/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 The Wechsler IQ test is designed... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The Wechsler IQ test is designed so that the mean is 100 and the standard deviation is 15 for the population of normal adults. Find the sample size necessary to estimate the mean IQ score of college professors. We want to be \(99 \%\) confident that our sample mean is within 4 IQ points of the true mean. The mean for this population is clearly greater than 100 . The standard deviation for this population is less than 15 because it is a group with less variation than a group randomly selected from the general population; therefore, if we use \(\sigma=15\) we are being conservative by using a value that will make the sample size at least as large as necessary. Assume then that \(\sigma=15\) and determine the required sample size. Does the sample size appear to be practical?

Short Answer

Expert verified
A sample size of 94 college professors is needed to estimate the mean IQ with 99% confidence within 4 points. This appears practical but will depend on resource availability.

Step by step solution

01

Identify Given Information

Given in the problem are: - Mean, \(\bar{x} = 100\) - Standard deviation, \(\sigma = 15\) - Confidence level, \(\text{confidence level} = 99\%\) - Margin of error, \(\text{E} = 4\) points
02

Understand Confidence Level and Critical Value

For a 99% confidence level, the critical value (z) is found using the standard normal distribution table. The z-value for 99% confidence is approximately \(\text{z} = 2.575\).
03

Use Sample Size Formula

The formula to find the sample size \( n \) is: \[ n = \frac{(z \times \sigma)^2}{E^2} \] Substitute the known values into the formula: \[ n = \frac{(2.575 \times 15)^2}{4^2} \]
04

Calculate Required Sample Size

Perform the calculations: \[ n = \frac{(2.575 \times 15)^2}{4^2} = \frac{(38.625)^2}{16} = \frac{1492.140625}{16} \] Calculate the final sample size: \[ n = 93.2587890625 \] Since sample size must be a whole number, round up to the next whole number: \[ n = 94 \]
05

Evaluate Practicality

With a required sample size of 94, consider whether it is practical to gather this many participants for the study. Typically, for studies involving specific populations like college professors, 94 may be attainable but will depend on resources and accessibility.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Level
When conducting a survey or experiment, the confidence level tells us how certain we are that our sample mean (or other estimate) falls within a specified range of the true population parameter. For instance, a 99% confidence level implies that if we were to take 100 different samples, approximately 99 of those samples' confidence intervals would contain the true population mean. This gives a high degree of certainty about the estimate.
Confidence level is connected to the critical value and the margin of error. Higher confidence levels require larger sample sizes to ensure the same margin of error, since we need to be more certain our estimate is close to the true value.
Margin of Error
The margin of error (E) in a statistical study measures the maximum expected difference between the true population parameter and a sample estimate. It defines the range within which we expect the true population parameter to lie.
In our example, we want the mean IQ score of college professors to be within 4 IQ points of the true mean with 99% confidence. This means our sample mean's range will be up to 4 points away from the true mean in either direction. Having a smaller margin of error requires a larger sample size because it reduces the range in which the true population parameter is expected to fall.
The formula for margin of error, when using the standard normal distribution, often involves the product of the critical value and the standard deviation, divided by the square root of the sample size.
Standard Deviation
Standard deviation (σ) is a measure of the spread of a set of values. It tells us how much the values deviate on average from the mean. A larger standard deviation indicates greater variability, while a smaller one indicates that values are more closely clustered around the mean.
In the context of the Wechsler IQ test, the standard deviation is given as 15 for the entire population. For a group like college professors, the standard deviation is expected to be smaller due to lesser variation. However, using a higher standard deviation like 15 can ensure our sample size calculation remains conservative, potentially overestimating rather than underestimating the necessary sample size. Using \(\sigma=15\, \) the formula \(\sqrt{(z \times \sigma)\) divides the total variability by the square of the desired precision.
Wechsler IQ Test
The Wechsler IQ test is a widely used intelligence test designed to measure cognitive ability in adults and older adolescents. It has a mean score set to 100 and a standard deviation of 15. These parameters make it a benchmark for other measurements and studies related to IQ among different populations.
The test assesses various aspects of intelligence through different subtests, including arithmetic, vocabulary, and pattern recognition. Due to these standards, the Wechsler IQ test is often used in academic and psychological research.
In our problem, the specific population of college professors is expected to have a mean IQ above 100, and the standard deviation is assumed to be less than 15, ensuring a more homogenous group with higher cognitive abilities.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In a study of the accuracy of fast food drive-through orders, Burger King had 264 accurate orders and 54 that were not accurate (based on data from \(Q S R\) magazine). a. Construct a \(99 \%\) confidence interval estimate of the percentage of orders that are not accurate. b. Compare the result from part (a) to this \(99 \%\) confidence interval for the percentage of orders that are not accurate at Wendy's: \(6.2 \%

Samples of DNA are collected, and the four DNA bases of A, G, C, and T are coded as \(1,2,3\), and 4, respectively. The results are listed below. Construct a \(95 \%\) confidence interval estimate of the mean. What is the practical use of the confidence interval? $$ \begin{array}{llllllllll} 2 & 2 & 1 & 4 & 3 & 3 & 3 & 3 & 4 & 1 \end{array} $$

When she was 9 years of age, Emily Rosa did a science fair experiment in which she tested professional touch therapists to see if they could sense her energy field. She flipped a coin to select either her right hand or her left hand, and then she asked the therapists to identify the selected hand by placing their hand just under Emily's hand without seeing it and without touching it. Among 280 trials, the touch therapists were correct 123 times (based on data in "A Close Look at Therapeutic Touch," Journal of the American Medical Association, Vol. 279, No. 13 ). a. Given that Emily used a coin toss to select either her right hand or her left hand, what proportion of correct responses would be expected if the touch therapists made random guesses? b. Using Emily's sample results, what is the best point estimate of the therapists' success rate? c. Using Emily's sample results, construct a \(99 \%\) confidence interval estimate of the proportion of correct responses made by touch therapists. d. What do the results suggest about the ability of touch therapists to select the correct hand by sensing an energy field?

A random sample of 860 births in New York State included 426 boys. Construct a 95\% confidence interval estimate of the proportion of boys in all births. It is believed that among all births, the proportion of boys is \(0.512 .\) Do these sample results provide strong evidence against that belief?

A study of 420,095 Danish cell phone users found that \(0.0321 \%\) of them developed cancer of the brain or nervous system. Prior to this study of cell phone use, the rate of such cancer was found to be \(0.0340 \%\) for those not using cell phones. The data are from the Journal of the National Cancer Institute. a. Use the sample data to construct a \(90 \%\) confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system. b. Do cell phone users appear to have a rate of cancer of the brain or nervous system that is different from the rate of such cancer among those not using cell phones? Why or why not?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.