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Suppose a simple random sample of size 50 is selected from a population with \(\sigma=10\) Find the value of the standard error of the mean in each of the following cases (use the finite population correction factor if appropriate) a. The population size is infinite. b. The population size is \(N=50,000\) c. The population size is \(N=5000\) d. The population size is \(N=500\).

Short Answer

Expert verified
a. 1.414 b. 1.414 c. 1.41 d. 1.343

Step by step solution

01

Define the Standard Error of the Mean

The standard error of the mean (SEM) is calculated as \( \text{SEM} = \frac{\sigma}{\sqrt{n}} \), where \( \sigma \) is the population standard deviation and \( n \) is the sample size. If the population is infinite, this formula is directly applied.
02

Calculate SEM for Infinite Population

Given \( \sigma = 10 \) and \( n = 50 \), use the formula: \( \text{SEM} = \frac{10}{\sqrt{50}} \). Compute \( \sqrt{50} \approx 7.071 \), so \( \text{SEM} \approx \frac{10}{7.071} \approx 1.414 \).
03

Define Finite Population Correction (FPC) Factor

The FPC is used when the sample is a significant portion of the population, calculated by \( \sqrt{\frac{N-n}{N-1}} \), where \( N \) is the population size.
04

Calculate SEM for Population Size of 50,000

Since \( N = 50,000 \) is large compared to the sample size \( n = 50 \), the FPC factor \( \sqrt{\frac{50000-50}{50000-1}} \approx 1 \). Thus, the SEM remains approximately 1.414.
05

Calculate SEM for Population Size of 5,000

Apply the FPC: \( \text{FPC} = \sqrt{\frac{5000-50}{5000-1}} \approx \sqrt{\frac{4950}{4999}} \approx 0.997 \). The adjusted SEM is \( 1.414 \times 0.997 \approx 1.41 \).
06

Calculate SEM for Population Size of 500

Apply the FPC: \( \text{FPC} = \sqrt{\frac{500-50}{500-1}} \approx \sqrt{\frac{450}{499}} \approx 0.95 \). The adjusted SEM is \( 1.414 \times 0.95 \approx 1.343 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Finite Population Correction
The finite population correction (FPC) factor is a tool used in statistics to adjust the standard error when working with a sample drawn from a finite population. When the sample size is a significant fraction of the total population, not accounting for this can lead to an overestimation of the standard error. The FPC is calculated using the formula:\[\text{FPC} = \sqrt{\frac{N-n}{N-1}}\]where:- \(N\) is the population size- \(n\) is the sample sizeApplying the FPC results in a corrected standard error of the mean, which is more accurate for finite populations. This adjustment becomes more important as the sample size approaches a significant proportion of the total population size. For instance, if you have a population of 500 and a sample of 50, the FPC will notably reduce the SEM from what would have been calculated assuming an infinite population.
Simple Random Sample
A simple random sample (SRS) is a straightforward method for selecting a sample from a population. In an SRS, every member of the population has an equal chance of being chosen. This randomness ensures that the sample is representative of the whole population, reducing bias. Key characteristics of an SRS include:
  • Equal probability: Each member of the population has the same chance of selection.
  • Independence: The selection of one member does not affect the selection of another.
Using an SRS is crucial in statistical studies because it allows for generalizations about the population from the sample data. It lays the foundation for most statistical methods, ensuring the validity and reliability of conclusions drawn from the sample observations.
Population Standard Deviation
Population standard deviation (denoted as \(\sigma\)) measures the dispersion or spread of a set of data points within a population. It provides insight into how much individual data points deviate from the population mean. The standard deviation is useful in calculating the standard error of the mean (SEM), expressed as:\[\text{SEM} = \frac{\sigma}{\sqrt{n}}\]Here, \(\sigma\) is essential as it determines how much variability to expect in the sample mean estimates if we draw multiple samples from the population. A larger \(\sigma\) indicates more variability and thus a larger SEM, implying that the sample means will have more fluctuation. Conversely, a smaller \(\sigma\) suggests more compact data points around the mean, resulting in a smaller SEM.
Sample Size
Sample size, denoted by \(n\), is the number of individual observations or data points collected from the population. It plays a crucial role in determining the accuracy and precision of statistical estimates. The choice of sample size directly affects the standard error of the mean (SEM), as demonstrated in the formula:\[\text{SEM} = \frac{\sigma}{\sqrt{n}}\]A larger sample size reduces the SEM, reflecting increased precision in the estimate of the population mean. When planning a study, it is important to choose a sample size that adequately represents the population while also remaining practical in terms of resources.Sample size is particularly significant when applying the finite population correction factor: as the sample size grows relative to the population size, the need for FPC grows. This relation emphasizes the balancing act between sample size, resource allocation, and statistical significance.

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Most popular questions from this chapter

A population proportion is \(.40 .\) A simple random sample of size 200 will be taken and the sample proportion \(\bar{p}\) will be used to estimate the population proportion. a. What is the probability that the sample proportion will be within ±.03 of the population proportion? b. What is the probability that the sample proportion will be within ±.05 of the population proportion?

Indicate which of the following situations involve sampling from a finite population and which involve sampling from an infinite population. In cases where the sampled population is finite, describe how you would construct a frame. a. \(\quad\) Obtain a sample of licensed drivers in the state of New York. b. Obtain a sample of boxes of cereal produced by the Breakfast Choice company. c. Obtain a sample of cars crossing the Golden Gate Bridge on a typical weekday. d. Obtain a sample of students in a statistics course at Indiana University. e. Obtain a sample of the orders that are processed by a mail-order firm.

Consider a finite population with five elements labeled \(\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D},\) and \(\mathrm{E}\). Ten possible \(\operatorname{sim}\) ple random samples of size 2 can be selected. a. List the 10 samples beginning with \(\mathrm{AB}, \mathrm{AC},\) and so on. b. Using simple random sampling, what is the probability that each sample of size 2 is selected? c. Assume random number 1 corresponds to A, random number 2 corresponds to B, and so on. List the simple random sample of size 2 that will be selected by using the random digits 8057532

In 2008 the Better Business Bureau settled \(75 \%\) of complaints it received (USA Today, March 2,2009 ). Suppose you have been hired by the Better Business Bureau to investigate the complaints it received this year involving new car dealers. You plan to select a sample of new car dealer complaints to estimate the proportion of complaints the Better Business Bureau is able to settle. Assume the population proportion of complaints settled for new car dealers is \(.75,\) the same as the overall proportion of complaints settled in 2008 a. Suppose you select a sample of 450 complaints involving new car dealers. Show the sampling distribution of \(\bar{p}\) b. Based upon a sample of 450 complaints, what is the probability that the sample proportion will be within .04 of the population proportion? c. Suppose you select a sample of 200 complaints involving new car dealers. Show the sampling distribution of \(\bar{p}\) d. Based upon the smaller sample of only 200 complaints, what is the probability that the sample proportion will be within .04 of the population proportion? e. As measured by the increase in probability, how much do you gain in precision by taking the larger sample in part (b)?

The Food Marketing Institute shows that \(17 \%\) of households spend more than \(\$ 100\) per week on groceries. Assume the population proportion is \(p=.17\) and a simple random sample of 800 households will be selected from the population. a. Show the sampling distribution of \(\bar{p}\), the sample proportion of households spending more than \(\$ 100\) per week on groceries. b. What is the probability that the sample proportion will be within ±.02 of the population proportion? c. Answer part (b) for a sample of 1600 households.

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