/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 89 A Quinnipiac poll conducted on F... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A Quinnipiac poll conducted on February 20 , 2018 , found that 824 people out of 1249 surveyed favored stricter gun control laws. A survey conducted one week later on February 28 , 2018 , by National Public Radio found that 754 out of 1005 people surveyed favored stricter gun control laws. a. Find both sample proportions and compare them. b. Test the hypothesis that the population proportions are not equal at the \(0.05\) significance level. c. After conducting the hypothesis test, a further question one might ask is what is the difference between the two population proportions? Find a \(95 \%\) confidence interval for the difference between the two proportions and interpret it. How does the confidence interval support the hypothesis test conclusion?

Short Answer

Expert verified
a) The sample proportions are \(0.6597\) for Quinnipiac poll and \(0.7502\) for National Public Radio. b) Following the hypothesis test, we reject the null hypothesis and conclude that there is a significant difference in the proportions. c) A \(95 \%\) confidence interval for the difference between proportions is \((-0.1286, -0.0523)\), indicating a significant difference, which supports our hypothesis test conclusion.

Step by step solution

01

Calculation of Sample Proportions

Calculate two sample proportions:\n For Quinnipiac poll, \(p_1 = \frac{824}{1249} = 0.6597\)\n For National Public Radio, \(p_2 = \frac{754}{1005} = 0.7502\)
02

Hypothesis Testing

Null Hypothesis \(H_0\): The population proportions are equal i.e., \(p_1 = p_2\).\nAlternative Hypothesis \(H_1\): The population proportions are not equal i.e., \(p_1 ≠ p_2\).\n\nFirst calculate the pooled sample proportion (\(p\)) and standard error (SE):\n\(p = \frac{824+754}{1249+1005} = 0.7041\)\nSE = \sqrt{p(1-p)(\frac{1}{1249}+\frac{1}{1005})} = 0.0193\n\nThen compute the z-score:\n\(z = \frac{(p_1 - p_2)}{SE} = -4.6890\n\nAt 5% significance level, the critical value for a two–tailed test from the standard normal table is approximately ±1.96. Since our calculated z score of -4.68 is less than -1.96, we reject the null hypothesis and conclude that there is a significant difference in the proportions.
03

Building 95% Confidence Interval

We compute the difference \(\delta = p_1 - p_2 = -0.0905\), and using the SE computed in step 2, the \(95 \%\) confidence interval for the difference between the two proportions would be \((\delta - 1.96 \cdot SE, \delta + 1.96 \cdot SE)\), which simplifies into \((-0.1286, -0.0523)\).\nBecause this confidence interval does not contain zero, it means that the difference between the two population proportions is statistically significant, and this supports our hypothesis test conclusion from step 2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportions
Sample proportions are estimates of the proportion of individuals in a sample who exhibit a particular trait. They are crucial in the field of statistics when determining the likelihood or proportion of a characteristic within a population, based on sample data. Here's how they work:
  • To find a sample proportion, divide the number of people exhibiting a trait by the total number of people in the sample.
  • In our exercise, the sample proportions were calculated for two surveys: one by Quinnipiac and another by National Public Radio.
For the Quinnipiac poll, the sample proportion, denoted as \(p_1\), was computed by dividing 824 (those in favor of stricter gun laws) by 1249 (total surveyed). This results in \(p_1 = 0.6597\).

Similarly, the National Public Radio survey yielded \(p_2 = \frac{754}{1005} = 0.7502\).

These sample proportions help in comparing how different samples relate to a broader population. Differences in sample proportions hint at possible differences in opinions between groups.
Confidence Interval
A confidence interval is a range of values that is used to estimate the true value of a population parameter. It provides an interval within which we are confident the true parameter lies. When constructing a confidence interval for the difference between two sample proportions, here's what you need to know:
  • The confidence level (like 95%) signifies the degree of certainty that the interval contains the true difference.
  • In the exercise, the computed sample difference \(\delta = p_1 - p_2 = -0.0905\), represents the estimated difference between the two proportions.
  • The confidence interval for this difference, computed using the standard error (SE), was \((-0.1286, -0.0523)\).
This interval tells us that we are 95% confident that the true difference between the population proportions falls between \(-0.1286\) and \(-0.0523\). Because zero is not within this range, it supports the idea that there is a significant difference between the two proportions. Thus, this confidence interval reinforces the decision from the hypothesis test to reject the null hypothesis.
Population Proportions
Population proportions are a statistical measure expressed as a fraction or percentage that describes the size of a group relative to the total population. Understanding these helps us make generalizations from samples to a whole population. Key points include:
  • Estimating population proportions often hinges on sample data, as entire population data can be impractical to collect.
  • In hypothesis testing, we assume population proportions to verify whether differences in samples reflect actual differences in the population or just occur by chance.
In the provided exercise, the hypothesis test examined whether the population proportions from two different times and samples were equal. The null hypothesis \(H_0\) presupposed no difference \((p_1 = p_2)\), while the alternative hypothesis \(H_1\) posited a difference \((p_1 eq p_2)\).

After finding the pooled sample proportion and conducting further calculations, we discovered a significant difference, leading us to reject the null hypothesis. Understanding and testing population proportions is essential in making informed decisions based on sample data, as illustrated by the survey results on gun control opinions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The mother of a teenager has heard a claim that \(25 \%\) of teenagers who drive and use a cell phone reported texting while driving. She thinks that this rate is too high and wants to test the hypothesis that fewer than \(25 \%\) of these drivers have texted while driving. Her alternative hypothesis is that the percentage of teenagers who have texted when driving is less than \(25 \%\).$$\begin{aligned} &\mathrm{H}_{0}: p=0.25 \\\&\mathrm{H}_{\mathrm{a}}: p<0.25\end{aligned}$$ She polls 40 randomly selected teenagers, and 5 of them report having texted while driving, a proportion of \(0.125 .\) The p-value is \(0.034\). Explain the meaning of the p-value in the context of this question.

A magazine advertisement claims that wearing a magnetized bracelet will reduce arthritis pain in those who suffer from arthritis. A medical researcher tests this claim with 233 arthritis sufferers randomly assigned either to wear a magnetized bracelet or to wear a placebo bracelet. The researcher records the proportion of each group who report relief from arthritis pain after 6 weeks. After analyzing the data, he fails to reject the null hypothesis. Which of the following are valid interpretations of his findings? There may be more than one correct answer. a. The magnetized bracelets are not effective at reducing arthritis pain. b. There's insufficient evidence that the magnetized bracelets are effective at reducing arthritis pain. c. The magnetized bracelets had exactly the same effect as the placebo in reducing arthritis pain. d. There were no statistically significant differences between the magnetized bracelets and the placebos in reducing arthritis pain.

Dolly the Sheep, the world's first mammal to be cloned, was introduced to the public in 1997. In a Pew Research poll taken soon after Dolly's debut, \(63 \%\) of Americans were opposed to the cloning of animals. In a Pew Research poll taken 20 years after Dolly, \(60 \%\) of those surveyed were opposed to animal cloning. Assume this was based on a random sample of 1100 Americans. Does this survey indicate that opposition to animal cloning has declined since \(1997 ?\) Use a \(0.05\) significance level.

Choose one of the answers given. The null hypothesis is always a statement about a ______ (sample statistic or population parameter).

A friend claims he can predict how a six-sided die will land. The parameter, \(p\), is the long-run likelihood of success, and the null hypothesis is that the friend is guessing. a. Pick the correct null hypothesis. i. \(p=1 / 6\) ii. \(p>1 / 6\) iii. \(p<1 / 6 \quad\) iv. \(p>1 / 2\) b. Which hypothesis best fits the friend's claim? (This is the alternative hypothesis.) i. \(p=1 / 6\) ii. \(p>1 / 6\) iii. \(p<1 / 6 \quad\) iv. \(p>1 / 2\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.