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Pew Research conducts polls on social media use. In \(2012,66 \%\) of those surveyed reported using Facebook. In 2018 , \(76 \%\) reported using Facebook. a. Assume that both polls used samples of 100 people. Do a test to see whether the proportion of people who reported using Facebook was significantly different in 2012 and 2018 using a \(0.01\) significance level. b. Repeat the problem, now assuming the sample sizes were both 1500 . (The actual survey size in 2018 was \(1785 .\) ) c. Comment on the effect of different sample sizes on the p-value and on the conclusion.

Short Answer

Expert verified
The conclusions drawn regarding the comparison of proportions depend greatly on the p-values. The p-values, in turn, can be heavily affected by the sample size.

Step by step solution

01

Set up the Null and Alternative Hypotheses

For a comparison of two proportions, the null hypothesis \(H_0\) is typically set to state that the proportions are equal, while the alternative hypothesis \(H_a\) states that the proportions are not equal. Here, \(P_1\) represents the proportion of people who reported using Facebook in 2012 and \(P_2\) represents the proportion in 2018. The hypotheses can be formulated as follows: \[H_0: P_1 = P_2\] for the null hypothesis and \[H_a: P_1 \neq P_2\] for the alternative hypothesis.
02

Calculate the Proportions and Test Statistic

For the first part with a sample size of 100, the proportions are \(P_1 = 0.66\) and \(P_2 = 0.76\). The pooled proportion would be equal to the total number of successes divided by the total sample size. The test statistic (Z) is calculated using the formula: \[Z = \frac{(P_1 - P_2) - 0}{\sqrt{P(1-P)(\frac{1}{n_1} + \frac{1}{n_2})}}\] where \(P\) is the pooled proportion and \(n_1\) and \(n_2\) are the sample sizes.
03

Calculate the p-value

The p-value can be found by looking up the calculated Z value in a standard normal distribution table and remembering that the p-value is double for a two-sided test.
04

Make a Decision

The decision about the null hypothesis is based on the p-value. If the p-value is less than the significance level (0.01), the null hypothesis is rejected. If the p-value is greater than the significance level, there's insufficient evidence to reject the null hypothesis.
05

Repeat for Larger Sample Size

Repeat steps 2 to 4 for the larger sample size of 1500, calculating new proportions and a new test statistic value.
06

Discuss the Effect of Sample Size

Discuss how the p-value and the conclusion of the test changes with the change in sample size from 100 to 1500.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportions
In hypothesis testing, proportions represent the parts of a whole that exhibit a certain characteristic or outcome. For instance, the problem at hand compares two proportions. Here, the proportions describe the percentage of people who reported using Facebook in two different years: 2012 and 2018.
To calculate these proportions, we simply divide the number of successes (people in the survey who use Facebook) by the total number of individuals surveyed. For 2012, the proportion is represented mathematically as \( P_1 = 0.66 \), meaning 66% of the sample was using Facebook. Similarly, for 2018, the proportion is \( P_2 = 0.76 \), implying a 76% usage rate.
In comparing these proportions, it's essential to determine whether or not there is a significant difference between them. This is what the hypothesis test aims to resolve.
Sample Size
Sample size is critical in hypothesis testing because it affects the accuracy and reliability of the results. In the exercise, two different sample sizes are considered: 100 and 1500.
A larger sample size tends to give more reliable estimates of the population parameter, which reduces variability and provides a clearer distinction between proportions if a real difference exists. For a sample of 100, estimate variability is relatively high, which can sometimes lead to less confidence in claiming a real difference between the population proportions.
Conversely, when the sample size is increased to 1500, the standard error decreases. This means the calculated test statistic becomes more stable, yielding a more precise p-value. - Greater sample sizes reduce the margin of error. - Larger samples give more power to detect a true effect. - In this problem, the shift from 100 to 1500 samples significantly alters the conclusions you might draw from the data.
P-value
The p-value is central in deciding whether to reject or fail to reject a null hypothesis. It indicates the probability that the observed data, or something more extreme, would occur if the null hypothesis were true.
In our scenario, the test statistic derived from the proportions is used to calculate the p-value. A smaller p-value signifies that, if the null hypothesis were true, the observed difference in proportions is unlikely. For smaller samples, this p-value is generally larger because of higher variability and less certainty.
The computation of a p-value also considers the type of test being performed. A two-tailed test, for example, captures the probability of a difference in either direction, doubling the p-value from a one-tailed test.
- If the p-value is less than the significance level, reject the null hypothesis. - A small p-value (<0.01) usually indicates strong evidence against the null hypothesis.
Significance Level
The significance level, often denoted by \( \alpha \), represents the threshold for determining whether the p-value indicates enough evidence to reject the null hypothesis. In this problem, a 0.01 significance level is used.
Choosing a significance level is crucial because it balances the risk of making a Type I error (incorrectly rejecting the null hypothesis) with the ability to detect true differences. Common significance levels are 0.05, 0.01, and 0.10, with a lower significance level indicating more stringent criteria for rejecting the null hypothesis.
Here, no statistically significant difference between the two proportions is found unless the p-value falls below 0.01. This level of significance implies a 1% risk of concluding that a difference exists when there isn't one, ensuring a high level of confidence in the test's conclusions.

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Most popular questions from this chapter

A proponent of a new proposition on a ballot wants to know the population percentage of people who support the bill. Suppose a poll is taken, and 580 out of 1000 randomly selected people support the proposition. Should the proponent use a hypothesis test or a confidence interval to answer this question? Explain. If it is a hypothesis test, state the hypotheses and find the test statistic, p-value, and conclusion. Use a \(5 \%\) significance level. If a confidence interval is appropriate, find the approximate \(95 \%\) confidence interval. In both cases, assume that the necessary conditions have been met.

In problem \(8.15\) the nutritionist was interested in knowing if the rate of vegetarianism in American adults has increased. She carried out a hypothesis test and found that the observed value of the test statistic was \(2.77 .\) We can calculate that the p-value associated with this is \(0.0028\), which is very close to 0\. Explain the meaning of the p-value in this context. Based on this result, should the nutritionist believe the null hypothesis is true?

According to the Bureau of Labor Statistics, \(10.1 \%\) of Americans are self- employed. A researcher wants to determine if the self-employment rate in a certain area is different. She takes a random sample of 500 working residents from the area and finds that 62 are self-employed. a. Test the hypothesis that the proportion of self-employed workers in this area is different from \(10.1 \%\). Use a \(0.05\) significance level. b. After conducting the hypothesis test, a further question one might ask, "What proportion of workers in this area are self-employed?" Use the sample data to find a \(95 \%\) confidence interval for the proportion of workers who are self-employed in the area from which the sample was drawn. How does this confidence interval support the hypothesis test conclusion?

Suppose you tested 50 coins by flipping each of them many times. For each coin, you perform a significance test with a significance level of \(0.05\) to determine whether the coin is biased. Assuming that none of the coins is biased, about how many of the 50 coins would you expect to appear biased when this procedure is applied?

A Gallup poll asked a random samples of Americans in 2016 and 2018 if they were satisfied with the quality of the environment. In 2016 , 543 were satisfied with the quality of the environment and 440 were dissatisfied. In 2018,461 were satisfied and 532 were dissatisfied. Determine whether the proportion of Americans who are satisfied with the quality of the environment has declined. Use a \(0.05\) significance level.

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