/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 The average stock price for comp... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The average stock price for companies making up the S\&P 500 is \(\$ 30,\) and the standard deviation is \(\$ 8.20\) (Business Week, Special Annual Issue, Spring 2003 ). Assume the stock prices are normally distributed. a. What is the probability that a company will have a stock price of at least \(\$ 40 ?\) b. What is the probability that a company will have a stock price no higher than \(\$ 20 ?\) c. How high does a stock price have to be to put a company in the top \(10 \% ?\)

Short Answer

Expert verified
a: 0.1112, b: 0.1112, c: \(\$40.50\).

Step by step solution

01

Understanding the Normal Distribution

The stock prices are normally distributed with a mean \(\mu = 30\) and a standard deviation \(\sigma = 8.2\). This means the data follows a bell-shaped curve where most values cluster around the mean.
02

Calculating Z-score for Part a

To find the probability that a stock price is at least \(\$40\), we need to calculate the Z-score using the formula: \[ Z = \frac{X - \mu}{\sigma} \]For \(X = 40\), the Z-score is:\[ Z = \frac{40 - 30}{8.2} \approx 1.22 \]
03

Finding Probability for Part a

The Z-score of 1.22 corresponds to a cumulative probability of approximately 0.8888 from Z-tables. This value represents the probability of having a stock price less than \(\\(40\). To find the probability of at least \(\\)40\):\[ P(X \geq 40) = 1 - P(X < 40) = 1 - 0.8888 = 0.1112 \]
04

Calculating Z-score for Part b

For a stock price no higher than \(\$20\), calculate the Z-score:\[ Z = \frac{20 - 30}{8.2} \approx -1.22 \]
05

Finding Probability for Part b

The Z-score of -1.22 corresponds to a cumulative probability of approximately 0.1112. This means:\[ P(X \leq 20) = 0.1112 \]
06

Determining Stock Price for Top 10% for Part c

To find the stock price at the top 10%, we need the Z-score that corresponds to the 90th percentile since 10% is in the upper tail. This Z-score is approximately 1.28. Using the Z-score formula and solving for \(X\):\[ X = Z \sigma + \mu = 1.28 \times 8.2 + 30 \approx 40.50 \]
07

Conclusion

The probability of having a stock price of at least \(\\(40\) is 0.1112. The probability of a stock price no higher than \(\\)20\) is also 0.1112. A stock price of approximately \(\$40.50\) places a company in the top 10% of the S\&P 500 stock prices.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score Calculation
Z-score calculation is a way to determine how many standard deviations an individual data point is from the mean in a normal distribution. It provides a method to standardize scores on a uniform scale, allowing for comparison of different data points.
The formula used to compute a Z-score is:
  • \( Z = \frac{X - \mu}{\sigma} \)
Where:
  • \( X \) is the individual data point,
  • \( \mu \) is the mean of the distribution, and
  • \( \sigma \) is the standard deviation.
Let's take an example:
Suppose the stock price of a company is \\(40, and we want to calculate the Z-score. If the average stock price is \\)30 and the standard deviation is \\(8.20, we substitute these values into our formula:
  • \( Z = \frac{40 - 30}{8.2} \approx 1.22 \)
A Z-score of 1.22 indicates that a stock price of \\)40 is 1.22 standard deviations above the mean. This standardization helps in knowing where the data point stands concerning the entire data set.
Probability
Probability in the context of a normal distribution tells us how likely it is for a certain event to occur. Each Z-score corresponds to a probability, which represents the likelihood that a randomly selected data point is equal to or less than that Z-score.
Suppose you calculated a Z-score of 1.22 for a stock price of \\(40. This Z-score relates to a cumulative probability of approximately 0.8888 if you're consulting standard Z-tables. This means there is an 88.88% chance that a stock price will be less than \\)40.
Therefore, to find the probability that a stock price is at least \\(40, you subtract this cumulative probability from 1:
  • \( P(X \geq 40) = 1 - 0.8888 = 0.1112 \)
This calculation indicates an 11.12% probability that a company's stock price will be \\)40 or more.
These probability calculations inform decisions and expectations by illuminating how extreme or common a particular observation really is.
Percentile Rank
The percentile rank in a normal distribution shows you what percentage of data points lie below a particular score. Percentiles are practical, especially when comparing scores across different data sets or distributions.
For example, the 90th percentile indicates that a value is higher than 90% of the data points in the distribution.
To find the stock price that places a company in the top 10% of the S&P 500, we utilize the 90th percentile. A Z-score that corresponds to the 90th percentile is about 1.28. Inserting this Z-score back into the Z-score equation helps us solve for the stock price:
  • \( X = Z \times \sigma + \mu = 1.28 \times 8.2 + 30 \approx 40.50 \)
This calculation means that a stock price of approximately \$40.50 is required for a company to be in the top 10% in terms of stock prices. Using percentile ranks thus allows businesses and analysts to understand where they stand within a large, potentially competitive field.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Assume a binomial probability distribution has \(p=.60\) and \(n=200\) a. What are the mean and standard deviation? b. Is this situation one in which binomial probabilities can be approximated by the normal probability distribution? Explain. c. What is the probability of 100 to 110 successes? d. What is the probability of 130 or more successes? e. What is the advantage of using the normal probability distribution to approximate the binomial probabilities? Use part (d) to explain the advantage.

A person must score in the upper \(2 \%\) of the population on an IQ test to qualify for membership in Mensa, the international high-IQ society. If IQ scores are normally distributed with a mean of 100 and a standard deviation of \(15,\) what score must a person have to qualify for Mensa?

A binomial probability distribution has \(p=.20\) and \(n=100\) a. What are the mean and standard deviation? b. Is this situation one in which binomial probabilities can be approximated by the normal probability distribution? Explain. c. What is the probability of exactly 24 successes? d. What is the probability of 18 to 22 successes? e. What is the probability of 15 or fewer successes?

Consider the following exponential probability density function. \\[ f(x)=\frac{1}{8} e^{-x / 8} \quad \text { for } x \geq 0 \\] a. \(\quad\) Find \(P(x \leq 6)\) b. Find \(P(x \leq 4)\) c. \(\quad\) Find \(P(x \geq 6)\) d. Find \(P(4 \leq x \leq 6)\)

The U.S. Bureau of Labor Statistics reports that the average annual expenditure on food and drink for all families is \(\$ 5700\) (Money, December 2003 ). Assume that annual expenditure on food and drink is normally distributed and that the standard deviation is \(\$ 1500\) a. What is the range of expenditures of the \(10 \%\) of families with the lowest annual spending on food and drink? b. What percentage of families spend more than \(\$ 7000\) annually on food and drink? c. What is the range of expenditures for the \(5 \%\) of families with the highest annual spending on food and drink?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.