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The prior probabilities for events \(A_{1}, A_{2},\) and \(A_{3}\) are \(P\left(A_{1}\right)=.20, P\left(A_{2}\right)=.50,\) and \(P\left(A_{3}\right)=\) \(.30 .\) The conditional probabilities of event \(B\) given \(A_{1}, A_{2},\) and \(A_{3}\) are \(P\left(B | A_{1}\right)=.50\) \(P\left(B | A_{2}\right)=.40,\) and \(P\left(B | A_{3}\right)=.30\). a. Compute \(P\left(B \cap A_{1}\right), P\left(B \cap A_{2}\right),\) and \(P\left(B \cap A_{3}\right)\). b. Apply Bayes' theorem, equation \((4,19),\) to compute the posterior probability \(P\left(A_{2} | B\right)\). c. Use the tabular approach to applying Bayes' theorem to compute \(P\left(A_{1} | B\right), P\left(A_{2} | B\right)\), and \(P\left(A_{3} | B\right)\) .

Short Answer

Expert verified
a. P(B ∩ A1) = 0.1, P(B ∩ A2) = 0.2, P(B ∩ A3) = 0.09. b. P(A2 | B) ≈ 0.513. c. P(A1 | B) ≈ 0.256, P(A2 | B) ≈ 0.513, P(A3 | B) ≈ 0.231.

Step by step solution

01

Calculate Joint Probabilities

To find the joint probabilities, use the formula: \[ P(B \cap A_i) = P(B | A_i) \cdot P(A_i) \]For each event:- \( P(B \cap A_1) = 0.5 \times 0.2 = 0.1 \)- \( P(B \cap A_2) = 0.4 \times 0.5 = 0.2 \)- \( P(B \cap A_3) = 0.3 \times 0.3 = 0.09 \)
02

Compute Total Probability of B

The total probability of event B is the sum of the joint probabilities:\[ P(B) = P(B \cap A_1) + P(B \cap A_2) + P(B \cap A_3) \]Substitute the values:\[ P(B) = 0.1 + 0.2 + 0.09 = 0.39 \]
03

Apply Bayes' Theorem for P(A2|B)

Bayes' Theorem is given by:\[ P(A_2 | B) = \frac{P(B \cap A_2)}{P(B)} \]Substitute the values found:\[ P(A_2 | B) = \frac{0.2}{0.39} \approx 0.513 \]
04

Use Bayes' Theorem for All Posterior Probabilities

Now, calculate \( P(A_1 | B) \), \( P(A_2 | B) \), and \( P(A_3 | B) \) using the tabular approach:- \( P(A_1 | B) = \frac{P(B \cap A_1)}{P(B)} = \frac{0.1}{0.39} \approx 0.256 \)- \( P(A_2 | B) = \frac{P(B \cap A_2)}{P(B)} = \frac{0.2}{0.39} \approx 0.513 \)- \( P(A_3 | B) = \frac{P(B \cap A_3)}{P(B)} = \frac{0.09}{0.39} \approx 0.231 \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Joint Probability
When we talk about joint probability, we are referring to the probability of two events happening at the same time. In this context, we're interested in both event B and an event from A happening together. To compute joint probabilities, we use the formula:
  • \( P(B \cap A_i) = P(B | A_i) \cdot P(A_i) \)
This formula is quite straightforward. It simply tells us to multiply the conditional probability of B given \(A_i\) by the probability of \(A_i\). For example:
  • \( P(B \cap A_1) = 0.5 \times 0.2 = 0.1 \)
  • \( P(B \cap A_2) = 0.4 \times 0.5 = 0.2 \)
  • \( P(B \cap A_3) = 0.3 \times 0.3 = 0.09 \)
These calculations allow us to understand the likelihood of the combination of events B and each \(A_i\) occurring in our scenario.
Conditional Probability
Conditional probability is a measure of the probability of an event occurring given that another event has already occurred. In simpler terms, it helps us adjust our probabilities based on additional information, showing us how probabilities alter under certain conditions.

It is represented as \( P(B | A) \), read as 'the probability of B given A.' The formula is:

\[ P(B | A) = \frac{P(B \cap A)}{P(A)} \]
In our exercise, this concept is specially used to link the occurrence of events B and each event A. The conditional probabilities were used in computing the joint probabilities initially. This is because, in those calculations, the condition that A had occurred was already considered, simplifying our calculations. By understanding conditional probability, we can make precise predictions in probability-related situations.
Posterior Probability
Posterior probability is an update of the initial probability of an event after taking into account new evidence or information. It reflects what we know about an event’s probability after considering what has happened. This concept is a critical part of Bayes’ Theorem.

Bayes’ Theorem helps us quantify the posterior probability by inversely weighting the initial, or prior, probabilities with the likelihood of the observed evidence. The formula is:

\[ P(A_i | B) = \frac{P(B \cap A_i)}{P(B)} \]
In our problem, we used this formula to find the updated probabilities of events \(A_1\), \(A_2\), and \(A_3\) given that event B occurred. For example, the posterior probability of \(A_2\) given B, represented as \(P(A_2 | B)\), was calculated as:
  • \(P(A_2 | B) = \frac{0.2}{0.39} \approx 0.513 \)
Bayes' theorem thus helps us transition from a world of initial assumptions to more informed decisions, integrating fresh evidence into our probabilistic models.

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Most popular questions from this chapter

How many permutations of three items can be selected from a group of six? Use the letters \(A\), \(\mathrm{B}, \mathrm{C}, \mathrm{D}, \mathrm{E},\) and \(\mathrm{F}\) to identify the items, and list each of the permutations of items \(\mathrm{B}, \mathrm{D},\) and \(\mathrm{F}\).

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Suppose that we have two events, \(A\) and \(B,\) with \(P(A)=.50, P(B)=.60,\) and \(P(A \cap B)=.40\). a. \(\quad\) Find \(P(A | B)\). b. Find \(P(B | A)\). c. Are \(A\) and \(B\) independent? Why or why not?

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