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Blackjack, or twenty-one as it is frequently called, is a popular gambling game played in Las Vegas casinos. A player is dealt two cards. Face cards (jacks, queens, and kings) and tens have a point value of \(10 .\) Aces have a point value of 1 or \(11 .\) A 52 -card deck contains 16 cards with a point value of 10 (jacks, queens, kings, and tens) and four aces. a. What is the probability that both cards dealt are aces or 10 -point cards? b. What is the probability that both of the cards are aces? c. What is the probability that both of the cards have a point value of \(10 ?\) d. \(A\) blackjack is a 10 -point card and an ace for a value of \(21 .\) Use your answers to parts (a), (b), and (c) to determine the probability that a player is dealt blackjack. (Hint: Part (d) is not a hypergeometric problem. Develop your own logical relationship as to how the hypergeometric probabilities from parts (a), (b), and (c) can be combined to answer this question.)

Short Answer

Expert verified
a) 0.1433, b) 0.0045, c) 0.0905, d) 0.0483

Step by step solution

01

Identify Total Combinations

In a deck of 52 cards, two cards are dealt. The total number of combinations for two cards is \( \binom{52}{2} = \frac{52 \times 51}{2} = 1326 \). This will serve as our denominator when calculating probabilities.
02

Calculate Probability of Both Cards Being Aces or 10-Point Cards

The deck has 16 ten-point cards and 4 aces, totaling 20 such cards. The number of combinations where both cards are either aces or 10-point cards is \( \binom{20}{2} = \frac{20 \times 19}{2} = 190 \). The probability is thus \( \frac{190}{1326} \approx 0.1433 \).
03

Calculate Probability of Both Cards Being Aces

There are 4 aces in the deck. The number of combinations for two aces is \( \binom{4}{2} = \frac{4 \times 3}{2} = 6 \). The probability that both cards are aces is \( \frac{6}{1326} \approx 0.0045 \).
04

Calculate Probability of Both Cards Being 10-Point Cards

There are 16 ten-point cards in the deck. The number of combinations for two ten-point cards is \( \binom{16}{2} = \frac{16 \times 15}{2} = 120 \). The probability is \( \frac{120}{1326} \approx 0.0905 \).
05

Calculate Probability of Being Dealt Blackjack

A blackjack is precisely one ace and one 10-point card. From part (a), we have 190 total combinations of two aces or 10-point cards. Subtract the combinations from part (b) (two aces = 6) and part (c) (two 10-point cards = 120) to get the blackjack combinations: \( 190 - 6 - 120 = 64 \). The probability is \( \frac{64}{1326} \approx 0.0483 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics
Combinatorics is a branch of mathematics concerned with counting, arrangement, and combination of objects. In the context of card games like blackjack, combinatorics is essential for determining the number of ways cards can be dealt, allowing us to calculate probabilities.

Understanding the basic combinatorics formula, known as the combination formula, is crucial. The combination formula is used for determining how many ways you can choose a subset of items from a larger set, where the order doesn't matter. It is given by:\[\binom{n}{r} = \frac{n!}{r!(n-r)!}\]where:
  • \(n\) is the total number of items.
  • \(r\) is the number of items to choose.
  • \(!\) denotes factorial, which is the product of all positive integers up to that number.
In this exercise about blackjack, combinatorics helps us determine the total number of possible two-card hands in a standard 52-card deck and the number of specific card combinations, such as two aces or two 10-point cards.
Hypergeometric Distribution
The hypergeometric distribution is a probability distribution used for sampling without replacement. It helps answer questions about probabilities in situations where the samples are dependent, such as drawing cards from a deck without putting them back.

A hypergeometric distribution is usually applied when you want to find the probability of drawing a certain number of "successful" outcomes (cards that meet a criteria) from the total number of draws. The probability mass function for a hypergeometric distribution is given by:\[P(X = k) = \frac{\binom{K}{k} \binom{N-K}{n-k}}{\binom{N}{n}}\]where:
  • \(N\) is the population size (e.g., 52 cards in a deck).
  • \(K\) is the number of successes in the population (e.g., number of aces).
  • \(n\) is the number of draws (e.g., cards dealt).
  • \(k\) is the number of observed successes (e.g., drawing two aces).
In the provided blackjack exercise, the hypergeometric distribution helps compute the probability of specific combinations, like drawing two aces or two 10-point cards when dealing cards without replacement.
Card Games Statistics
Understanding card games statistics involves comprehending the probabilities of drawing certain hands from a deck, impacting strategies in games like blackjack. The exercise showcases how stats are applied to calculate probabilities of drawing hands that consist of specific cards, enhancing decision-making during gameplay.

In blackjack, specific card values, such as aces and 10-point cards, play a crucial role in achieving the best hand, known as "blackjack," a combination of one ace and one 10-point card. Calculating such probabilities helps players determine the likelihood of achieving certain hands, allowing them to make informed decisions.

Statistics also uncover the expected outcomes in various scenarios. For instance, knowing there's roughly a 4.83% chance of being dealt a blackjack hand helps players assess risk versus reward when deciding whether or not to draw more cards or stand. Thus, mastering these statistics enables players to enhance their game strategy and improve their chances of winning.

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Most popular questions from this chapter

Phone calls arrive at the rate of 48 per hour at the reservation desk for Regional Airways. a. Compute the probability of receiving three calls in a 5 -minute interval of time. b. Compute the probability of receiving exactly 10 calls in 15 minutes. c. Suppose no calls are currently on hold. If the agent takes 5 minutes to complete the current call, how many callers do you expect to be waiting by that time? What is the probability that none will be waiting? d. If no calls are currently being processed, what is the probability that the agent can take 3 minutes for personal time without being interrupted by a call?

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Three students scheduled interviews for summer employment at the Brookwood Institute. In each case the interview results in either an offer for a position or no offer. Experimental outcomes are defined in terms of the results of the three interviews. a. \(\quad\) List the experimental outcomes. b. Define a random variable that represents the number of offers made. Is the random variable continuous? c. Show the value of the random variable for each of the experimental outcomes.

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Axline Computers manufactures personal computers at two plants, one in Texas and the other in Hawaii. The Texas plant has 40 employees; the Hawaii plant has \(20 .\) A random sample of 10 employees is to be asked to fill out a benefits questionnaire. a. What is the probability that none of the employees in the sample work at the plant in Hawaii? b. What is the probability that one of the employees in the sample works at the plant in Hawaii? c. What is the probability that two or more of the employees in the sample work at the plant in Hawaii? d. What is the probability that nine of the employees in the sample work at the plant in Texas?

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