/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 The quadratic mean (or root mean... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The quadratic mean (or root mean square, or R.M.S.) is used in physical applications, such as power distribution systems. The quadratic mean of a set of values is obtained by squaring each value, adding those squares, dividing the sum by the number of values \(n\), and then taking the square root of that result, as indicated below: $$\text { Quadratic mean }=\sqrt{\frac{\sum x^{2}}{n}}$$ Find the R.M.S. of these voltages measured from household current: \(0,60,110,-110,-60,0 .\) How does the result compare to the mean?

Short Answer

Expert verified
The R.M.S. is approximately 72.33 and the mean is 0.

Step by step solution

01

List the Voltages

Write down the given voltages: 0, 60, 110, -110, -60, 0
02

Square Each Voltage

Square each voltage value: 0^2 = 0, 60^2 = 3600, 110^2 = 12100, (-110)^2 = 12100, (-60)^2 = 3600, 0^2 = 0
03

Sum the Squares

Add together the squares of each voltage: 0 + 3600 + 12100 + 12100 + 3600 + 0 = 31400
04

Divide by the Number of Values

Divide the sum of the squares by the number of values (n = 6): \[\frac{31400}{6} = 5233.33\]
05

Take the Square Root

Take the square root of the result: \[\text{R.M.S.} = \sqrt{5233.33} \approx 72.33\]
06

Calculate the Mean

Calculate the arithmetic mean of the voltages: \(\text{mean} = \frac{0 + 60 + 110 - 110 - 60 + 0}{6} = 0\)
07

Compare R.M.S. to Mean

Compare the obtained R.M.S. value (72.33) to the arithmetic mean (0). The R.M.S. is significantly higher than the mean.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

root mean square
The root mean square (R.M.S.), or quadratic mean, is a mathematical concept used to measure the magnitude of a set of numbers. It's particularly valuable in situations involving alternating values, like voltages. You might wonder why we use the R.M.S. instead of just averaging the numbers directly. This is because the R.M.S. considers the squaring and taking the root of values, making it ideal for capturing both positive and negative fluctuations. For example, to find the R.M.S. of the voltages 0, 60, 110, -110, -60, 0, we square each number, sum them up, find their average, and then take the square root. The formula looks like this: \[ \text{Quadratic mean (R.M.S.)} = \sqrt{\frac{\sum x^2}{n}} \]. This ensures that any negative values do not cancel out positive ones, providing a more accurate representation of the magnitude of these values.
voltage measurement
Voltage measurements are crucial in many practical applications, such as household electrical currents and power distribution systems. Voltages can fluctuate between positive and negative values, which makes straightforward averaging inaccurate. For example, if we measure the voltages as 0, 60, 110, -110, -60, 0, a simple arithmetic mean would yield 0. This result does not truly reflect the actual power carried by these currents. By using the R.M.S. method, we can account for the oscillations and get a value that better represents the effective voltage. Thus, calculated R.M.S. for the given voltages is 72.33, which gives a clearer picture of their effective magnitude.
arithmetic mean comparison
The arithmetic mean is a simple average calculated by summing values and dividing by the count of numbers. It's useful for many everyday situations but falls short in cases with alternating positive and negative values. Taking our voltage example: 0, 60, 110, -110, -60, 0, the arithmetic mean is (0 + 60 + 110 - 110 - 60 + 0) / 6 = 0. While the arithmetic mean indicates balance between positive and negative values, it does not express the overall magnitude effectively. The R.M.S. provides a better measure by squaring values first, ensuring all values contribute positively to the final result. As seen, the quadratic mean (or R.M.S.) value is 72.33, which is more representative of the voltage's effective strength.
statistics in physical applications
In physical applications, including engineering, physics, and natural sciences, accurate statistical measures are critical. The R.M.S. is widely used because it handles the fluctuating nature of data well. Whether measuring sound levels, velocities, or electrical currents, the R.M.S. provides a clearer picture of the overall magnitude. Unlike the arithmetic mean, which can be misleading in the presence of opposites (like positive and negative voltages), the R.M.S. captures the true impact. For example, in our voltage measurements of 0, 60, 110, -110, -60, 0, the R.M.S. calculation gave us 72.33, while the arithmetic mean gave 0. This difference highlights why the R.M.S. is preferred in accurately interpreting real-world fluctuating data, offering insights into the effective energy, power, or other physical quantities.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the mean and median for each of the two samples, then compare the two sets of results. Waiting times (in seconds) of customers at the Madison Savings Bank are recorded with two configurations: single customer line; individual customer lines. Carefully examine the data to determine whether there is a difference between the two data sets that is not apparent from a comparison of the measures of center. If so, what is it? \(\begin{array}{lllllllllll}\text { Single Line } & 390 & 396 & 402 & 408 & 426 & 438 & 444 & 462 & 462 & 462 \\ \text { Individual Lines } & 252 & 324 & 348 & 372 & 402 & 462 & 462 & 510 & 558 & 600\end{array}\)

The geometric mean is often used in business and economics for finding average rates of change, average rates of growth, or average ratios. To find the geometric mean of \(n\) values (all of which are positive), first multiply the values, then find the \(n\) th root of the product. For a 6-year period, money deposited in annual certificates of deposit had annual interest rates of \(5.154 \%, 2.730 \%, 0.488 \%, 0.319 \%, 0.313 \%\), and \(0.268 \%\). Identify the single percentage growth rate that is the same as the five consecutive growth rates by computing the geometric mean of \(1.05154,1.02730,1.00488,1.00319,1.00313\), and \(1.00268\).

USA Today published a list consisting of the state tax on each gallon of gas. If we add the 50 state tax amounts and then divide by 50 , we get \(27.3\) cents. Is the value of \(27.3\) cents the mean amount of state sales tax paid by all U.S. drivers? Why or why not?

Use the given data to construct a boxplot and identify the 5-number summary. Listed below are the measured radiation absorption rates (in \(\mathrm{W} / \mathrm{kg}\) ) corresponding to these cell phones: iPhone 5S, BlackBerry Z30, Sanyo Vero, Optimus V, Droid Razr, Nokia N97, Samsung Vibrant, Sony Z750a, Kyocera Kona, LG G2, and Virgin Mobile Supreme. The data are from the Federal Communications Commission. \(\begin{array}{lllllllllll}1.18 & 1.41 & 1.49 & 1.04 & 1.45 & 0.74 & 0.89 & 1.42 & 1.45 & 0.51 & 1.38\end{array}\)

Watch out for these little buggers. Each of these exercises involves some feature that is somewhat tricky. Find the (a) mean, \((b)\) median, (c) mode, (d) midrange, and then answer the given question. Biologists conducted experiments to determine whether a deficiency of carbon dioxide in the soil affects the phenotypes of peas. Listed below are the phenotype codes, where \(1=\) smooth-yellow, \(2=\) smooth-green, \(3=\) wrinkled- yellow, and \(4=\) wrinkled-green. Can the measures of center be obtained for these values? Do the results make sense? \(\begin{array}{lllllllllllllllllllllllll}2 & 1 & 1 & 1 & 1 & 1 & 1 & 4 & 1 & 2 & 2 & 1 & 2 & 3 & 3 & 2 & 3 & 1 & 3 & 1 & 3 & 1 & 3 & 2 & 2\end{array}\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.