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In the study referenced in exercise \(10.33\), researchers also collected data on use of apps to monitor diet and calorie intake. The data are reported in the table. Test the hypothesis that diet app use and gender are associated. Use a \(0.05\) significance level. $$ \begin{array}{ccc} \text { Use } & \text { Male } & \text { Female } \\ \text { Yes } & 43 & 241 \\ \text { No } & 50 & 84 \\ \hline\end{array}$$

Short Answer

Expert verified
Conduct a Chi-Square Test of Independence. Calculate expected counts, the Chi-Square test statistic, the degree of freedom and then determine the p-value. If the p-value is less than 0.05, reject the null hypothesis that there is no relationship between gender and use of diet apps.

Step by step solution

01

Table Organization

The data needs to be organized in a two-way table format. From the information provided, there are four categories: males who use the app, males who do not, females who use the app, and females who do not. The cell counts for these categories are 43, 50, 241, and 84 respectively.
02

Calculation of Expected Counts

Expected counts are calculated by using the formula \((row \ total*column \ total)/grand \ total\). For example, the expected count for males who use the app is \((93*284)/418 = 63.0\) (to one decimal place). Similar calculations can be made for all categories.
03

Chi-Square Test Statistic

Chi-square test statistic is calculated as the sum of \(\(\(\(\frac{(observed \ count - expected \ count)^2}{expected \ count}\)+\) for each cell in the table. For example, for males who use the app, this would be \((43 - 63)^2 / 63 = 6.3\) (to one decimal place). The sum of the four cells would give the test statistic.
04

Degree of Freedom and p-value

The degrees of freedom for the Chi-square test is calculated by \((number \ of \ rows - 1) * (number \ of \ columns - 1)\), which in this case is \((2 - 1) * (2 - 1) = 1\). The p-value can be found using the Chi-square distribution with df=1 and the test statistic calculated in the previous step. If the p-value is less than 0.05, reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypothesis Testing
When examining potential relationships in data, hypothesis testing is a fundamental statistical approach used to determine the existence of a significant effect. It involves posing a null hypothesis which suggests that no effect or no difference exists. In the case of gender and diet app usage, the null hypothesis might be that there is no association between gender and the use of diet apps.

Then, an alternative hypothesis is proposed, which posits that there is an effect or difference—here it would be that gender does affect diet app usage. Using statistical tests, we collect evidence against the null hypothesis. If the evidence is strong enough, we reject the null hypothesis in favor of the alternative hypothesis, suggesting a potential association between the variables.
Expected Counts Calculation
Expected counts are fundamental to performing a chi-square test. They represent the frequencies we would expect to see in each category if the null hypothesis were true, meaning if there were no association between the variables. To calculate these in a contingency table, we use the formula \(\frac{row \ total \times column \ total}{grand \ total}\).

This formula considers the proportion of the totals across both dimensions (rows and columns) of the table and applies it to the grand total, thereby estimating what the count would be under the assumption of independence between variables. Expected counts must be calculated for each cell in the contingency table to proceed with the chi-square test.
Statistical Significance
Statistical significance is the probability of our observed data, or something more extreme, if the null hypothesis were true. It is typically measured by a p-value, which tells us whether the observed differences or associations could be due to random chance. In most research, including the study on gender and diet app usage, a p-value of less than 0.05 is considered significant.

This threshold, known as the significance level, is chosen to balance the risk of making a type I error (falsely rejecting the true null hypothesis) against being too conservative and missing a real effect. The p-value obtained from the chi-square test will ultimately guide us in deciding whether the association observed is statistically significant or could likely have occurred by chance.
Gender and Diet App Usage Association
Considering the example of gender's association with diet app usage, researchers conducted the chi-square test to explore whether a statistical relationship exists between these two variables. By looking at the usage patterns among males and females, scientists can infer whether gender might influence the likelihood of using diet apps. A significant result would suggest behavioral differences between genders in the context of diet monitoring, which could have implications for app development, marketing strategies, and public health interventions focusing on dietary tracking.

If we find the chi-square test indicates a significant association, it implies that one gender might be more inclined to use diet apps than the other. However, it's important to remember that statistical tests reveal associations, not causations; further research would be needed to understand the underlying reasons for such a difference in app usage.

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In the study referenced in exercise \(10.8\), researchers also asked whether or not students bought fast food at least one to two times per week. The data are reported by gender in the table. $$\begin{array}{lcc}\text { Buy fast food at least 1-2 times weekly } & \text { Females } & \text { Males } \\\\\hline \text { Yes } & 138 & 85 \\ \text { No } & 160 & 58\end{array}$$ a. Find the row, column, and grand totals, and prepare a table showing these values as well as the counts given. b. Find the percentage of students overall who buy fast food at least 1 or 2 times weekly. Round off to one decimal place. c. Find the expected number who buy fast food at least 1 or 2 times weekly for each gender. Round to two decimal places as needed. d. Find the expected number who did not buy fast food at least 1 or 2 times weekly for each gender. Round to two decimal places as needed. e. Calculate the observed value of the chi-square statistic.

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