/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 The mean age of all 2550 student... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The mean age of all 2550 students at a small college is \(22.8\) years with a standard deviation is \(3.2\) years, and the distribution is right-skewed. A random sample of 4 students' ages is obtained, and the mean is \(23.2\) with a standard deviation of \(2.4\) years. a. \(\mu=? \quad \sigma=? \quad \bar{x}=? \quad s=?\) b. Is \(\mu\) a parameter or a statistic? c. Are the conditions for using the CLT fulfilled? What would be the shape of the approximate sampling distribution of many means, each from a sample of 4 students? Would the shape be right-skewed, Normal, or left-skewed?

Short Answer

Expert verified
a. \(\mu=22.8\), \(\sigma=3.2\), \(\bar{x}=23.2\), \(s=2.4\).\n b. \(\mu\) is a parameter.\n c. The conditions for using the CLT are not fulfilled because using the CLT requires a much larger sample size. The distribution shape would be right-skewed, as it mirrors the shape of the population distribution.

Step by step solution

01

Identifying the Variables

\(\mu\), the population mean, is the average age of all students at the college. Here, \(\mu = 22.8\) years. \ \(\sigma\), the population standard deviation, is a measure of the distribution's spread. It's given as \(\sigma = 3.2\) years. \ \(\bar{x}\), the sample mean, is the average age of sampled students. In this instance, \(\bar{x} = 23.2\). \ \(s\), the sample standard deviation, provides an idea of the dispersion of the sample ages, with \(s = 2.4\) years.
02

Parameter or Statistic

\(\mu\) is a parameter because it is a numerical characteristic of the population.
03

Applying the Central Limit Theorem

The Central Limit Theorem (CLT) states that for a random sample drawn from any population with finite standard deviation, the sampling distribution of the mean will approximate a normal distribution as the sample size becomes large (usually n>30). Here, however, even though the total of students is large (2550), the sample size is only four, which is below the general threshold. Hence, the CLT does not apply here. Consequently, the sampling distribution of many means from a sample of 4 students would be approximately the same shape as the population distribution, which is right-skewed.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Population Mean
The population mean, denoted as \( \mu \), represents the average of a complete set of data. In our exercise, the population mean \( \mu \) is the average age of all 2550 students at the college, calculated to be \( 22.8 \) years. When we talk about the population mean, it's important to recognize that it encompasses every individual's age in the group. Because it includes every student's age, the population mean is classified as a parameter. A parameter is a value that describes a characteristic of a population, being a fixed and constant measure. It is different from statistics, which are calculated from samples and can vary. In our example, since the population mean value is derived from the total student body, it provides a comprehensive picture of the general age in the college environment.
Diving into Sample Mean
The sample mean, denoted as \( \bar{x} \), is the average of a subset chosen from the larger population. In this exercise, the sample mean was determined by finding the average age of only four students. The calculated sample mean is \( 23.2 \) years. A sample mean is a statistic, which means it is derived from a smaller group sampled from the population. Unlike parameters, statistics can vary across different samples. For instance, if you randomly picked another set of students, their average age might differ from \( 23.2 \) years. Sample means are useful to identify characteristics within a subset of the broader population. They provide insights into what might be true for the larger group without having to evaluate the entire population.
Exploring Sampling Distribution
Sampling distribution refers to the probability distribution of a statistic based on a large number of samples drawn from a specific population. It describes the variation of sample means if you were to take many samples. The Central Limit Theorem (CLT) plays a crucial role here. It states that the sampling distribution of the mean will approximate a normal distribution as the sample size becomes sufficiently large. In general, a sample size of over 30 is deemed sufficient to apply the CLT. In this exercise, the sample size was only 4, which is quite small. Due to this, the shape of the sampling distribution will mirror the population's right-skewed distribution rather than a normal distribution since the CLT conditions are not fulfilled. Essentially, for smaller samples, the shape of the sampling distribution will closely follow that of the population from which the samples are drawn.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The final exam grades for a sample of daytime statistics students and evening statistics students at one college are reported. The classes had the same instructor, covered the same material, and had similar exams. Using graphical and numerical summaries, write a brief description about how grades differ for these two groups. Then carry out a hypothesis test to determine whether the mean grades are significantly different for evening and daytime students. Assume that conditions for a \(t\) -test hold. Select your significance level. Daytime grades: \(100,100,93,76,86,72.5,82,63,59.5,53,79.5\), \(67,48,42.5,39\) Evening grades: \(100,98,95,91.5,104.5,94,86,84.5,73,92.5\), \(86.5,73.5,87,72.5,82,68.5,64.5,90.75,66.5\)

If you take samples of 40 lines from a random number table and find that the confidence interval for the proportion of odd-numbered digits captures \(50 \% 37\) times out of the 40 lines, is it the confidence interval or confidence level you are estimating with the 37 out of \(40 ?\)

A study of all the students at a small college showed a mean age of \(20.7\) and a standard deviation of \(2.5\) years. a. Are these numbers statistics or parameters? Explain. b. Label both numbers with their appropriate symbol (such as \(\bar{x}, \mu, s\), or \(\sigma)\).

A random sample of 10 independent healthy people showed the following body temperatures (in degrees Fahrenheit): $$98.5,98.299 .0,96.3,98.3,98.7,97.2,99.1,98.7,97.2$$ Test the hypothesis that the population mean is not \(98.6^{\circ} \mathrm{F}\), using a significance level of \(0.05 .\) See page 500 for guidance.

The weights of four randomly chosen bags of horse carrots, each bag labeled 20 pounds, were \(20.5,19.8,20.8\), and \(20.0\) pounds. Assume that the distribution of weights is Normal. Find a \(95 \%\) confidence interval for the mean weight of all bags of horse carrots. Use technology for your calculations. a. Decide whether each of the following three statements is a correctly worded interpretation of the confidence interval, and fill in the blanks for the correct option(s). i. \(95 \%\) of all sample means based on samples of the same size will be between _____ and _____. ii. I am \(95 \%\) confident that the population mean is between _____ and _____. iii. We are \(95 \%\) confident that the boundaries are _____ and _____. b. Can you reject a population mean of 20 pounds? Explain.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.