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Consider a finite population with five elements labeled \(\mathrm{A}, \mathrm{B}, \mathrm{C}, \mathrm{D},\) and \(\mathrm{E}\). Ten possible \(\operatorname{sim}\) ple random samples of size 2 can be selected. a. List the 10 samples beginning with \(\mathrm{AB}, \mathrm{AC},\) and so on. b. Using simple random sampling, what is the probability that each sample of size 2 is selected? c. Assume random number 1 corresponds to A, random number 2 corresponds to B, and so on. List the simple random sample of size 2 that will be selected by using the random digits 8057532

Short Answer

Expert verified
10 samples: AB, AC, AD, AE, BC, BD, BE, CD, CE, DE. Probability per sample: \( \frac{1}{10} \). Random sample: DE.

Step by step solution

01

List All Possible Samples

For a sample of size 2 selected from a population of 5 elements (A, B, C, D, E), we can list all the possible samples without repetition. The samples starting with 'AB' are: AB, AC, AD, AE, BC, BD, BE, CD, CE, and DE. We ensure that each pair is considered only once.
02

Calculate Probability for Each Sample

The number of ways to choose 2 elements from 5 is given by the combination formula \( \binom{n}{k} \), where \( n \) is the population size, and \( k \) is the sample size. Here, \( \binom{5}{2} = 10 \). Since the sampling is random and each sample has an equal chance, the probability of selecting any one sample is \( \frac{1}{10} \).
03

Assign Random Numbers to Elements

We associate each population element with a unique random number: A -> 1, B -> 2, C -> 3, D -> 4, E -> 5. This set-up helps us map the digits from the random sequence to elements.
04

Select Samples Using Random Digits

Given the random sequence of digits 8057532, we select pairs based on unique, consecutive non-repeating digits. Starting with 80 (ignored as it exceeds the limit 1-5), move to 57 -> DE, 53 -> EC, 32 -> CB (since we ignore repeats like using 5 again within a set). The random sample size 2 by this sequence first yields 'DE'.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Finite Population
A finite population is a set of distinct elements or items that can be counted. When working with populations in statistics, knowing whether it's finite or infinite helps in choosing the correct sampling methods.
In the exercise, the finite population consists of five distinct labels: A, B, C, D, and E. This small number makes it feasible to list all possible outcomes when choosing samples.
For finite populations, we can determine the exact sample space, in this case by listing every possible pair from the set. With a finite population, it is easier to apply statistical formulas, like the combination formula, to determine possibilities and probabilities.
Combination Formula
The combination formula is useful for determining how many ways we can choose a subset from a larger set without considering the order of selection. This formula is especially helpful when dealing with finite populations.
The formula for combinations is expressed as \(\binom{n}{k}\), where \(n\) is the total number of elements in the population, and \(k\) is the number of elements we want in each sample. By applying this to our finite population of 5 elements and determining all combinations of 2, we calculate \(\binom{5}{2} = 10\).
This tells us there are 10 unique combinations of samples of size 2 that can be taken from this population. Importantly, this calculation confirms the process and provides the number needed to compute probabilities.
Probability of Selection
Probability measures how likely an event is to occur. In simple random sampling, every sample should have an equal chance of being selected.
In our exercise, we have 10 possible samples, each is equally likely to be selected. This is due to the nature of simple random sampling, which ensures each sample of the same size has the same probability.
The probability of selecting any one of these 10 samples is calculated as \(\frac{1}{10}\) or 0.1. So, each pairing of elements A to E as a group of two has this probability of being chosen in this method.

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Most popular questions from this chapter

In 2008 the Better Business Bureau settled \(75 \%\) of complaints it received (USA Today, March 2,2009 ). Suppose you have been hired by the Better Business Bureau to investigate the complaints it received this year involving new car dealers. You plan to select a sample of new car dealer complaints to estimate the proportion of complaints the Better Business Bureau is able to settle. Assume the population proportion of complaints settled for new car dealers is \(.75,\) the same as the overall proportion of complaints settled in 2008 a. Suppose you select a sample of 450 complaints involving new car dealers. Show the sampling distribution of \(\bar{p}\) b. Based upon a sample of 450 complaints, what is the probability that the sample proportion will be within .04 of the population proportion? c. Suppose you select a sample of 200 complaints involving new car dealers. Show the sampling distribution of \(\bar{p}\) d. Based upon the smaller sample of only 200 complaints, what is the probability that the sample proportion will be within .04 of the population proportion? e. As measured by the increase in probability, how much do you gain in precision by taking the larger sample in part (b)?

A population has a mean of 200 and a standard deviation of \(50 .\) A simple random sample of size 100 will be taken and the sample mean \(\bar{x}\) will be used to estimate the population mean a. What is the expected value of \(\bar{x} ?\) b. What is the standard deviation of \(\bar{x} ?\) c. Show the sampling distribution of \(\bar{x}\). d. What does the sampling distribution of \(\bar{x}\) show?

Suppose a simple random sample of size 50 is selected from a population with \(\sigma=10\) Find the value of the standard error of the mean in each of the following cases (use the finite population correction factor if appropriate) a. The population size is infinite. b. The population size is \(N=50,000\) c. The population size is \(N=5000\) d. The population size is \(N=500\).

A market research firm conducts telephone surveys with a \(40 \%\) historical response rate. What is the probability that in a new sample of 400 telephone numbers, at least 150 individuals will cooperate and respond to the questions? In other words, what is the probability that the sample proportion will be at least \(150 / 400=.375 ?\)

About \(28 \%\) of private companies are owned by women (The Cincinnati Enquirer, January 26,2006)\(.\) Answer the following questions based on a sample of 240 private companies. a. Show the sampling distribution of \(\bar{p},\) the sample proportion of companies that are owned by women. b. What is the probability that the sample proportion will be within ±.04 of the population proportion? c. What is the probability that the sample proportion will be within ±.02 of the population proportion?

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