/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 A TV signal traveling at the spe... [FREE SOLUTION] | 91Ó°ÊÓ

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A TV signal traveling at the speed of light takes about \(8 \cdot 10^{-5}\) second to travel 15 miles. How long would it take the signal to travel a distance of 3000 miles?

Short Answer

Expert verified
0.016 seconds

Step by step solution

01

- Identify the Speed of the Signal

It's given that the TV signal travels 15 miles in \(8 \times 10^{-5}\) seconds. First, calculate the speed (miles per second) of the TV signal using the formula: \[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \text{Speed} = \frac{15 \text{ miles}}{8 \times 10^{-5} \text{ seconds}} \]
02

- Calculate the Speed

Now, compute the speed of the TV signal with the given values: \[ \text{Speed} = \frac{15}{8 \times 10^{-5}} = \frac{15}{0.00008} = 187,500 \text{ miles/second} \]
03

- Use the Speed to Find Time for 3000 Miles

Using the speed you just found, determine how long it would take for the signal to travel 3000 miles with the formula: \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \text{Time} = \frac{3000 \text{ miles}}{187,500 \text{ miles/second}} \]
04

- Calculate the Time

Now, compute the time using the given values: \[ \text{Time} = \frac{3000}{187,500} = 0.016 \text{ seconds} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Speed of Light
The speed of light in a vacuum is a fundamental constant in physics. It's typically represented as \( c \) and is approximately 299,792,458 meters per second (about 186,282 miles per second). This high-speed characteristic allows us to utilize light in various technologies such as TV signals, radio waves, and even calculating time for astronomical events.

In our exercise, the TV signal is traveling at this incredible speed, making it possible to cover vast distances in a very short amount of time.
Distance Calculation
Calculating distance is a straightforward process when you know the speed and time. The formula used is: \[ \text{Distance} = \text{Speed} \times \text{Time} \] In the given problem, we're determining how far the signal can travel given a set speed over a period of time.

For example, if a TV signal travels at 187,500 miles per second, you can calculate how far it goes in any given time by multiplying its speed by that time interval.

This direct relationship helps in quickly finding how distance varies with speed and time.
Time Calculation
To determine how long it takes to travel a certain distance, we rearrange the distance formula. The time it takes (\text{t}) can be calculated using: \[ \text{Time} = \frac{\text{Distance}}{\text{Speed}} \]
Applying this formula in our problem, we find: \[ \text{Time} = \frac{3000 \text{ miles}}{187,500 \text{ miles/second}} = 0.016 \text{ seconds} \] Thus, it only takes 0.016 seconds for the TV signal to travel 3000 miles.

Breaking down the formula helps in understanding how time, speed, and distance interplay.
Unit Conversion
Often, we need to convert units to match the context of a problem. In the given exercise, the speed of light and distances are in miles, but sometimes you may encounter measurements in different units like meters or kilometers.

To convert between these units, use the following:
  • 1 mile = 1.60934 kilometers
  • 1 kilometer = 0.621371 miles
  • 1 mile = 1609.34 meters
  • 1 meter = 0.000621371 miles

These conversions enable you to adjust the values appropriately for accurate calculations. It's always important to ensure the units match across all parts of the problem before performing any calculations.

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Most popular questions from this chapter

Determine the order-of-magnitude difference in the sizes of the radii for: a. The solar system \(\left(10^{12}\right.\) meters) compared with Earth \(\left(10^{7}\right.\) meters) b. Protons \(\left(10^{-15}\right.\) meter) compared with the Milky Way \(\left(10^{21}\right.\) meters) c. Atoms \(\left(10^{-10}\right.\) meter) compared with neutrons \(\left(10^{-15}\right.\) meter)

Radio waves, sent from a broadcast station and picked up by the antenna of your radio, are a form of electromagnetic (EM) radiation, as are microwaves, X-rays, and visible, infrared, and ultraviolet light. They all travel at the speed of light. Electromagnetic radiation can be thought of as oscillations like the vibrating strings of a violin or guitar or like ocean swells that have crests and troughs. The distance between the crest or peak of one wave and the next is called the wavelength. The number of times a wave crests per minute, or per second for fast-oscillating waves, is called its frequency. Wavelength and frequency are inversely proportional: the longer the wavelength, the lower the frequency, and vice versa-the faster the oscillation, the shorter the wavelength. For radio waves and other \(\mathrm{EM}\), the number of oscillations per second of a wave is measured in hertz, after the German scientist who first demonstrated that electrical waves could transmit information across space. One cycle or oscillation per second equals 1 hertz \((\mathrm{Hz})\). For the following exercise you may want to find an old radio or look on a stereo tuner at the AM and FM radio bands. You may see the notation \(\mathrm{kHz}\) beside the AM band and MHz beside the FM band. AM radio waves oscillate at frequencies measured in the kilohertz range, and FM radio waves oscillate at frequencies measured in the megahertz range. a. The Boston FM rock station WBCN transmits at \(104.1 \mathrm{MHz}\). Write its frequency in hertz using scientific notation. b. The Boston AM radio news station WBZ broadcasts at 1030 \(\mathrm{kHz}\). Write its frequency in hertz using scientific notation. The wavelength \(\lambda\) (Greek lambda) in meters and frequency \(\mu\) (Greek mu) in oscillations per second are related by the formula \(\lambda=\frac{c}{\mu}\) where \(c\) is the speed of light in meters per second. c. Estimate the wavelength of the WBCN FM radio transmission. d. Estimate the wavelength of the WBZ AM radio transmission. e. Compare your answers in parts (c) and (d), using orders of magnitude, with the length of a football field (approximately 100 meters).

a. In 2006 Japan had a population of approximately 127.5 million people and a total land area of about 152.5 thousand square miles. What was the population density (the number of people per square mile)? b. In 2006 the United States had a population of approximately 300 million people and a total land area of about 3620 thousand square miles. What was the population density of the United States? c. Compare the population densities of Japan and the United States.

Change each number into scientific notation, then perform the indicated calculation without a calculator. a. A \(\$ 600,000\) lottery jackpot is divided among 300 people. What are the winnings per person? b. A total of 2500 megawatts are used over 500 hours. What is the rate in watts per hour? c. If there were 6 million births in 30 years, what is the birth rate per year?

The concentration of hydrogen ions in a water solution typically ranges from \(10 \mathrm{M}\) to \(10^{-15} \mathrm{M}\). (One \(\mathrm{M}\) equals \(6.02 \cdot 10^{23}\) particles, such as atoms, ions, molecules, etc., per liter or 1 mole per liter.) Because of this wide range, chemists use a logarithmic scale, called the pH scale, to measure the concentration (see Exercise 12 of Section 4.6 ). The formal definition of \(\mathrm{pH}\) is \(\mathrm{pH}=-\log \left[\mathrm{H}^{+}\right],\) where \(\left[\mathrm{H}^{+}\right]\) denotes the concentration of hydrogen ions. Chemists use the symbol \(\mathrm{H}^{+}\) for hydrogen ions, and the brackets [ ] mean "the concentration of." a. Pure water at \(25^{\circ} \mathrm{C}\) has a hydrogen ion concentration of \(10^{-7} \mathrm{M}\). What is the \(\mathrm{pH} ?\) b. In orange juice, \(\left[\mathrm{H}^{+}\right] \approx 1.4 \cdot 10^{-3} \mathrm{M}\). What is the \(\mathrm{pH}\) ? c. Household ammonia has a pH of about \(11.5 .\) What is its \(\left[\mathrm{H}^{+}\right] ?\) d. Does a higher pH indicate a lower or a higher concentration of hydrogen ions? e. A solution with a \(\mathrm{pH}>7\) is called basic, one with a \(\mathrm{pH}=7\) is called neutral, and one with a \(\mathrm{pH}<7\) is called acidic. Identify pure water, orange juice, and household ammonia as either acidic, neutral, or basic. Then plot their positions on the accompanying scale, which shows both the \(\mathrm{pH}\) and the hydrogen ion concentration.

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