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In a program designed to help patients stop smoking, 198 patients were given sustained care, and \(82.8 \%\) of them were no longer smoking after one month. Among 199 patients given standard care, \(62.8 \%\) were no longer smoking after one month (based on data from "Sustained Care Intervention and Postdischarge Smoking Cessation Among Hospitalized Adults"" by Rigotti et al., Journal of the American Medical Association, Vol. 312, No. 7). Construct the two \(95 \%\) confidence interval estimates of the percentages of success. Compare the results. What do you conclude?

Short Answer

Expert verified
Sustained care: (0.773, 0.883), Standard care: (0.560, 0.696). Sustained care is more effective.

Step by step solution

01

- Identify the given data

Extract the given information from the problem: For sustained care: sample size (n1) = 198, sample proportion (p1) = 0.828. For standard care: sample size (n2) = 199, sample proportion (p2) = 0.628.
02

- Determine the critical value

For a 95% confidence interval, the critical value (z) for the standard normal distribution is 1.96.
03

- Calculate the confidence interval for sustained care

Use the formula for the confidence interval for a proportion: \[ \text{CI} = p \pm z \times \sqrt{ \frac{p(1-p)}{n} } \] where p = 0.828, n = 198, and z = 1.96. Compute the margin of error: \[ \text{Margin of Error} = 1.96 \times \sqrt{ \frac{0.828(0.172)}{198} } = 0.055 \] Thus, the confidence interval for sustained care is: \[ 0.828 \pm 0.055 = (0.773, 0.883) \]
04

- Calculate the confidence interval for standard care

Similarly, use the same formula for the second group with p = 0.628 and n = 199. Compute the margin of error: \[ \text{Margin of Error} = 1.96 \times \sqrt{ \frac{0.628(0.372)}{199} } = 0.068 \] Thus, the confidence interval for standard care is: \[ 0.628 \pm 0.068 = (0.560, 0.696) \]
05

- Comparison of results

Compare the two confidence intervals: The confidence interval for sustained care is (0.773, 0.883) and for standard care is (0.560, 0.696).
06

- Conclusion

Since the confidence interval for sustained care is significantly higher than that for standard care, it can be concluded that sustained care appears to be more effective at helping patients stop smoking after one month.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion
In statistical terms, a proportion represents a part of the whole. It's often used to express percentages. In this smoking cessation study, proportions tell us the percentage of patients who stopped smoking in each group.
For example, in the sustained care group, 82.8% of the 198 patients stopped smoking. To use this proportion in calculations, it's converted to a decimal: 0.828.
The sample proportion is then represented as follows: \( \text{Sample Proportion} (p1) = \frac{\text{Number of Successes}}{\text{Total Sample Size}} = \frac{164}{198} = 0.828 \) where 164 is the number of patients who stopped smoking.
Margin of Error
The margin of error essentially provides a range around our sample proportion to show where the true population proportion might lie with a certain level of confidence. It accounts for variability in sampling.
For sustained care, the margin of error can be calculated using the formula: \[ Margin of Error = z \times \frac{\text{Standard Error}}{\text{Square Root of the Sample Size}} \]
Using our numbers: \[ Margin of Error = 1.96 \times \frac{ \text{Square Root of}[0.828 \times (1 - 0.828) / 198]} \]
This calculation results in a margin of error of about 0.055. This is added to and subtracted from the sample proportion to get the confidence interval.
Critical Value
The critical value is a key factor in calculating confidence intervals. It represents how many standard deviations our sample proportion is from the population proportion.
For a 95% confidence interval, the critical value (z) is typically 1.96. This means we are covering the middle 95% of the normal distribution curve. The critical value provides assurance that the true proportion is within our calculated range.

Using the standard normal distribution: \[ z_{0.025} = 1.96 \] This critical value helps determine how wide our confidence interval will be, affecting the margin of error.
Hypothesis Testing
Hypothesis testing allows us to test assumptions (hypotheses) about a population parameter based on sample data.
In this smoking cessation study, we might set up a hypothesis to test if there’s a significant difference between the smoking cessation rates for sustained care vs. standard care.
Typically, we start with a null hypothesis (H_0: No difference exists) and an alternative hypothesis (H_1: A difference does exist). We then use sample data, confidence intervals, and critical values to accept or reject the null hypothesis. If the confidence intervals for two different proportions do not overlap significantly, we can reject H_0 and conclude that one treatment is more effective.
Smoking Cessation Study
This study by Rigotti et al. aimed to determine the effectiveness of sustained vs. standard care in helping patients quit smoking. We have two groups with different care types and respective cessation rates.
By calculating and comparing the confidence intervals for each group's proportion of success, the study demonstrates the effectiveness of sustained care. The higher confidence interval for sustained care, (0.773, 0.883), compared to standard care, (0.560, 0.696), clearly suggests that sustained care is more effective.
  • Sustained Care: Higher proportion of quitters.
  • Standard Care: Lower proportion of quitters.
The margin of error and critical values assure that these conclusions are statistically significant.

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