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Roll a fair six-sided die. a. What is the probability that the die shows an even number or a number greater than 4 on top? b. What is the probability the die shows an odd number or a number less than 3 on top?

Short Answer

Expert verified
Probability for (a) is 0.67 and for (b) is 0.67

Step by step solution

01

Define Even Numbers Greater Than 4

There are three even numbers on a six-sided die: 2, 4, and 6. Two numbers, namely 5 and 6, are greater than 4. Therefore, we have four unique favorable outcomes for part (a), which are: 2, 4, 5, 6.
02

Calculate the Probability For Part (a)

The probability of an event occurring is the number of favorable outcomes divided by the total number of outcomes. So, since there are 4 numbers that satisfy the condition (2, 4, 5, 6) and there are 6 total outcomes, the probability for part (a) is 4 / 6 = 0.67, or 67%.
03

Define Odd Numbers Less Than 3

There are three odd numbers on a six-sided die: 1, 3, and 5. Two numbers, namely 1 and 2, are less than 3. Therefore, we also have four unique favorable outcomes for part (b), which are: 1, 2, 3, 5.
04

Calculate the Probability For Part (b)

Following the similar step as in part (a), the probability for part (b) is also 4 / 6 = 0.67, or 67%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fair Six-Sided Die
The concept of a 'fair six-sided die' lies at the heart of probability exercises involving dice games. A fair die is one that is perfectly balanced, ensuring that each of its six faces—numbered 1 through 6—has an equal chance of landing face up when the die is rolled. This characteristic of fairness is essential for making probability calculations reliable, since it implies that no single outcome is more likely than another.

For any roll of a fair six-sided die, there are six possible outcomes, corresponding to the six faces. The chance of the die landing on any given number is therefore one in six, or approximately 16.67%. Understanding that each side has an equal probability of showing up is fundamental when calculating the chances of various events involving dice rolls.
Even and Odd Numbers
When dealing with dice, categorizing the numbers into even and odd is a common practice in probability. Even numbers can be evenly divided by 2, which on a six-sided die are 2, 4, and 6. In contrast, odd numbers are those that cannot be divided evenly by 2, corresponding to the faces showing 1, 3, and 5 on the die.

Recognizing the difference between even and odd numbers is critical in many probability problems, as these characteristics often define the set of 'favorable outcomes'. For example, when asked for the probability of rolling an even number, we know to only consider the three even faces out of the six possible outcomes, thus impacting the probability calculation.
Favorable Outcomes
In probability, 'favorable outcomes' refer to the specific results of an experiment or event that satisfy the condition(s) we are interested in. Identifying these outcomes is crucial to calculating probabilities. For instance, when rolling a die with the goal of getting an even number or a number greater than 4, the favorable outcomes would be 2, 4, 5, and 6.

It's important to note that when listing favorable outcomes, each outcome must be unique and distinct—duplicates don't count twice when calculating probabilities. Moreover, ensuring that the outcomes are relevant to the conditions specified by the question will help ascertain correct probabilities.
Calculating Probabilities
Calculating probabilities involves determining the chance of an event occurring out of all possible events. The basic formula used in most elementary probability situations is: \( P(E) = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Outcomes}} \), where \( P(E) \) is the probability of event \( E \) happening.

Returning to our die example, if we want to find the probability of rolling an even number or a number greater than 4, we identify that there are four favorable outcomes (2, 4, 5, 6) and six total possible outcomes. Hence, the probability is calculated as \( \frac{4}{6} \), which simplifies to \( \frac{2}{3} \) or approximately 67%. Understanding and applying this formula correctly is a key skill in probability and ensures that students can tackle a wide range of problems effectively.

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Most popular questions from this chapter

A famous study by Amos Tversky and Nobel laureate Daniel Kahneman asked people to consider two hospitals. Hospital \(\mathrm{A}\) is small and has 15 babies born per day. Hospital B has 45 babies born each day. Over one year, each hospital recorded the number of days that it had more than \(60 \%\) girls born. Assuming that \(50 \%\) of all babies are girls, which hospital had the most such days? Or do you think both will have about the same number of days with more than \(60 \%\) girls born? Answer, and explain. (Source: Tversky, Preference, belief, and similarity: Selected Writings, ed. [Cambridge, MA: MIT Press], 205)

A true/false test has 20 questions. Each question has two choices (true or false), and only one choice is correct. Which of the following methods is a valid simulation of a student who guesses randomly on each question. Explain. (Note: there might be more than one valid method.) a. Twenty digits are selected using a row from a random number table. Each digit represents one question on the test. If the number is even the answer is correct. If the number is odd, the answer is incorrect. b. A die is rolled 20 times. Each roll represents one question on the test. If the die lands on a 6 , the answer is correct; otherwise the answer is incorrect. c. A die is rolled 20 times. Each roll represents one question on the test. If the die lands on an odd number, the answer is correct. If the die lands on an even number, the answer is incorrect.

Probability For each of the values, state whether the number could be the probability of an event. Give a reason for your answers. a. \(99 \%\) b. \(0.9\) c. \(9.9\) d. \(0.0099\) e. \(-0.90\)

A certain professional basketball player typically makes \(80 \%\) of his basket attempts, which is considered to be good. Suppose you go to several games at which this player plays. Sometimes the player attempts only a few baskets, say, 10. Other times, he attempts about 60 . On which of those nights is the player most likely to have a "bad" night, in which he makes much fewer than \(80 \%\) of his baskets?

Some estimates say that \(10 \%\) of the population is left-handed. We wish to design a simulation to find an empirical probability that if five babies are born on a single day, one or more will be left-handed. Suppose we decide that the even digits \((0,2,4,\), 6,8 ) will represent left-handed babies and the odd digits will represent right-handed babies. Explain what is wrong with the stated simulation method, and provide a correct method.

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