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A random variable is normally distributed with a mean of \(\mu=50\) and a standard deviation of \(\sigma=5\) a. Sketch a normal curve for the probability density function. Label the horizontal axis with values of \(35,40,45,50,55,60,\) and \(65 .\) Figure 6.4 shows that the normal curve almost touches the horizontal axis at three standard deviations below and at three standard deviations above the mean (in this case at 35 and 65 ). b. What is the probability that the random variable will assume a value between 45 and \(55 ?\) c. What is the probability that the random variable will assume a value between 40 and \(60 ?\)

Short Answer

Expert verified
b. Approximately 0.6826 c. Approximately 0.9544

Step by step solution

01

Set Up the Normal Distribution Details

The given random variable is normally distributed with mean \( \mu = 50 \) and standard deviation \( \sigma = 5 \). These are the key parameters for analyzing the normal distribution and for further calculations.
02

Sketch the Normal Curve

Draw the bell-shaped normal curve, centering it at the mean, \( \mu = 50 \). On the horizontal axis, mark the values at one, two, and three standard deviations from the mean: 35, 40, 45, 50, 55, 60, and 65. This will help visualize where the range of interest falls with respect to the distribution.
03

Standard Normal Transformation

To find probabilities using the standard normal distribution, convert the given values to \( z \)-scores. Use the formula \( z = \frac{x - \mu}{\sigma} \). For \( x = 45 \): \[ z_{45} = \frac{45 - 50}{5} = -1 \]For \( x = 55 \): \[ z_{55} = \frac{55 - 50}{5} = 1 \]
04

Calculate Probability Between 45 and 55

Using a standard normal distribution table or calculator, find the probability that \( z \) is between \(-1\) and \(1\). This corresponds to:\( P(-1 < z < 1) \). By using standard normal tables, we find:\( P(-1 < z < 1) \approx 0.6826 \).
05

Calculate Z-Scores for 40 and 60

Convert the given values 40 and 60 to \( z \)-scores:For \( x = 40 \):\[ z_{40} = \frac{40 - 50}{5} = -2 \]For \( x = 60 \):\[ z_{60} = \frac{60 - 50}{5} = 2 \]
06

Calculate Probability Between 40 and 60

Find the probability that \( z \) is between \(-2\) and \(2\), using a standard normal distribution table or calculator:\( P(-2 < z < 2) \). From standard normal tables, this probability is:\( P(-2 < z < 2) \approx 0.9544 \).
07

Listing Final Answers for Probabilities

Based on our calculations: b. The probability that the random variable falls between 45 and 55 is approximately 0.6826. c. The probability that the random variable falls between 40 and 60 is approximately 0.9544.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation Explained
Understanding standard deviation in a normal distribution is crucial as it measures the spread of data around the mean. In a normal distribution, most of the data points are clustered around the average. The standard deviation tells you how far the data tends to deviate from the average value. If the standard deviation is small, it means most data points are close to the mean. Conversely, a larger standard deviation indicates a wider spread, with data points scattered further from the mean. When sketching a normal curve, the standard deviation helps outline how the curve will look: the peak is centered at the mean, then symmetrically decreases as we move +1, +2, or +3 standard deviations away from the center. The area under the curve corresponds to probability. Hence, within one standard deviation on either side of the mean, approximately 68% of the data falls; within two, about 95%.
Understanding Probability Calculation
Calculating probability within a normal distribution involves understanding the area under the curve. Probabilities are essentially the likelihood that a random variable, such as test scores or manufacturing weights, falls within a certain range. For instance, if you have a normal distribution curve, calculating the probability of a variable being between two values means finding the area under the curve between those values. This area corresponds to the probability value. Standardization makes calculation easier. We convert the variable to a standard score or z-score, then reference a standard normal distribution table, which tells us the probability of obtaining a z-score within that range. The two examples in the exercise demonstrate this:
  • For the range 45 to 55, the probability is approximately 0.6826, meaning about 68% falls there.
  • For 40 to 60, the probability is approximately 0.9544, indicating 95.44% falls in this range.
Z-scores and Their Significance
Z-scores are a standardized way to express data points relative to the mean of a distribution. They are crucial for comparing values from different normal distributions.A z-score tells you how many standard deviations a particular data point is from the mean. For example, if a score is one standard deviation away from the mean, its z-score is 1. If it is below the mean by 1 standard deviation, the z-score is -1.In probability calculations, converting raw data to z-scores simplifies finding the probability. It standardizes different scales to a common scale called the standard normal distribution.Using the formula:\[ z = \frac{x - \mu}{\sigma} \]you can convert any data point to a z-score. For instance, if the mean \( \mu = 50 \) and standard deviation \( \sigma = 5 \) in our example, a value of 45 corresponds to a z-score of -1, while a value of 55 corresponds to a z-score of 1. This indicates they're 1 standard deviation away from the mean. The standardized z-scores easily allow us to determine the probability of data points occurring within a particular range.

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Most popular questions from this chapter

According to Salary Wizard, the average base salary for a brand manager in Houston, Texas, is \(\$ 88,592\) and the average base salary for a brand manager in Los Angeles, California, is \(\$ 97,417\) (Salary Wizard website, February 27,2008 ). Assume that salaries are normally distributed, the standard deviation for brand managers in Houston is \(\$ 19,900,\) and the standard deviation for brand managers in Los Angeles is \(\$ 21,800\) a. What is the probability that a brand manager in Houston has a base salary in excess of \(\$ 100,000 ?\) b. What is the probability that a brand manager in Los Angeles has a base salary in excess of \(\$ 100,000 ?\) c. What is the probability that a brand manager in Los Angeles has a base salary of less than \(\$ 75,000 ?\) d. How much would a brand manager in Los Angeles have to make in order to have a higher salary than \(99 \%\) of the brand managers in Houston?

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