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Assume a standard Normal distribution. Draw a separate, well-labeled Normal curve for each part. a. Find an approximate \(z\) -score that gives a left area of \(0.7000\). b. Find an approximate \(z\) -score that gives a left area of \(0.9500\).

Short Answer

Expert verified
The approximate \(z\)-scores that give a left area of \(0.7000\) and \(0.9500\) respectively are generally found to be \(0.52\) and \(1.65\), although some variations might be there based on the level of approximation.

Step by step solution

01

Finding the z-score for left area 0.7000

For the first part, you'll use the standard Normal distribution table or Z-table or modern statistical software to determine the \(z\)-score. This is done by looking up the area closest to \(0.7000\) in the body of the table and then finding the corresponding \(z\)-score.
02

Verifying z-score for left area 0.7000

After finding the z-score, verify it by ensuring that the area to the left of it on the standard Normal distribution curve is \(0.7000\), as per the problem's requirements.
03

Finding the z-score for left area 0.9500

For the second part, just like in step 1, you'll use the standard Normal distribution table or Z-table to find the \(z\)-score that gives a left-hand area of \(0.9500\). Again, this is done by looking up the area closest to \(0.9500\) in the body of the table and then finding the corresponding \(z\)-score.
04

Verifying z-score for left area 0.9500

After finding the z-score, verify it by ensuring that the area to the left of it on the standard Normal distribution curve is \(0.9500\), as per the problem's requirements.

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