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A Gallup poll asked college students in 2016 and again in 2017 whether they believed the First Amendment guarantee of freedom of the press was secure or threatened in the country today. In 2016,2489 out of 3072 students surveyed said that freedom of the press was secure or very secure. In 2017,1808 out of 2014 students surveyed felt this way. a. Determine whether the proportion of college students who believe that freedom of the press is secure or very secure in the country changed from \(2016 .\) Use a significance level of \(0.05\). b. Use the sample data to construct a \(95 \%\) confidence interval for the difference in the proportions of college students in 2016 and 2017 who felt freedom of the press was secure or very secure. How does your confidence interval support your hypothesis test conclusion?

Short Answer

Expert verified
Validity of the claim that proportion of college students who believe that freedom of the press is secure changed from 2016 to 2017 can be determined by performing two-tailed hypothesis test and comparing it with the \(95\%\) confidence interval for difference in proportions. If both results match, then the claim is supported.

Step by step solution

01

State the Hypotheses

The null hypothesis (H0) is that the proportion of students believing in press freedom in 2016 and 2017 is same, i.e., \(p_{2016}\) = \(p_{2017}\). The alternative hypothesis (Ha) is that the proportions are not equal i.e., \(p_{2016}\) ≠ \(p_{2017}\).
02

Calculate Proportions and Difference

First, calculate proportions using number of students who believed in freedom of press over total students surveyed for both years. For 2016, \(p_{2016}\) = \(\frac{2489}{3072}\), and for 2017, \(p_{2017}\) = \(\frac{1808}{2014}\). Then calculate the difference: \(d = p_{2016} - p_{2017}\).
03

Hypothesis Testing

Compute the test statistic and the P-value to check against the significance level (\(0.05\)). If the P-value is less than the significance level, we reject the null hypothesis.
04

Calculate Confidence Interval

Calculate the \(95\%\) confidence interval for the difference in the proportions using the formula: \([d - Z(\frac{1 - \text{confidence level}}{2})\sqrt{\frac{p_{2016}(1-p_{2016})}{n_{2016}} + \frac{p_{2017}(1-p_{2017})}{n_{2017}}},\newline d + Z(\frac{1 - \text{confidence level}}{2})\sqrt{\frac{p_{2016}(1-p_{2016})}{n_{2016}} + \frac{p_{2017}(1-p_{2017})}{n_{2017}}})\] , where \(Z(\) is critical value from z-table. If the CI contains 0, it supports our hypothesis test conclusion.
05

Compare and Conclude

Interpret the confidence interval and compare it with the result from Hypothesis test to validate the claim. If the results from hypothesis test and confidence interval match, conclude that the analysis supports the hypothesis test conclusion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Significance
Understanding statistical significance is crucial when analyzing data and drawing conclusions from it. In hypothesis testing, we try to determine whether the observed effect in our sample data is likely to reflect an actual effect in the population or if it's just a result of sample variability.

Consider a scenario where we're comparing the opinions of college students in two different years to see if there's been a change in their perception of press freedom. To assert that the observed change is statistically significant, we use a significance level, often denoted as \(\alpha\). Commonly, a level of \(0.05\) (or 5%) is chosen, which implies that we would expect our results to occur by random chance only 5% of the time if the null hypothesis were true.

During hypothesis testing, if the computed P-value is less than the chosen significance level (\(\alpha\)), we have enough evidence to reject the null hypothesis. This means that it is statistically unlikely that the observed difference between the 2016 and 2017 student opinions occurred by chance, hence indicating a real change in perception.
Confidence Intervals
A confidence interval gives us a range of values within which we expect the true population parameter to fall, with a certain level of confidence. When constructing a \(95\%\) confidence interval for the difference in proportions, as seen in the exercise with the college students' opinions over two years, the interval provides the plausible range for the difference in population proportions.

Here's what a \(95\%\) confidence interval tells us: If we were to take many random samples from the population and calculate the \(95\%\) confidence interval for each sample, then approximately \(95\%\) of these intervals will contain the true difference in population proportions.

A key thing to note is that if the \(95\%\) confidence interval includes zero, it suggests that the true difference between the two population proportions might be zero—implying no evidence of a significant change. This conclusion would be consistent with failing to reject the null hypothesis in our statistical test.
Gallup Poll Data Analysis
Gallup poll data is an example of how sampling can be used to gauge public opinion. In the case of analyzing the security of the freedom of the press as perceived by college students, it’s important to conduct data analysis carefully to ensure accurate conclusions.

First, data is collected via surveys as done in 2016 and 2017. The responses are then used to calculate proportions of students with a certain opinion. When the results from these two different years are compared by testing hypotheses and constructing confidence intervals, analysts can make inferences about the population's perspective and its changes over time.

It's important, however, to remember that the accuracy of these inferences depends on several factors such as sample size, sampling method, and how well the sample represents the population. In the given exercise, the data from the Gallup poll enables us to not only test hypotheses but also to gain insights into the confidence we have regarding changes in student opinions by using confidence intervals.

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Most popular questions from this chapter

If we reject the null hypothesis, can we claim to have proved that the null hypothesis is false? Why or why not?

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