/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 107 From Formula \(7.2\), an estimat... [FREE SOLUTION] | 91Ó°ÊÓ

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From Formula \(7.2\), an estimate for margin of error for a \(95 \%\) confidence interval is \(m=2 \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\) where \(\mathrm{n}\) is the required sample size and \(\hat{p}\) is the sample proportion. Since we do not know a value for \(\hat{p}\), we use a conservative estimate of \(0.50\) for \(\hat{p}\). Replace \(\hat{p}\) with \(0.50\) in the formula and simplify.

Short Answer

Expert verified
The simplified formula for margin of error is \(m= \sqrt{\frac{1}{n}}\).

Step by step solution

01

Substitution

Replace the symbol \(\hat{p}\) in the formula with the conservative estimate of 0.50: \(m=2 \sqrt{\frac{(0.50)(1-0.50)}{n}}\)
02

Simplification

Simplify the fraction inside the square root: \(m=2 \sqrt{\frac{(0.50)(0.50)}{n}} = 2 \sqrt{\frac{0.25}{n}}\
03

Further Simplification

Factor out the square of 0.5 from under the square root sign to simplify further: \(m=2 \cdot 0.5 \sqrt{\frac{1}{n}} = \sqrt{\frac{1}{n}}\)
04

Conclusion

The simplified formula for margin of error is \(m= \sqrt{\frac{1}{n}}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
Understanding confidence intervals is crucial when working with statistics, especially in estimating population parameters. A confidence interval provides a range of values, typically centered around a sample statistic, that is believed to contain the true population parameter. Imagine you're trying to measure the average height of trees in a large forest. You can't measure them all, but you take a sample and find the average height within this sample. The confidence interval gives you a range that you're 95% confident includes the true average height of all trees in the forest.

When we talk about a 95% confidence interval, we imply that if we were to take 100 different samples and compute a confidence interval for each sample, approximately 95 out of those 100 intervals would contain the true population parameter. It's a way of expressing certainty—or rather uncertainty—about our estimates. In the original exercise, the 95% confidence interval's margin of error is calculated using a formula that takes into account the sample proportion and size. By using these calculations, researchers can state with a certain degree of confidence that the true value lies within the specified interval.
Sample Size
Sample size, denoted as 'n' in statistical formulas, is essentially the number of observations or replicates included in a statistical sample. It's one of the foundational elements in any statistical analysis because it directly influences the precision of an estimate or the power of a hypothesis test.

For instance, let's say you're conducting a survey to understand the percentage of students who prefer online classes. If you survey only a handful of students, the generalizability of your findings will be questionable. Conversely, surveying a large proportion of the student population would give you more confidence that your findings accurately reflect the overall preference.

In the context of our exercise, the sample size affects the margin of error of our confidence interval: a larger sample size generally yields a smaller margin of error, meaning our estimate is more precise. Therefore, determining the right sample size is a balancing act between the desired precision and the resources available for the study.
Sample Proportion
Sample proportion, commonly represented by \(\hat{p}\), is a statistic that estimates the proportion of the population that exhibits a certain characteristic based on a sample drawn from that population. Essentially, it's the equivalent of a percentage for a specific attribute within your sample.

Let's imagine you're studying voting behaviors and want to estimate the proportion of people favoring a particular candidate. By polling a random group of voters, you calculate the sample proportion of voters supporting that candidate. If 60 out of 100 polled voters prefer your candidate, the sample proportion \(\hat{p}\) would be 0.60 or 60%.

In our original exercise, a conservative estimate of 0.50 is used for \(\hat{p}\) when the actual value is unknown. This is done because 0.50 maximizes the product \(\hat{p}(1-\hat{p})\), leading to the largest possible margin of error for a given sample size. This conservative approach ensures that the calculated confidence interval is wide enough to be likely to capture the true population parameter, regardless of the actual sample proportion.

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Most popular questions from this chapter

The city of San Francisco provides an open data set of commercial building energy use. Each row of the data set represents a commercial building. A sample of 100 buildings from the data set had a mean floor area of 32,470 square feet. Of the sample, \(28 \%\) were office buildings. a. What is the correct notation for the value 32,470 ? b. What is the correct notation for the value \(28 \%\) ?

The website scholarshipstats.com collected data on all 5341 NCAA basketball players for the 2017 season and found a mean height of 77 inches. Is the number 77 a parameter or a statistic? Also identify the population and explain your choice.

Two symbols are used for the mean: \(\mu\) and \(\bar{x}\). a. Which represents a parameter, and which a statistic? b. In determining the mean age of all students at your school, you survey 30 students and find the mean of their ages. Is this mean \(\bar{x}\) or \(\mu\) ?

According to a 2018 Pew Research report, \(40 \%\) of Americans read print books exclusively (rather than reading some digital books). Suppose a random sample of 500 Americans is selected. a. What percentage of the sample would we expect to read print books exclusively? b. Verify that the conditions for the Central Limit Theorem are met. c. What is the standard error for this sample proportion? d. Complete this sentence: We expect ____\(\%\) of Americans to read print books exclusively, give or take ______\(\%\) .

A 2017 survey of U.S. adults found that \(74 \%\) believed that protecting the rights of those with unpopular views is a very important component of a strong democracy. Assume the sample size was 1000 . a. How many people in the sample felt this way? b. Is the sample large enough to apply the Central Limit Theorem? Explain. Assume all other conditions are met. c. Find a \(95 \%\) confidence interval for the proportion of U.S. adults who believe that protecting the rights of those with unpopular views is a very important component of a strong democracy. d. Find the width of the \(95 \%\) confidence interval. Round your answer to the nearest tenth percent. e. Now assume the sample size was 4000 and the percentage was still \(74 \%\). Find a \(95 \%\) confidence interval and report the width of the interval. f. What happened to the width of the confidence interval when the sample size was increased? Did it increase or decrease?

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