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Collina's Italian Café in Houston, Texas, advertises that carryout orders take about 25 minutes (Collina's website, February 27,2008 ). Assume that the time required for a carryout order to be ready for customer pickup has an exponential distribution with a mean of 25 minutes. a. What is the probability than a carryout order will be ready within 20 minutes? b. If a customer arrives 30 minutes after placing an order, what is the probability that the order will not be ready? c. \(\quad\) A particular customer lives 15 minutes from Collina's Italian Café. If the customer places a telephone order at 5: 20 P.M., what is the probability that the customer can drive to the café, pick up the order, and return home by 6: 00 p.n.?

Short Answer

Expert verified
a. 0.5507; b. 0.3012; c. 0.3297.

Step by step solution

01

Understanding the Exponential Distribution

The problem states that the time to prepare a carryout order follows an exponential distribution with a mean of 25 minutes. The exponential distribution is defined by a rate parameter \( \lambda \) which is the reciprocal of the mean: \( \lambda = \frac{1}{25} = 0.04 \text{ per minute} \). The probability density function for an exponential distribution is given by \( f(t) = \lambda e^{-\lambda t} \).
02

Calculate Probability for Less Than 20 Minutes

To find the probability that a carryout order is ready within 20 minutes, we use the cumulative distribution function (CDF) of the exponential distribution: \( P(T \leq 20) = 1 - e^{-\lambda \times 20} \). Substitute \( \lambda = 0.04 \):\[ P(T \leq 20) = 1 - e^{-0.04 \times 20} = 1 - e^{-0.8} \approx 0.5507. \]
03

Calculate Probability for Order Not Ready After 30 Minutes

To find the probability that the order is not ready after 30 minutes, we calculate \( P(T > 30) = 1 - P(T \leq 30) = e^{-\lambda \times 30} \). Substitute \( \lambda = 0.04 \):\[ P(T > 30) = e^{-0.04 \times 30} = e^{-1.2} \approx 0.3012. \]
04

Calculate Probability for Round Trip Within 40 Minutes

If a customer has 40 minutes to complete a round trip (15 minutes either way and assuming the order time takes the rest), we need to find \( P(T \leq 10) \), since they will spend 30 minutes traveling. Calculate using the CDF: \( P(T \leq 10) = 1 - e^{-\lambda \times 10} \). Using \( \lambda = 0.04 \):\[ P(T \leq 10) = 1 - e^{-0.04 \times 10} = 1 - e^{-0.4} \approx 0.3297. \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculations
In the context of the exponential distribution, probability calculations are essential to make predictions about events and their likelihood. To find probabilities, we often use the cumulative distribution function (CDF), which helps determine the probability of a random variable being less than or equal to a certain value.

For instance, to find the probability that a carryout order from Collina's Italian Café is ready within 20 minutes, you utilize the formula:
  • The cumulative distribution function is computed as: \( P(T \leq t) = 1 - e^{-\lambda t} \)
  • Where \( \lambda \) is the rate parameter (reciprocal of the mean).
  • Substitute \( \lambda = 0.04 \) and time \( t = 20 \) to find \( P(T \leq 20) \).
This results in a probability of approximately 0.5507, meaning there is a 55.07% chance that an order is ready in under 20 minutes.

Probability calculations are foundational in predicting outcomes and assessing risks in a variety of fields, from business to engineering and beyond.
Statistical Distribution
Understanding statistical distributions is crucial in data analysis and decision-making. The exponential distribution, in particular, describes the time until an event occurs, assuming a constant rate of process. It's often used to model scenarios like waiting times, such as the time taken for a carryout order at a café.

This distribution is characterized by its rate parameter \( \lambda \), which is derived from the inverse of the mean. For Collina's Italian Café, where the average time is 25 minutes, \( \lambda = \frac{1}{25} = 0.04 \text{ per minute} \). The probability density function (PDF) that describes the distribution is:
  • \( f(t) = \lambda e^{-\lambda t} \)
This equation expresses the likelihood of the time \( t \) to prepare an order being a specific value. The exponential distribution helps predict occurrences of random events over time, making it a valuable tool in statistics for modeling various processes.

This statistical distribution is not only limited to carryout order times but is also applicable in areas like reliability engineering, to model the lifespan of products.
Cumulative Distribution Function
The cumulative distribution function (CDF) is a powerful tool in probability and statistics, helping to determine the probability that a random variable takes on a value less than or equal to a given datum. In the context of an exponential distribution, the CDF helps quantify the probability of occurrences before a certain time.

For a customer picking up an order after 30 minutes, understanding \( P(T > 30) \) is key. However, first, compute \( P(T \leq 30) \) using the CDF:
  • \( P(T \leq 30) = 1 - e^{-0.04 \times 30} = 1 - e^{-1.2} \)
  • Thus, to find \( P(T > 30) \), compute \( 1 - P(T \leq 30) \).
The result shows a probability of about 0.3012, indicating a roughly 30.12% chance the order is still not ready after 30 minutes.

The CDF is instrumental in understanding and predicting behavior in processes with inherent randomness, such as wait times in service industries or time taken in manufacturing processes.

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Most popular questions from this chapter

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