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Express all probabilities as fractions. Quicken Loans offered a prize of \(\$ 1\) billion to anyone who could correctly predict the winner of the NCAA basketball tournament. After the "play-in" games, there are 64 teams in the tournament. a. How many games are required to get 1 championship team from the field of 64 teams? b. If you make random guesses for each game of the tournament, find the probability of picking the winner in every game.

Short Answer

Expert verified
a. 63 games are required. b. \( \left( \frac{1}{2} \right)^{63} \) is the probability.

Step by step solution

01

Determine Total Number of Teams

Start with the initial number of teams, which is 64.
02

Calculate Number of Games

To find the number of games required, note that each game eliminates one team. Therefore, 63 games are required to determine a single champion from 64 teams.
03

Understanding Random Guess Probability

For part (b), consider that each game has two possible outcomes. Therefore, in each game, you have a probability of \( \frac{1}{2} \) of guessing correctly.
04

Calculate Total Probability

Use the individual game probability to find the overall probability by raising \( \frac{1}{2} \) to the power of the number of games (63). Thus, the probability is \( \left( \frac{1}{2} \right)^{63} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Probability is the measure of the likelihood that an event will occur. It's quantified as a number between 0 and 1, where 0 means the event won't happen and 1 means it definitely will. In sports tournaments like the NCAA basketball tournament, calculating the probability involves understanding the structure of the games and how outcomes are determined. In this exercise, we start with 64 teams, and each game eliminates one team until only one champion remains. Therefore, there are 63 games to find one champion. If each game is a coin flip and you guess randomly, the chance of picking the winner in each game is \( \frac{1}{2} \). To find the overall probability of guessing all games correctly, multiply the individual probabilities. Therefore, the overall probability is \( \left( \frac{1}{2} \right)^{63} \). This exponential function highlights how quickly probabilities decrease with each additional game.
NCAA Basketball Tournament
The NCAA basketball tournament, also known as March Madness, is a renowned event in college sports. It involves 64 teams competing in a knockout format. Each game is a single-elimination match, meaning the losing team is out of the tournament. This continues until only one team is left standing as the national champion. To better understand, imagine starting with a clean bracket of 64 teams:
  • First round: 64 teams play 32 games (64/2 = 32 winning teams)
  • Second round: 32 teams play 16 games (32/2 = 16 winning teams)
  • Third round: 16 teams play 8 games, and so on, until the finals
This structure keeps cutting the number of teams in half each round until only one champion remains. Thus, there are 63 games in total (one less than the initial number of teams) to determine the overall winner.
Random Guessing
When guessing randomly in a structured event like the NCAA tournament, each guess can be seen as an independent event with two possible outcomes—either you guess right, or you guess wrong. Let's break it down:
  • For each game, you have a 50% chance of guessing correctly, or \( \frac{1}{2} \).
  • Since each game is independent, you multiply the probabilities of guessing each game right together.
  • This leads to the overall probability of \( \left( \frac{1}{2} \right)^{63} \), considering there are 63 games to guess correctly.
Calculating this:
\( \left( \frac{1}{2} \right)^{63} \) is a very small number indeed, indicating that random guessing is highly unlikely to win. To illustrate, it is similar to flipping a coin and getting heads 63 times in a row. The likelihood of such a streak is exceptionally low, highlighting the challenge of predicting each game's outcome in the tournament by pure chance.

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