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Babies in the United States have a mean birth length of \(20.5\) inches with a standard deviation of \(0.90\) inch. The shape of the distribution of birth lengths is approximately Normal. a. How long is a baby born at the 20 th percentile? b. How long is a baby born at the 50 th percentile? c. How does your answer to part b compare to the mean birth length? Why should you have expected this?

Short Answer

Expert verified
The length of a baby born at the 20th percentile is approximately 19.24 inches. The length of a baby born at the 50th percentile is 20.5 inches, which equals to the mean birth length. This outcome is expected as in a normal distribution, the mean, median (50th percentile) and mode are all equal.

Step by step solution

01

Calculate the length at the 20th percentile

To calculate the length at the 20th percentile, we need to use the standard normal distribution table or the Z-table. The 20th percentile corresponds approximately to a Z-score of -0.84. So the formula for calculating the length at the 20th percentile \(L_{20}\) would be \(L_{20}= \text{mean} + Z_{20} * \text{std_dev}\) where mean is 20.5, \(Z_{20}\) is -0.84, and std_dev is 0.9.
02

Calculate the length at the 50th percentile.

The same method applies to calculate the length at the 50th percentile. However, take note that the 50th percentile (median) corresponds to a Z-score of 0. Thus, the formula for calculating the length at the 50th percentile \(L_{50}\) would be \(L_{50} = \text{mean} + Z_{50}* \text{std_dev}\) where mean is 20.5, \(Z_{50}\) is 0, and std_dev is 0.9.
03

Comparing the calculated 50th percentile to the mean birth length.

Evaluate the results from step 2 and compare \(L_{50}\) with the given mean (20.5 inches). Also, justify the result theoretically.

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