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When a certain type of thumbtack is tossed, the probability that it lands tip up is \(60 \%\), and the probability that it lands tip down is \(40 \%\). All possible outcomes when two thumbtacks are tossed are listed. U means the tip is Up, and D means the tip is Down. \(\begin{array}{llll}\mathrm{UU} & \mathrm{UD} & \mathrm{DU} & \mathrm{DD}\end{array}\) a. What is the probability of getting exactly one Down? b. What is the probability of getting two Downs?

Short Answer

Expert verified
The probability of getting exactly one down is 0.48 and the probability of getting two downs is 0.16.

Step by step solution

01

Understand the Problem and Define the Probabilities

First, identify the probabilities of the individual outcomes. The probability of 'up' is 0.6 and the probability of 'down' is 0.4. Note that the events are independent, meaning the outcome of one thumbtack toss does not affect the outcome of the other.
02

Solve for Exactly One Down

To find the probability of exactly one down, realize that we have two situations where this can occur: UD or DU. The probabilities for these would be \((0.6 \times 0.4)\) and \((0.4 \times 0.6)\) respectively. Since these are mutually exclusive events, we can add the probabilities: \((0.6 \times 0.4) + (0.4 \times 0.6) = 0.24 + 0.24 = 0.48.\
03

Solve for Two Downs

To find the probability of getting two downs, simply multiply the probability of getting down on the first toss with the probability of getting down on the second, remembering that these are independent events: \((0.4 \times 0.4) = 0.16.\

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
When discussing probability, independent events are a fundamental concept to grasp. Two events are considered independent if the occurrence of one does not affect the probability of the other. In simpler terms, knowing the outcome of one event gives no information about the other.
Consider tossing each of two thumbtacks independently. The probability of one landing tip up or tip down does not influence the outcome of the other. This independence allows us to calculate probabilities for the combination of events by multiplying their individual probabilities.
  • The first thumbtack lands tip up with probability 0.6 or tip down with probability 0.4.
  • The second thumbtack is independent, so its probabilities remain the same: 0.6 for up and 0.4 for down.
Understanding independent events is crucial when calculating the probability of various combinations, as you'll see in probability calculation and problem-solving.
Mutually Exclusive Events
The concept of mutually exclusive events is another key component in probability theory. This term describes scenarios where two events cannot occur at the same time. If one occurs, the other cannot.
In our thumbtack exercise, when dealing with combinations such as UD and DU, they are mutually exclusive. If the first thumbtack lands down (D), having a second thumbtack also land down in the same trial is impossible under this description: each combination (like UD) represents a separate and unique outcome that doesn't overlap with another (like DU).
  • UD: First thumbtack up, second down
  • DU: First thumbtack down, second up
Predicting the precise outcome of a toss uses mutually exclusive events well. Thus, to find the probability of either happening, we add their probabilities together, vital for accurate calculations.
Probability Calculation
Probability calculation is an essential skill in understanding probabilities of complex events. It involves calculating the likelihood of different outcomes in a systematic approach.
To calculate probability effectively, it’s crucial to understand both independent and mutually exclusive events combined. Using our thumbtack example, when determining the probability of exactly one thumbtack landing down (for events UD and DU), you handle calculation as follows:
1. **Find individual probabilities** - Calculate the probability of each independent event. For instance, UD involves the probability of the first toss being up (0.6) and the second down (0.4): \[ P(UD) = 0.6 \times 0.4 = 0.24 \]
2. **Consider different orders for the same outcome** - The probability of DU is calculated similarly: \[ P(DU) = 0.4 \times 0.6 = 0.24 \]
3. **Add the probabilities for mutually exclusive events** - As UD and DU can't happen together, add their probabilities: \[ P(\text{Exactly one down}) = 0.24 + 0.24 = 0.48 \]
The same steps apply to finding two downs with calculations involving independent events only, showing how expertise in probability calculation is applied in problem-solving.

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