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How long will it take \(\$ 1000\) to triple if it is invested at an annual interest rate of \(5.5 \%\) compounded continuously? Round to the nearest year.

Short Answer

Expert verified
It will take approximately 20 years for the investment of $1000 to triple under an annual interest rate of 5.5% compounded continuously.

Step by step solution

01

Convert interest rate

Convert the interest rate to decimal. We do this by dividing the given interest rate by a 100. So, \(r = 5.5\% = 5.5/100 = 0.055\).
02

Plug values into the continuous compounding formula

Insert the known values \(P = $1000\), \(A = $3000\) and \(r = 0.055\) into the continuous compounding formula: \(3000 = 1000 * e^{0.055t}\). Here, \(e\) is the base of natural logarithm, approximately equals to 2.71828.
03

Solve for t

Divide both sides of the equation by 1000. This gives: \(3 = e^{0.055t}\). Now, to get \(t\) out of the exponent, we take the natural logarithm (ln) on both sides: \(ln(3) = ln(e^{0.055t})\). By properties of logarithms, we can bring down the \(t\) and write our equation as \(ln(3) = 0.055t*ln(e)\). Remember, \(ln(e) = 1\), so this simplifies to \(ln(3) = 0.055t\). Now, to isolate \(t\), divide both sides of the equation by \(0.055\): \(t = ln(3)/0.055 \).
04

Compute for t

Calculate \(t = ln(3)/0.055\) using a calculator to get a numeric value. We have: \(t ≈ 20\).
05

Round the answer

Since the question asked for an answer rounded to the nearest year, we have \(t ≈ 20\) years. No rounding is needed here as 20 is already an integer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Compounded Interest Rate
The compounded interest rate is a concept that is used to calculate the amount of interest earned on an investment or loan where interest is being added to the principal amount on a regular basis, leading to interest accruing on previously earned interest.

When it comes to continuous compounding, the formula to calculate the final amount is given by: \( A = Pe^{rt} \) where:
  • \( P \) is the principal amount,
  • \( r \) is the annual interest rate in decimal form,
  • \( e \) is the base of the natural logarithm,
  • \( t \) is the time in years,
  • and \( A \) is the amount of money accumulated after \( n \) years, including interest.
Under continuous compounding, interest is theoretically compounded an infinite number of times per year.

In our exercise, by using the continuous compounding formula, we could determine how long it would take for an initial investment of \( \(1000 \) to grow to \( \)3000 \) at an annual interest rate of 5.5%.
Natural Logarithm
The natural logarithm, usually represented as \( \text{ln} \) or \( \text{log}_e \), is the logarithm to the base '\( e \)'. This special number, '\( e \)', is approximately 2.71828 and is irrational, which means it cannot be represented as a simple fraction and its decimal representation goes on infinitely without repeating.

In various financial calculations, including continuous compounding problems, the natural logarithm aids in solving for the time required for investments to reach a certain value. It has a fundamental property that \( \text{ln}(e^x) = x \) which is crucial for simplifying our calculations.

During our example problem, to isolate and solve for time '\( t \) ', we used the property that the natural logarithm of '\( e \) ' raised to any power is simply the power itself. This allowed us to take the natural logarithm of both sides of our equational equation to solve for '\( t \) ' effectively.
Exponential Growth
Exponential growth occurs when an amount increases at a rate that is proportional to its current value, such as in the case of continuous interest compounding. The phenomenon of exponential growth shows up in not just finance, but in populations, resource use, and technology as well.

An exponential growth function can be represented as \( y = a(1 + r)^t \) in general, where \( a \) is the initial amount, \( r \) is the growth rate, and \( t \) is the time. However, for continuous growth, the formula transforms to \( y = ae^{rt} \), leveraging the mathematical constant '\( e \)'.

In the context of our given problem, the investment is growing exponentially, meaning it increases faster as time goes on. The continuous compounding formula is a representation of exponential growth where the base \( e \) indicates the nature of continuous growth. We were interested in finding the time \( t \) when the investment tripped in value, highlighting the essence of exponential growth in continuously compounded interest scenarios.

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