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91Ó°ÊÓ

A person must score in the upper \(2 \%\) of the population on an IQ test to qualify for membership in Mensa, the international high-IQ society. If IQ scores are normally distributed with a mean of 100 and a standard deviation of \(15,\) what score must a person have to qualify for Mensa?

Short Answer

Expert verified
A person must score approximately 131 on an IQ test to qualify for Mensa.

Step by step solution

01

Understand the Problem

To solve this problem, we need to find the IQ score that places a person in the upper 2% of the population. Since IQ scores are normally distributed, we will use the properties of the normal distribution.
02

Identify Key Values

The mean of the distribution is 100, and the standard deviation is 15. We are looking for the IQ score that corresponds to the 98th percentile (since the top 2% would be above the 98th percentile).
03

Use the Standard Normal Distribution

Convert the desired percentile (98%) into a z-score using a standard normal distribution table or calculator. The z-score for the 98th percentile is approximately 2.05.
04

Apply the Z-Score Formula

Use the z-score formula to find the corresponding IQ score:\[ z = \frac{X - \mu}{\sigma} \]Where \( z = 2.05 \), \( \mu = 100 \), and \( \sigma = 15 \). Calculate to find \( X \), the required IQ score:\[ 2.05 = \frac{X - 100}{15} \].
05

Solve for X

Rearrange the equation to solve for \( X \):\[ X = 2.05 \times 15 + 100 \]Calculate to find:\[ X = 30.75 + 100 = 130.75 \].
06

Interpret the Result

The IQ score required to be in the top 2% of the population and qualify for Mensa membership is approximately 130.75. Typically, we round this to the nearest integer, so 131 is often used.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Percentiles
Percentiles are used to understand the relative position of a data point within a dataset. Imagine lining up all data points from smallest to largest. Each position in this lineup corresponds to a percentile. For example, the 98th percentile means a value is higher than 98% of the other values in the dataset.

In the context of IQ scores, being in the 98th percentile means your score is higher than 98% of the population. Since percentiles indicate relative standing, they are highly useful in educational and psychological assessments to quickly assess how a score compares to others.

With a normally distributed dataset like IQ scores, which spread symmetrically around the mean, percentiles are predictable. This predictability makes it easier to pinpoint exact cutoff scores for benchmarks, such as determining eligibility for Mensa.
Z-score
The Z-score is a statistical measure that tells us how many standard deviations an element is from the mean of a dataset. It's a way of standardizing scores, so we can compare them more easily, even if they were originally from different scales or distributions.

We use the Z-score in relation to the standard normal distribution, where the mean is 0 and the standard deviation is 1. This standardized approach allows for straightforward assessment of where a particular score falls in relation to the overall distribution.
  • Calculation: The formula to calculate a Z-score is \( z = \frac{X - \mu}{\sigma} \), where \( X \) is the data point, \( \mu \) is the mean, and \( \sigma \) is the standard deviation of the dataset.
  • Interpretation: A positive Z-score means the score is above the mean, while a negative Z-score indicates it is below the mean.
In our IQ exercise, using the Z-score of 2.05 for the 98th percentile was crucial to determine the exact IQ score needed to be part of the elite top 2%.
Standard Deviation
Standard deviation is a key concept in statistics that indicates the amount of variation or spread in a set of values. Simply put, it tells us how much individual data points differ from the mean.

A low standard deviation means that the data points are close to the mean, suggesting less variability within the dataset. Meanwhile, a high standard deviation indicates a wide range of values, showing larger variability.
  • Formula: The standard deviation \( \sigma \) is calculated as the square root of the variance. This involves determining the average of the squared deviations from the mean.
  • Use in Normal Distribution: In a normal distribution, about 68% of all data points lie within one standard deviation of the mean, 95% within two, and 99.7% within three standard deviations.
In the context of the given IQ problem, the standard deviation of 15 helps determine how much the IQ scores vary around the mean of 100.
Mean
The mean, often referred to as the "average," is the central value of a dataset. It's calculated by adding up all the numbers and then dividing by the count of numbers. The mean gives us a quick snapshot of the data's central tendency.

While the mean is a pivotal measure for data analysis, in a normal distribution like IQ scores, it also serves as a point of symmetry. The data tends to cluster around the mean, showing where most values are located.
  • Importance: Understanding the mean helps in gauging the general performance or behavior within a domain, like how IQ scores typically center around certain values.
  • Mean in Normal Distribution: The mean essentially cuts the graph of the normal distribution in half, providing a balance with equal data distribution on both sides.
For our Mensa qualification exercise, the mean IQ of 100 serves as the baseline from which we determine how much higher a score needs to be to reach the upper 2% threshold.

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