/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 In the city of Whispering Palms,... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In the city of Whispering Palms, which has a population of 80,000 people, the number of people \(P(t)\) exposed to a rumor in \(t\) hours is given by the function \(P(t)=80,000\left(1-e^{-0.00055}\right)\) a. Find the number of hours until \(10 \%\) of the population has heard the rumor. b. Find the number of hours until \(50 \%\) of the population has heard the rumor.

Short Answer

Expert verified
The number of hours until 10% of the population has heard the rumor is determined by evaluating the expression \[t = -\frac{ln(0.9)}{0.00055}\]. The number of hours until 50% of the population has heard the rumor is determined by evaluating the expression \[t = -\frac{ln(0.5)}{0.00055}\].

Step by step solution

01

Solve for time when 10% of the population has heard the rumor

To find out when 10% of the population has heard the rumor, set P(t) equal to 8000 and solve for \(t\): \[8000 = 80000 \times (1-e^{-0.00055t})\]. This simplifies to: \[0.1 = 1 - e^{-0.00055t}\]. After rearranging the terms, we get an equation \[e^{-0.00055t} = 0.9\]. Taking the natural logarithm of each side of the above equation yields an equation of the form: \[-0.00055t = ln(0.9)\]. By dividing both sides by -0.00055 yields the value of \(t\).
02

Solve for time when 50% of the population has heard the rumor

To find out when 50% of the population has heard the rumor, set P(t) equal to 40000 and solve for \(t\): \[40000 = 80000 \times (1-e^{-0.00055t})\]. This simplifies to: \[0.5 = 1 - e^{-0.00055t}\]. After rearranging the terms, we get an equation \[e^{-0.00055t} = 0.5\]. Taking the natural logarithm of each side of the above equation yields an equation of the form: \[-0.00055t = ln(0.5)\]. By dividing both sides by -0.00055 yields the value of \(t\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Functions
Exponential functions are mathematical representations of growth or decay processes that increase or decrease at rates proportional to their current value. In basic terms, these functions describe situations where something grows by a fixed percentage over equally spaced intervals, like population growth or radioactive decay.

For example, the expression \(P(t) = 80,000(1 - e^{-0.00055t})\) as given in the problem we're discussing, is an exponential function. This specific function represents the number of people in a city who have heard a rumor after \(t\) hours. In this case, \(e\) represents Euler's number (approximately 2.71828), a constant often associated with natural growth scenarios, and the exponent \( -0.00055t\) dictates the rate at which the rumor spreads.
Natural Logarithm
The natural logarithm, often abbreviated as \(\ln\), is the logarithm to the base \(e\), Euler's number. It acts as the 'undo' operation for exponentiation with base \(e\). So when we have an expression like \(e^x\), taking the natural logarithm \(\ln(e^x)\) will result in \(x\).

When solving our initial problem, using the natural logarithm allows us to isolate the variable \(t\) from the exponent of the exponential function. This mathematical maneuver is critical in solving exponential equations, particularly when we want to find out how long it takes for a certain percentage of the population to hear a rumor. For instance, to solve \(e^{-0.00055t} = 0.9\), we take the natural logarithm of both sides, yielding the equation \(\ln(e^{-0.00055t}) = \ln(0.9)\), which simplifies to \(-0.00055t = \ln(0.9)\).
Population Growth Models
Population growth models like the one in our Whispering Palms city example use exponential functions to describe how populations change over time. These models account for various scenarios, including unlimited resource availability and unrestricted growth, or scenarios where resources and growth are limited.

These models are crucial in fields ranging from ecology to urban planning, as they help predict future population sizes based on current trends. The particular model used in our problem assumes a fixed percentage of new individuals hearing the rumor each hour. It's not just about the raw number; it's the fact that as more people know, they, in turn, tell others, creating an exponential effect.
Solving Exponential Equations
Solving exponential equations often requires isolating the variable that is the exponent, which is frequently accomplished by using logarithms. As evidenced in the solutions to both parts of our original problem, the natural logarithm works effectively when the base of the exponential is \(e\).

Once we take the natural logarithm of both sides, we can then solve for the variable of interest. In educational contexts, this solving process may be simplified as 'apply the natural logarithm, then divide to isolate the variable'. For real-world applications, these equations can be more complex, but the underlying strategy remains the same: logarithms are a powerful tool for solving equations that contain exponents.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An exponential function that approximates the number of people in the United States who have been infected with AIDS is= given by \(N(t)=138,000(1.39)^{t},\) where \(t\) is the number of years after January 1,1990 a. According to this function, how many people had been infected with AIDS as of January \(1,1994 ?\) Round to the nearest thousand. b. Use a graph to estimate during what year the number of people in the United States who had been infected with AIDS first reached 1.5 million.

Make use of the factorial function, which is defined as follows. For whole numbers \(n\), the number \(n !\) (which is read "n factorial") is given by $$n !=\left\\{\begin{array}{ll} n(n-1)(n-2) \cdots 1, & \text { if } n \geq 1 \\\1, & \text { if } n=0 \end{array}\right.$$Thus, \(0 !=1\) and \(4 !=4 \cdot 3 \cdot 2 \cdot 1=24\) A study shows that the number of people who arrive at a bank teller's window averages 4.1 people every 10 minutes. The probability \(P\) that exactly \(x\) people will arrive at the teller's window in a given 10 -minute period is $$P(x)=\frac{4.1^{x} e^{-4.1}}{x !}$$ Find, to the nearest \(0.1 \%,\) the probability that in a given 10-minute period, exactly a. 0 people arrive at the window. b. 2 people arrive at the window. c. 3 people arrive at the window. d. 4 people arrive at the window. e. 9 people arrive at the window. As \(x \rightarrow \infty,\) what does \(P\) approach?

Use a graphing utility to graph each function. If the function has a horizontal asymptote, state the equation of the horizontal asymptote. $$f(x)=0.5 e^{-x}$$

A medical care package is air lifted and dropped to a disaster area. During the free-fall portion of the drop, the time, in seconds, required for the package to obtain a velocity of \(v\) feet per second is given by the function $$t=2.43 \ln \frac{150+v}{150-v}, \quad 0 \leq v<150$$ a. Determine the velocity of the package 5 seconds after it is dropped. Round to the nearest foot per second. b. Determine the vertical asymptote of the function. c. Write a sentence that explains the meaning of the vertical asymptote in the context of this application.

Geologists have determined that Crater Lake in Oregon was formed by a volcanic eruption. Chemical analysis of a wood chip that is assumed to be from a tree that died during the eruption has shown that it contains approximately \(45 \%\) of its original carbon- 14 Determine how long ago the volcanic eruption occurred. Use 5730 years as the half-life of carbon- 14

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.