 225.
02

Calculate the Base of the Exponential Function

To find the base, use the ratio between consecutive y-values. Consider the ratio between y-values at x = 1 and x = 0: \ \ \ \[ \frac{221.63}{225} = 0.9848 \] Repeat this for x = 2 and x = 1: \[ \frac{218.30}{221.63} = 0.9849 \] And for x = 3 and x = 2: \[ \frac{215.03}{218.30} = 0.985 \] Notice that these ratios are approximately equal, confirming that the base of the exponential function, b, is approximately 0.9849.
03

Construct the Exponential Function

Given the initial value (a) and the base (b), the exponential function can be written as \ \ \ \[ y = 225 \times (0.9849)^x \]
04

Identify Growth or Decay Rate

Since the base of the exponential function (0.9849) is less than 1, it represents exponential decay. The decay rate (r) can be found using the formula: \ \ \ \[ r = (1 - b) \times 100 \] Substituting in the base value: \[ r = (1 - 0.9849) \times 100 \ = 0.0151 \times 100 \ = 1.51\text{%} \] Therefore, the decay rate is 1.51%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

initial value
The concept of 'initial value' in an exponential function is crucial for understanding how the function behaves from the beginning. The initial value is essentially the starting point of the function, representing the value of y when x equals zero. In our example, you can see that when x = 0, the value of y is 225. Thus, the initial value of our function is 225. This value is often denoted by the symbol 'a'. Initial value is important because it sets the stage for how the function will grow or decay moving forward. Anytime you are given a list of x and y values, look for the y-value that corresponds to x = 0 to find your initial value.
base of the exponential function
The base of an exponential function dictates how the function grows or decays. It is represented by the symbol 'b'. To find the base, you need to examine the ratio between consecutive y-values. For our example:
  • When x increases from 0 to 1, we calculate \[ \frac{221.63}{225} = 0.9848 \]
  • When x increases from 1 to 2, we calculate \[ \frac{218.30}{221.63} = 0.9849 \]
  • When x increases from 2 to 3, we calculate \[ \frac{215.03}{218.30} = 0.985 \]

The base values are very close to each other, with an average of 0.9849. This demonstrates how the function’s values decrease by a consistent factor each time x increases by 1. The closer the base is to 1, the slower the rate of change. If the base is less than 1, it represents exponential decay. If it is greater than 1, it represents exponential growth.
growth or decay rate
Growth or decay rate tells you how fast the function's values increase or decrease. It's calculated using the base, 'b', of the exponential function. Since our base is 0.9849, which is less than 1, it indicates decay. The formula to find the decay rate 'r' in percentage form is:
\[ r = (1 - b) \times 100 \]
Plugging in our base value: \[ r = (1 - 0.9849) \times 100 \]
Simplifying this calculation: \[ r = 0.0151 \times 100 = 1.51\text{%} \]
This tells us that the function is decaying at a rate of 1.51% per unit increase in x. Understanding the growth or decay rate is crucial for predicting future values and for applications like population studies, radioactive decay, and financial forecasts.

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Most popular questions from this chapter

Estimate the time it will take an initial quantity to drop to half its value when: a. \(P=3.02(0.998)^{t}\), with \(t\) in years b. \(Q=12(0.75)^{T}\), with \(T\) in decades

National health care expenditures in 2005 were approximately \(\$ 2016\) billion and are expected to increase by a factor of 1.076 per year. In 5 years what would be the predicted expenditures?

(Graphing program recommended.) You have a chance to invest money in a risky investment at \(6 \%\) interest compounded annually. Or you can invest your money in a safe investment at \(3 \%\) interest compounded annually. a. Write an equation that describes the value of your investment after \(n\) years if you invest \(\$ 100\) at \(6 \%\) compounded annually. Plot the function. Estimate how long it would take to double your money. b. Write an equation that describes the value of your investment after \(n\) years if you invest \(\$ 200\) at \(3 \%\) compounded annually. Plot the function on the same grid as in part (a). Estimate the time needed to double your investment. c. Looking at your graph, indicate whether the amount in the first investment in part (a) will ever exceed the amount in the second account in part (b). If so, approximately when?

Represents an exponential function. Construct that function and then identify the corresponding growth or decay rate in percentage form. $$ \begin{array}{ccccc} \hline x & 0 & 1 & 2 & 3 \\ y & 225.00 & 228.38 & 231.80 & 235.28 \\ \hline \end{array} $$

Which of the following exponential functions represent growth and which decay? a. \(N=50 \cdot 2.5^{T}\) b. \(y=264(5 / 2)^{x}\) c. \(R=745(1.001)^{t}\) d. \(g(z)=\left(3 \cdot 10^{5}\right) \cdot(0.8)^{z}\) e. \(f(T)=\left(1.5 \cdot 10^{11}\right) \cdot(0.35)^{T}\) f. \(h(x)=2000\left(\frac{2}{3}\right)^{x}\)

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