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Texting While Driving The mother of a teenager has heard a claim that \(25 \%\) of teenagers who drive and use a cell phone reported texting while driving. She thinks that this rate is too high and wants to test the hypothesis that fewer than \(25 \%\) of these drivers have texted while driving. Her alternative hypothesis is that the percentage of teenagers who have texted when driving is less than \(25 \%\) $$ \begin{aligned} &\mathrm{H}_{0}=p=0.25 \\ &\mathrm{H}_{\mathrm{a}}=p<0.25 \end{aligned} $$ She polls 40 randomly selected teenagers, and 5 of them report having texted while driving, a proportion of \(0.125 .\) The p-value is \(0.034\). Explain the meaning of the p-value in the context of this question.

Short Answer

Expert verified
The p-value of 0.034 suggests there is a 3.4% chance of observing a sample proportion as extreme, or more extreme, than the one observed (0.125), assuming that the true population proportion of teenagers who text while driving is 25%. Since the p-value is less than 0.05, there is enough evidence to reject the null hypothesis and support the mother's claim that less than 25% of teenagers have texted while driving.

Step by step solution

01

Understanding Hypothesis Testing

In hypothesis testing, the null hypothesis (\(H_0\)) is the claim that is initially presumed to be true. Here \(H_0: p = 0.25\), which means it is assumed that 25% of teenagers text while driving. The alternative hypothesis (\(H_a\)) is the statement that contradicts the null hypothesis. In this case, \(H_a: p < 0.25\), meaning it is proposed that less than 25% of teenagers text while driving.
02

Understanding the Sample Proportion

The sample proportion is calculated by finding the ratio of the number of successes (texted while driving) to the sample size. Here, the sample size is 40 and 5 out of 40 teenagers reported having texted while driving, so the sample proportion \( \hat{p} \) is \( \frac{5}{40} = 0.125 \).
03

Understanding the P-Value

The p-value is a probability that provides a measure of the evidence against the null hypothesis provided by the data. A small p-value (typically ≤ 0.05) indicates strong evidence against the null hypothesis, so you reject the null hypothesis. Here, the p-value is 0.034, which is less than the commonly used significance level of 0.05.
04

Conclusion

Based on our p-value, we have enough evidence to reject the null hypothesis. This means we support the mother's claim that less than 25% of teenage drivers have texted while driving.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Null and Alternative Hypotheses
In statistics, we use hypothesis testing to determine if there is enough evidence to support a particular belief about a population. The null hypothesis (H_0) represents the status quo or a commonly accepted fact. In our exercise, the mother begins with the assumption that 25% of teenagers text while driving, written as H_0: p = 0.25. This is a statement of no effect or no change.

On the other side, we have the alternative hypothesis (H_a), which challenges the null hypothesis. The mother suspects that the true proportion of texting while driving is less than the assumed 25%, represented as H_a: p < 0.25. The alternative hypothesis is what you aim to support with evidence from your data. The burden of proof lies with the alternative hypothesis—it's about showing that the null hypothesis is unlikely to be true given what we've observed.
Understanding Sample Proportion
The sample proportion is a fraction that gives us an estimated percentage of occurrences in a population, based on sampled data. It is denoted by \( \hat{p} \) and is calculated by dividing the number of 'successes' by the total number of observations. In the mother's case, 5 out of 40 teenagers, or 12.5%, reported texting while driving—leading to a sample proportion of \( \frac{5}{40} = 0.125 \). This is a practical example of using the sample proportion to estimate a characteristic of the broader population (teenage drivers), based on the data collected from a sample.
Interpreting the P-Value
The p-value is a key concept in hypothesis testing and is used to decide whether to reject the null hypothesis. It represents the probability of obtaining an observed statistic, or something more extreme, if the null hypothesis were true. A low p-value suggests the observed data is unusual under the assumption that the null hypothesis is correct.

In our exercise, the p-value is 0.034, meaning there's a 3.4% chance of observing a sample proportion as extreme as 0.125 or lower if the true proportion is actually 0.25. Since this p-value is less than the typical alpha level of 0.05, it indicates that such an extreme result is unlikely to occur due to random chance alone, and provides evidence against the null hypothesis.
Determining Statistical Significance
Statistical significance is the likelihood that a relationship between two or more variables is caused by something other than random chance. It's assessed by looking at the p-value relative to an agreed-upon threshold called the significance level, often denoted by \( \alpha \).

If the p-value is less than or equal to \( \alpha \), we reject the null hypothesis. Since in our texting and driving study the p-value of 0.034 is less than the common threshold of 0.05, we conclude there's statistically significant evidence to support the mother's theory that fewer than 25% of teenage drivers text while driving.

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Most popular questions from this chapter

Historically, the percentage of U.S. residents who support stricter gun control laws has been \(52 \%\). A recent Gallup Poll of 1011 people showed 495 in favor of stricter gun control laws. Assume the poll was given to a random sample of people. Test the claim that the proportion of those favoring stricter gun control has changed. Perform a hypothesis test, using a significance level of \(0.05\). See page 423 for guidance. Choose one of the following conclusions: i. The percentage is not significantly different from \(52 \%\). (A significant difference is one for which the p-value is less than or equal to \(0.050 .\) ) ii. The percentage is significantly different from \(52 \%\).

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