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According to the 2017 SAT Suite of Assessments Annual Report, the average SAT math score for students in Illinois was 556. Assume the scores are Normally distributed with a standard deviation of 100 . Answer the following including an appropriately labeled and shaded Normal curve for each question. a. What percentage of Illinois Math SAT takers scored 600 or more? b. What percentage of Illinois Math SAT takers scored between 600 and 650 ? c. Suppose students who scored in the top \(5 \%\) of test takers in the state were eligible for a special scholarship program. What SAT math score would qualify students for this scholarship program?

Short Answer

Expert verified
a. 33% of Illinois Math SAT takers scored 600 or more. b. 16% of Illinois Math SAT takers scored between 600 and 650. c. A SAT math score of 720 would qualify students for the scholarship program.

Step by step solution

01

Calculating z-scores

Let's calculate z-scores for parts (a) and (b). This is done by subtracting the mean from the given raw score and dividing by the standard deviation. For a score of 600, the z-score is \((600 - 556) / 100 = 0.44\).
02

Finding the percentage for a score of 600 or more

In part (a), we're asked to find the percentage of students that scored 600 or more. We need to look up the z-score of 0.44 in a z-table. But since we're interested in the scores over 600, we want to know the area of the curve to the right of our z-score. Z-tables typically give the area to the left, so we need to calculate \(1 - P(z < 0.44)\), where \(P(z < 0.44)\) is the percentage that a z-table gives for 0.44, which is 0.67. So, \(1 - 0.67 = 0.33\), or 33%.
03

Finding the percentage for scores between 600 and 650

In part (b), it is asked to find the percentage of students that scored between 600 and 650. We already have the z-score for 600 which is 0.44. Let's calculate the z-score for 650, using the same method as in Step 1, we find it is \( (650 - 556) / 100 = 0.94 \). We look both z-scores in a z-table which gives us \(P(z < 0.44) = 0.67 \) and \(P(z < 0.94) = 0.83 \). We're interested in the area between these two z-scores, so we calculate \( 0.83 - 0.67 = 0.16 \), or 16%.
04

Finding the SAT score for the top 5%

In part (c), we're asked to find the SAT score for those in the top 5%. This is a reverse lookup in the z-table. First, we convert that percentage to a decimal and subtract from 1 because this is the 'top' 5%, resulting in 1 - 0.05 = 0.95. The z-score associated with 0.95 in the z-table is 1.645. Finally, we use this z-score to find the raw SAT score using the formula: score = mean + z * standard deviation which gives us \(556 + 1.645 * 100 = 719.5\). We can round this to 720.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
Understanding the normal distribution is essential for analyzing data that tends to cluster around a mean. Picture a bell-shaped curve that is symmetrical about its center, and you're envisioning a normal distribution. This curve represents how traits or test scores like the SAT math scores are spread across a population.

In the case of our exercise, the average SAT math score in Illinois is 556, and this average represents the peak of the bell curve. A key feature of the normal distribution is that about 68% of values fall within one standard deviation of the mean, 95% within two standard deviations, and nearly all (99.7%) within three standard deviations. This predictable pattern allows us to make informed statements about the distribution of SAT scores among Illinois students.
Z-scores
A z-score is like a mathematical translator; it takes a score from our normal distribution and translates it into how many standard deviations away from the mean that score is. It's a way of standardizing scores across different scales. The formula for a z-score is:
\( z = \frac{X - \mu}{\sigma} \)
where \( X \) is the raw score, \( \mu \) is the mean, and \( \sigma \) is the standard deviation. In our SAT math example, to find the percentage of students scoring 600 or above, we calculated the z-score of 600 which was 0.44. This means that a score of 600 is 0.44 standard deviations above the mean of 556.
Standard Deviation
Standard deviation is kind of like the ruler of the normal distribution; it tells you how spread out the scores are from the average. When the standard deviation is small, scores are tightly grouped around the mean, and when it's large, they are more spread out.

For the SAT math scores, we're dealing with a standard deviation of 100. That means that scores are, on average, about 100 points away from the mean score of 556. Knowing the standard deviation helps us determine the likelihood of a student scoring within certain ranges, such as within one standard deviation (556 to 656) or two standard deviations (456 to 756) from the mean.
SAT Score Percentile
Percentile ranks are a way to see how a student's SAT score compares to others. If a student's score is in the 60th percentile, for example, this means they scored better than 60% of students who took the test. It's a handy way to gauge where a score stands in the larger picture.

In our exercise, students scoring at or above the 95th percentile qualify for a special scholarship. To find this score, we looked at the z-score that corresponds to the 95th percentile, which then allowed us to calculate the minimum SAT math score needed for the scholarship. It turns out a student would need a score around 720 to be in that top 5%, a benchmark that can be instrumental in setting educational goals.

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Most popular questions from this chapter

Use technology or a Normal table to find each of the following. Include an appropriately labeled sketch of the Normal curve for each part with the appropriate area shaded. a. Find the probability that a \(z\) -score will be \(2.03\) or less. b. Find the probability that a \(z\) -score will be \(-1.75\) or more. c. Find the probability that a \(z\) -score will be between \(-1.25\) and \(1.40\).

Whales have one of the longest gestation periods of any mammal. According to whalefacts.org, the mean gestation period for a whale is 14 months. Assume the distribution of gestation periods is Normal with a standard deviation of \(1.2\) months. a. Find the standard score associated with a gestational period of \(12.8\) months. b. Using the Empirical Rule and your answer to part a, what percentage of whale pregnancies will have a gestation period between \(12.8\) months and 14 months? c. Would it be unusual for a whale to have a gestation period of 18 months? Why or why not?

Use the table or technology to find the answer to each question. Include an appropriately labeled sketch of the Normal curve for each part. Shade the appropriate region. A section of the Normal table is provided in the previous exercise. a. Find the area to the left of a \(z\) -score of \(0.92\). b. Find the area to the right of a z-score of \(0.92\).

Survey data, the distribution of arm spans for males is approximately Normal with a mean of \(71.4\) inches and a standard deviation of \(3.3\) inches. a. What percentage of men have arm spans between 66 and 76 inches? b. Professional basketball player, Kevin Durant, has an arm span of almost 89 inches. Find the \(z\) -score for Durant's arm span. What percentage of males have an arm span at least as long as Durant's?

The length of gestation for hippopotami is approximately Normal, with a mean of 270 days and a standard deviation of 7 days. a. What percentage of hippos have a gestation period less than 260 days? b. Complete this sentence: Only \(6 \%\) of hippos will have a gestational period longer than \(-\) days. c. In 2017 , Fiona the Hippo was born at the Cincinnati Zoo, 6 weeks premature. This means her gestational period was only about 228 days. What percentage of hippos have a gestational period of 228 days or less?

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