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The 2017 Chapman University Survey of American Fears asked a random sample of 1207 adults Americans if they believed that aliens had come to Earth in modern times, and \(26 \%\) responded yes. a. What is the standard error for this estimate of the percentage of all Americans who believe that aliens have come to Earth in modern times? b. Find a \(95 \%\) confidence interval for the proportion of all Americans who believe that aliens have come to Earth in modern times. c. What is the margin of error for the \(95 \%\) confidence interval? d. A similar poll conducted in 2016 found that \(24.7 \%\) of Americans believed aliens have come to Earth in modern times. Based on your confidence interval, can you conclude that the proportion of Americans who believe this has increased since 2016 ?

Short Answer

Expert verified
The solution includes the standard error, the confidence interval, the margin of error, and a comparison with previous year's data. Depending on the results of the calculations, a specific conclusion will be drawn on whether there was a significant increase in the belief from 2016 to 2017 or not.

Step by step solution

01

Calculate the Standard Error

The standard error (SE) of a proportion is given by: \[ SE = \sqrt{ (p × (1 - p)) / n } \] Where \(p\) is the proportion (or percentage in this case, so \( p = 0.26 \)) and \(n\) = 1207. Substituting these values into the formula, calculate SE.
02

Construct Confidence Interval

The 95% confidence interval is found using the formula: \[ CI = p ± ( z*SE ) \] Where \(z\) =1.96 (which corresponds to 95% confidence level) and \(SE\) is the standard error calculated in step 1. Substitute these values into the formula and calculate the interval.
03

Calculate Margin of Error

The Margin of Error (MOE) is given by the formula: \[ MOE = z * SE \] Where \(z\) = 1.96 (corresponding to 95% confidence level) and \(SE\) is the standard error calculated in step 1. Substitute these values into the formula and calculate MOE.
04

Compare with Previous Poll

Assess whether the 2016 poll result of 0.247 falls within the 95% confidence interval calculated in step 2. If it does, we cannot conclude that there has been a significant increase. If it falls outside the interval, then we can conclude that there has been a significant increase.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Error
Imagine you're trying to measure the accuracy of a basketball player's shooting percentage from the free-throw line. To ensure the estimate is reliable, you don't just look at one game, but several. In statistics, when we want to understand how accurate an estimate of a population parameter, like a proportion, is based on sample data, we use something called the standard error (SE).

The smaller the standard error, the closer our sample estimate is likely to be to the true population proportion. It’s like having a basketball player who consistently scores around the same percentage in every game – this player's shooting percentage has a small 'standard error'.

In the context of the survey on American's belief in alien visits, the standard error is mathematically represented by the formula \[ SE = \sqrt{ (p \times (1 - p)) / n } \] In simpler words, the standard error combines the estimated proportion (\(p\)) and the number of people asked (\(n\)) to give an idea about the 'spread' or 'variability' of the estimate.
Margin of Error
Now, think of the margin of error as the 'wiggle room' for our basketball player’s shooting percentage. It tells us how much the percentage could vary while still being considered accurate. In statistical terms, the margin of error gives us a range around our sample statistic — such as the proportion estimate of Americans who believe in extraterrestrial visits — within which we can be fairly confident that the true population statistic lies.

The margin of error can be calculated using the formula \[ MOE = z * SE \] where \(z\) is a value that corresponds to the desired confidence level (for 95% confidence, \(z = 1.96\)), and SE is the standard error you've calculated. With a smaller margin of error, we have a more precise estimate. It's like saying, our basketball player’s true shooting percentage is within a couple of points from what we’ve observed in the sample games.
Proportion Estimate
Returning to our basketball metaphor, let's say our player’s observed shooting percentage over the sample games represents an estimate of their true ability over all games. Similarly, in statistics, the proportion estimate refers to the estimated percentage of a population displaying a certain characteristic, based on sample data.

In the survey about beliefs in alien visits, 26% of the sampled American adults said 'yes', they do believe. This 26% is our proportion estimate (\(p\)). It's essential to understand that while this estimate provides an insight, it's still subject to sampling variability—which is why calculating the standard error and the margin of error is so crucial for getting a full picture of what the true proportion could be across all Americans.
Statistical Significance
Imagine if our basketball player has been training hard and you want to see if the training has made a significant difference in his shooting percentage. After collecting new data, you'd compare it to his old performance stats to make a judgment. In statistics, determining if a difference is not due to random chance but is statistically significant follows a similar principle.

It involves comparing a sample statistic, such as the proportion of people in 2017 who believe in alien visits, to another value or a previous study's findings, like the 2016 survey result. Using the calculated confidence interval, if the value from the previous study doesn't fall within the new confidence interval, it suggests that the change is statistically significant–indicating a real shift in beliefs between the years.

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Most popular questions from this chapter

Pew Research reported that \(46 \%\) of Americans surveyed in 2016 got their news from local television. A similar survey conducted in 2017 found that \(37 \%\) of Americans got their news from local television. Assume the sample size for each poll was 1200 . a. Construct the \(95 \%\) confidence interval for the difference in the proportions of Americans who get their news from local television in 2016 and 2017 . b. Based on your interval, do you think there has been a change in the proportion of Americans who get their news from local television? Explain.

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