/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 A study addressed the issue of w... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A study addressed the issue of whether pregnant women can correctly predict the gender of their baby. Among 104 pregnant women, 57 correctly predicted the gender of their baby (based on data from "Are Women Carrying 'Basketballs'...," by Perry, DiPietro, Constigan, Birth, Vol. 26, No. 3). If pregnant women have no such ability, there is a \(0.327\) probability of getting such sample results by chance. What do you conclude?

Short Answer

Expert verified
The data do not provide sufficient evidence to conclude that pregnant women can predict the gender of their baby better than random chance.

Step by step solution

01

Understand the Given Data

Identify and understand the given data points: - Total number of pregnant women: 104 - Pregnant women who correctly predicted gender: 57 - Probability of getting such sample results by chance: 0.327
02

Formulate the Null Hypothesis

State the null hypothesis. In this case, the null hypothesis is that pregnant women have no ability to predict the gender of their baby better than random chance.
03

Formulate the Alternative Hypothesis

State the alternative hypothesis. The alternative hypothesis is that pregnant women can predict the gender of their baby better than random chance.
04

Interpret the Probability (P-Value)

Interpret the given probability (P-value). A P-value of 0.327 means there is a 32.7% chance of getting the observed results, or more extreme, assuming the null hypothesis is true.
05

Compare P-Value with Significance Level

Typically, a significance level (alpha) of 0.05 is used. Compare the P-value to this threshold: - If P-value ≤ 0.05, reject the null hypothesis - If P-value > 0.05, fail to reject the null hypothesis
06

Conclusion

Since the P-value (0.327) is greater than the significance level (0.05), we fail to reject the null hypothesis. Therefore, the data do not provide sufficient evidence to conclude that pregnant women can predict the gender of their baby better than random chance.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

null hypothesis
When we conduct a statistical hypothesis test, we start with the **null hypothesis** (denoted as \( H_0 \)). The null hypothesis is a statement that there is no effect or no difference, and it assumes that any kind of apparent pattern or result in our data is simply due to chance.

In the given exercise, the null hypothesis is: **Pregnant women have no ability to predict the gender of their baby better than random chance**. This means we assume there's no actual predictive power, and any correct predictions occurred purely by luck. The null hypothesis is our default or baseline assumption that we try to test against.
alternative hypothesis
Opposing the null hypothesis is the **alternative hypothesis** (denoted as \( H_1 \) or \( H_A \)). This is the hypothesis we want to test for, and it suggests that there is an effect, a difference, or a relationship that exists.

In the context of the exercise, the alternative hypothesis is: **Pregnant women can predict the gender of their baby better than random chance**. This hypothesis suggests that any correct predictions are more than just luck and that pregnant women have some form of predictive ability.

The goal of hypothesis testing is to determine whether there is enough evidence in the data to reject the null hypothesis in favor of the alternative hypothesis.
P-value
The **P-value** is a key concept in hypothesis testing. It measures the probability of obtaining results at least as extreme as the ones observed, assuming that the null hypothesis is true. It helps us determine whether to reject the null hypothesis.

In the exercise, the P-value is **0.327**, meaning there is a 32.7% probability of getting the sample results (or something more extreme) if the null hypothesis is actually true. A high P-value indicates that the observed data is likely under the null hypothesis, while a low P-value suggests the data is unusual under the null hypothesis and may thus support the alternative hypothesis.

P-values are used to make decisions about the null hypothesis: whether to reject it or not.
significance level
The **significance level** (denoted as \( \alpha \)) is a threshold used to decide whether the P-value obtained from our test is low enough to reject the null hypothesis. Common choices for \( \alpha \) are 0.05, 0.01, and 0.10. The choice of \( \alpha \) depends on how strict we want to be about making an error in our conclusion.

In general, if the P-value is less than \( \alpha \), we reject the null hypothesis. If the P-value is greater than \( \alpha \), we fail to reject the null hypothesis.

In this exercise, a typical significance level of \(0.05\) is used. Because the P-value \((0.327)\) is greater than \(0.05\), we **fail to reject the null hypothesis**. Therefore, we conclude that there isn't sufficient evidence to say pregnant women can predict the gender of their babies better than random chance.

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