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Simplify and express your answer with positive exponents: a. \(\left(x^{-3}\right) \cdot\left(x^{4}\right)\) b. \(\left(x^{-3}\right) \cdot\left(x^{-2}\right)\) c. \(\left(x^{2}\right)^{-3}\) d. \(\left(n^{-2}\right)^{-3}\) e. \(\left(2 n^{-2}\right)^{-3}\) f. \(n^{-4}\left(n^{5}-n^{2}\right)+n^{-3}\left(n-n^{4}\right)\)

Short Answer

Expert verified
a. x, b. \frac{1}{x^5}, c. \frac{1}{x^6}, d. n^6, e. \frac{1}{8}n^6, f. 0

Step by step solution

01

Part (a): Simplify \left( x^{-3} \right) \cdot\left( x^{4} \right)

Use the property of exponents which states that \left( a^{m} \right) \cdot\left( a^{n} \right) = a^{m+n}. Therefore, \( x^{-3} \cdot x^4 = x^{-3+4} = x^1 = x \).
02

Part (b): Simplify \left( x^{-3} \right) \cdot\left( x^{-2} \right)

Again, use the property of exponents: \left( a^{m} \right) \cdot\left( a^{n} \right) = a^{m+n}. Thus, \( x^{-3} \cdot x^{-2} = x^{-3-2} = x^{-5} = \frac{1}{x^5} \).
03

Part (c): Simplify \left( x^{2} \right)^{-3}

Use the property which states \left( a^{m} \right)^{n} = a^{m \cdot n}. Thus, \( \left( x^{2} \right)^{-3} = x^{2 \cdot -3} = x^{-6} = \frac{1}{x^6} \).
04

Part (d): Simplify \left( n^{-2} \right)^{-3}

Use \left( a^{m} \right)^{n} = a^{m \cdot n}. Thus, \( \left( n^{-2} \right)^{-3} = n^{-2 \cdot -3} = n^6 \).
05

Part (e): Simplify \left( 2 n^{-2} \right)^{-3}

Start by breaking down the expression: \( (2 n^{-2})^{-3} = 2^{-3} \cdot (n^{-2})^{-3} \). We already know \( n^{-2 \cdot -3} = n^6 \), so in the end it gives: \( 2^{-3} = \frac{1}{8} \). Therefore, \( (2 n^{-2})^{-3} = \frac{1}{8} n^{6} \).
06

Part (f): Simplify \left( n^{-4} \right) \left( n^{5} - n^{2} \right) + n^{-3} \left( n - n^{4} \right)

Distribute as per the property of exponents: \( n^{-4} n^{5} - n^{-4} n^{2} + n^{-3} n - n^{-3} n^{4} \). Which simplifies to: \( n^{-4+5} - n^{-4+2} + n^{-3+1} - n^{-3+4} = n^{1} - n^{-2} + n^{-2} - n^{1} \). Simplifying further, \( n - \frac{1}{n^{2}} + \frac{1}{n^{2}} - n \) which results in \( n - n = 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponent Rules
Understanding exponent rules is crucial for simplifying expressions. Exponents represent repeated multiplication. The exponent refers to how many times a number (the base) multiplies itself. Here are some useful rules:

1. Product of Powers: \((a^m \times a^n = a^{m+n})\) - You add the exponents when multiplying like bases.
2. Power of a Power: \(( (a^m)^n = a^{m \times n} )\) - You multiply the exponents when raising a power to another power.
3. Power of a Product: \(( (ab)^n = a^n \times b^n )\) - Distribute the exponent to each factor inside the parentheses.
4. Negative Exponents: \((a^{-n} = \frac{1}{a^n})\) - A negative exponent indicates division by that number instead of multiplication.
These rules help simplify complex exponent expressions efficiently and accurately.
Simplifying Expressions
Simplifying expressions involves reducing them to their simplest form using mathematical properties and rules. Follow these steps:

1. Apply exponent rules to combine or manipulate the exponents.
2. Convert negative exponents to positive by using the reciprocal.
3. If necessary, break down any compound terms by distributing exponents.
4. Combine like terms when possible.
Consider the expression \((x^{-3} \times x^{4})\). Using the product of powers rule, \((x^{-3+4} = x^1 = x) \) simplifies directly to \((x)\). This technique allows for consistency and clarity in solving exponential expressions.
Positive Exponents
Positive exponents indicate how many times you multiply the base by itself. They are more intuitive and easier to work with compared to negative exponents. To convert negative exponents to positive exponents, use the reciprocal. For example, \((x^{-3} \) is equivalent to \(\frac{1}{x^3}) \).

Let's look at another example: \((n^{-4} \times (n^5 - n^2))\). After using the distributive property and simplifying: \((n^{-4+5} - n^{-4+2} = n^1 - n^{-2})\), converting \((n^{-2}) \) to positive form gives \((n - \frac{1}{n^2})\). Always aim to express your final answers using positive exponents for consistency.
Distributive Property
The distributive property allows you to simplify expressions that involve both multiplication and addition or subtraction inside parentheses. It states that \((a(b + c) = ab + ac) \). For exponent expressions, distribute the exponent to every term inside.

Step through this example: Given \((n^{-4}(n^5 - n^2) + n^{-3}(n - n^4))\), first distribute each term:
  • For \((n^{-4}(n^5 - n^2))\), key steps include \((n^{-4+5} - n^{-4+2}) \) yielding \((n - n^{-2})\).
  • For \((n^{-3}(n - n^4))\), you get \((n^{-3+1} - n^{-3+4}) \) resulting in \((n^{-2} - n)\).
Simplifying further combines all terms into \((n - n^{-2} + n^{-2} - n = 0)\). The distributive property is a powerful tool in algebra for breaking down and easily solving complex expressions.

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Most popular questions from this chapter

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