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According to the 2017 SAT Suite of Assessments Annual Report, the average SAT math score for students in Illinois was 556. Assume the scores are Normally distributed with a standard deviation of 100 . Answer the following including an appropriately labeled and shaded Normal curve for each question. a. What percentage of Illinois Math SAT takers scored 600 or more? b. What percentage of Illinois Math SAT takers scored between 600 and 650 ? c. Suppose students who scored in the top \(5 \%\) of test takers in the state were eligible for a special scholarship program. What SAT math score would qualify students for this scholarship program?

Short Answer

Expert verified
a. 33% of Illinois Math SAT takers scored 600 or more. b. 16% of Illinois Math SAT takers scored between 600 and 650. c. A SAT math score of 720 would qualify students for the scholarship program.

Step by step solution

01

Calculating z-scores

Let's calculate z-scores for parts (a) and (b). This is done by subtracting the mean from the given raw score and dividing by the standard deviation. For a score of 600, the z-score is \((600 - 556) / 100 = 0.44\).
02

Finding the percentage for a score of 600 or more

In part (a), we're asked to find the percentage of students that scored 600 or more. We need to look up the z-score of 0.44 in a z-table. But since we're interested in the scores over 600, we want to know the area of the curve to the right of our z-score. Z-tables typically give the area to the left, so we need to calculate \(1 - P(z < 0.44)\), where \(P(z < 0.44)\) is the percentage that a z-table gives for 0.44, which is 0.67. So, \(1 - 0.67 = 0.33\), or 33%.
03

Finding the percentage for scores between 600 and 650

In part (b), it is asked to find the percentage of students that scored between 600 and 650. We already have the z-score for 600 which is 0.44. Let's calculate the z-score for 650, using the same method as in Step 1, we find it is \( (650 - 556) / 100 = 0.94 \). We look both z-scores in a z-table which gives us \(P(z < 0.44) = 0.67 \) and \(P(z < 0.94) = 0.83 \). We're interested in the area between these two z-scores, so we calculate \( 0.83 - 0.67 = 0.16 \), or 16%.
04

Finding the SAT score for the top 5%

In part (c), we're asked to find the SAT score for those in the top 5%. This is a reverse lookup in the z-table. First, we convert that percentage to a decimal and subtract from 1 because this is the 'top' 5%, resulting in 1 - 0.05 = 0.95. The z-score associated with 0.95 in the z-table is 1.645. Finally, we use this z-score to find the raw SAT score using the formula: score = mean + z * standard deviation which gives us \(556 + 1.645 * 100 = 719.5\). We can round this to 720.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
Understanding the normal distribution is essential for analyzing data that tends to cluster around a mean. Picture a bell-shaped curve that is symmetrical about its center, and you're envisioning a normal distribution. This curve represents how traits or test scores like the SAT math scores are spread across a population.

In the case of our exercise, the average SAT math score in Illinois is 556, and this average represents the peak of the bell curve. A key feature of the normal distribution is that about 68% of values fall within one standard deviation of the mean, 95% within two standard deviations, and nearly all (99.7%) within three standard deviations. This predictable pattern allows us to make informed statements about the distribution of SAT scores among Illinois students.
Z-scores
A z-score is like a mathematical translator; it takes a score from our normal distribution and translates it into how many standard deviations away from the mean that score is. It's a way of standardizing scores across different scales. The formula for a z-score is:
\( z = \frac{X - \mu}{\sigma} \)
where \( X \) is the raw score, \( \mu \) is the mean, and \( \sigma \) is the standard deviation. In our SAT math example, to find the percentage of students scoring 600 or above, we calculated the z-score of 600 which was 0.44. This means that a score of 600 is 0.44 standard deviations above the mean of 556.
Standard Deviation
Standard deviation is kind of like the ruler of the normal distribution; it tells you how spread out the scores are from the average. When the standard deviation is small, scores are tightly grouped around the mean, and when it's large, they are more spread out.

For the SAT math scores, we're dealing with a standard deviation of 100. That means that scores are, on average, about 100 points away from the mean score of 556. Knowing the standard deviation helps us determine the likelihood of a student scoring within certain ranges, such as within one standard deviation (556 to 656) or two standard deviations (456 to 756) from the mean.
SAT Score Percentile
Percentile ranks are a way to see how a student's SAT score compares to others. If a student's score is in the 60th percentile, for example, this means they scored better than 60% of students who took the test. It's a handy way to gauge where a score stands in the larger picture.

In our exercise, students scoring at or above the 95th percentile qualify for a special scholarship. To find this score, we looked at the z-score that corresponds to the 95th percentile, which then allowed us to calculate the minimum SAT math score needed for the scholarship. It turns out a student would need a score around 720 to be in that top 5%, a benchmark that can be instrumental in setting educational goals.

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Most popular questions from this chapter

The distribution of red blood cell counts is different for men and women. For both, the distribution is approximately Normal. For men, the middle \(95 \%\) range from \(4.5\) to \(5.7\) million cells per microliter and for women, the middle \(95 \%\) have red blood cells counts between \(3.9\) and \(5.0\) million cells per microliter. a. What is the mean and the standard deviation of red blood cell counts for men? Explain your reasoning. b. What is the mean and the standard deviation of red blood cell counts for women? Explain your reasoning. c. Which gender shows more variation in red blood cell counts? Support your answer with appropriate statistics.

Rule with z-Scores The Empirical Rule applies rough approximations to probabilities for any unimodal, symmetric distribution. But for the Normal distribution we can be more precise. Use the figure and the fact that the Normal curve is symmetric to answer the questions. Do not use a Normal table or technology. According to the Empirical Rule, a. Roughly what percentage of \(z\) -scores are between \(-2\) and 2 ? i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) b. Roughly what percentage of \(z\) -scores are between \(-3\) and 3 ? i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) c. Roughly what percentage of \(z\) -scores are between \(-1\) and 1 . i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) d. Roughly what percentage of \(z\) -scores are greater than \(0 ?\) i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) e. Roughly what percentage of \(z\) -scores are between 1 and \(2 ?\) i. almost all iii. \(50 \%\) ii. \(13.5 \%\) iv. \(2 \%\)

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According to the Centers of Disease Control and Prevention, \(44 \%\) of U.S. households still had landline phone service. Suppose a random sample of 60 U.S. households is taken. a. Find the probability that exactly 25 of the households sampled still have a landline. b. Find the probability that more than 25 households still have a landline. c. Find the probability that at least 25 households still have a landline. d. Find the probability that between 20 and 25 households still have a landline.

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